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f(x)=sinx,a=π/2

Short Answer

Expert verified

sin(x)=1-x-π222+xx-π2424-x-π26720+

Step by step solution

01

Given information.

The Maclaurin expansion of the functionf(x)=sinx,a=π/2 is to be evaluated.

02

Definition of Maclaurin series.

The definition of the Maclaurin series is defined.

cos(x)=1-x22+x424-x6720+

03

Begin by stating the Maclaurin series.

State the Maclaurin series.

sin(x)=sinπ2+x-π2=x-x36+x3120+

Use the fact sinx+π2=cos(x)to equate the previous equation.

sinπ2+x-π2=cosx-π2

cos(x)=1-x22+x424-x6720+

04

Make appropriate substitution in the Maclaurin series and evaluate.

Replace x with the expressionx-π2in the third defined Maclaurin series.

sin(x)=cosx-π2

localid="1657384732250" sin(x)=1-x-π222+xx-π2424-x-π26720+

Thus, the final answer islocalid="1657384971196" sin(x)=1-x-π222+xx-π2424-x-π26720+

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