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Use Equation 6.59 to estimate the internal field in hydrogen, and characterize quantitatively a "strong" and "weak" Zeeman field.

Short Answer

Expert verified

The value of internal magnetic field is 12 T .

The strong and weak Zeeman field is characterized as:

BextBintstrong Zeeman field

BextBintweak Zeeman field

Step by step solution

01

Expression for the internal magnetic field

The expression for the internal magnetic field in the hydrogen atom is given as follows,

B=14πε0.emc2r3L

Here,ε0is the permittivity of the free space with value role="math" localid="1658138846877" 8.9×10-10C2/N.m2,e is the charge on electron with value 1.6×10-19C,m, is the mass of the electron with value 9.1×10-31kg,c is the speed of light with value 3×108m/s,ris the Bohr’s radius with value 0.53×10-10m, and L=ħwhich is Planck’s constant with value 1.05×10-34J.s.

02

Determination of the internal magnetic field of the hydrogen atom

Assume r=a that is Bohr’s radius, and L=ħ.

Substitute the values in the expression for the internal magnetic field in the hydrogen atom.

B=14πε0.emec2a3ħ=14π8.9×10-10C2/N.m2×1N.m1J.1.6×10-19C1.05×10-34J.s9.1×10-31kg3×108m/s20.53×10-10m=12C.m/s×1T1C.m/s=12T

03

Quantitative characterization of strong and weak Zeeman field

It is known that the strong Zeeman field is Bext>>10Tand the weak Zeeman field is Bext10T. So,BextBintandBextBint .

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Most popular questions from this chapter

(a) Plugs=0,s=2, and s=3into Kramers' relation (Equation 6.104) to obtain formulas for (r-1),(r),(r-2),and(r3). Note that you could continue indefinitely, to find any positive power.

(b) In the other direction, however, you hit a snag. Put in s=-1, and show that all you get is a relation between role="math" localid="1658216018740" (r-2)and(r-3).

(c) But if you can get (r-2)by some other means, you can apply the Kramers' relation to obtain the rest of the negative powers. Use Equation 6.56(which is derived in Problem 6.33) to determine (r-3) , and check your answer against Equation 6.64.

Consider the (eight) n=2states, |2ljmj. Find the energy of each state, under weak-field Zeeman splitting, and construct a diagram like Figure 6.11 to show how the energies evolve asBext increases. Label each line clearly, and indicate its slope.

Question: Evaluate the following commutators :

a)[L·S,L]

b)[L·S,S]

c)role="math" localid="1658226147021" [L·S,J]

d)[L·S,L2]

e)[L·S,S2]

f)[L·S,J2]

Hint: L and S satisfy the fundamental commutation relations for angular momentum (Equations 4.99 and 4.134 ), but they commute with each other.

[LX,LY]=ihLz;[Ly,Lz]=ihLx;[Lz,Lx]=ihLy.......4.99[SX,SY]=ihSz;[Sy,Sz]=ihSx;[Sz,Sx]=ihSy........4.134

Two identical spin-zero bosons are placed in an infinite square well (Equation 2.19). They interact weakly with one another, via the potential

V(x1,x2)=-aV0δ(x1-x2). (2.19).

(where V0is a constant with the dimensions of energy, and a is the width of the well).

(a)First, ignoring the interaction between the particles, find the ground state and the first excited state—both the wave functions and the associated energies.

(b) Use first-order perturbation theory to estimate the effect of the particle– particle interaction on the energies of the ground state and the first excited state.

Question: Sometimes it is possible to solve Equation 6.10 directly, without having to expand in terms of the unperturbed wave functions (Equation 6.11). Here are two particularly nice examples.

(a) Stark effect in the ground state of hydrogen.

(i) Find the first-order correction to the ground state of hydrogen in the presence of a uniform external electric fieldEext (the Stark effect-see Problem 6.36). Hint: Try a solution of the form

(A+Br+Cr2)e-r/acosθ

your problem is to find the constants , and C that solve Equation 6.10.

(ii) Use Equation to determine the second-order correction to the ground state energy (the first-order correction is zero, as you found in Problem 6.36(a)). Answer:-m(3a2eEext/2)2 .

(b) If the proton had an electric dipole moment p the potential energy of the electron in hydrogen would be perturbed in the amount

H'=-epcosθ4π̀o0r2

(i) Solve Equation 6.10 for the first-order correction to the ground state wave function.

(ii) Show that the total electric dipole moment of the atom is (surprisingly) zero, to this order.

(iii) Use Equation 6.14 to determine the second-order correction to the ground state energy. What is the first-order correction?

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