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The functionssint,cost,···,are called “circular functions” and the functionssinht,cosht,···, are called “hyperbolic functions”. To see a reason for this, show thatx=cost,y=sint, satisfy the equation of a circlex2+y2=1, whilex=cosht,y=sinht, satisfy the equation of a hyperbola

x2-y2=1.

Short Answer

Expert verified

It has been proved that the x=cost,y=sintsatisfies the equation of the circle andx=cost,y=sinht satisfies the equation of the hyperbola.

Step by step solution

01

Given Information.

The given equations are, x=cost,y=sint.

02

Meaning of rectangular form.

Represent the complex number in rectangular form means writing the given complex number in the form of in which is the real part and is the imaginary part.

03

Substitute the values in the equation of the circle.

Put

x=costy=sin(t)

The equation of the circle is x2+y2=1.

Substitute the values.

x2+y2=cos2(t)+sin2t=1

Therefore, it satisfies the equation of the circle.

04

Substitute the values in the equation of the hyperbola.

Put

x=coshty=sinh(t)

The equation of the circle is x2-y2=1.

Substitute the values.

x2+y2=cosh2(t)+sinh2t=1

Therefore, it satisfies the equation of the hyperbola

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