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(a) Prove that the two-dimensional rotation matrix (Eq.1.29) preserves dot products.
(That is, show thatAyBy¯+AzBz¯=AyBy+AzBz.)
(b) What constraints must the elements (Rij) of the three-dimensional rotation matrix
(Eq.1.30) satisfy, in order to preserve the length of A (for all vectorsA )?

Short Answer

Expert verified

(a) It is proved that two dimensional rotation matrix preserves dot product

(b) The constraints in order to preserve the length of A are:

2RxyRxz+RyyRyz+RzyRzz=02RxzRxx+RyzRyx+RzzRzx=02RxyRxz+RyyRyz+RzyRzz=02RxxRxy+RxyRyy+RzxRzy=0

And

Rxx2+Ryx2+Rzx2=0Rxy2+Ryy2+Rzy2=0Rxz2+Ryz2+Rzz2=0

Step by step solution

01

Explain the concept and write the 2-D matix.

Thescalars are invariant under rotations. Mass m is always the same underrotations.

Also, dot product is a scalar quantity. So, it should be invariant under rotation. Vectors transformation of rotation around xaxisisgivenby,

Ay=cosϕAy+sinϕAzAz=-sinϕAy+cosϕAz

Similarly, find ByandBz

By=cosϕBy+sinϕBzBz=-sinϕBy+cosϕBz

The dot product of two dimensional rotational vector

Hence, the two-dimensional rotation matrix preserves dot products.

02

Find the constraint on rotation matrix

Since the coordinate system is rotated around an arbitrary axis, Origin is always at the same point in both the coordinate system. So length of the vector should be invariant. Under rotation.

Forrotationaboutanarbitraryaxisinthreedimensions, thetransformationlawis,

Ax¯Ay¯Az¯=RxxRxyRxzRyxRyyRxzRzxRzyRzzAxAyAz

Compare the length of the system in the two coordinated system as follows:

Ax¯2+Ay¯2+Az¯2=Ax2+Ay2+Az2Ax¯2+Ay¯2+Az¯2=Ax2+Ay2+Az2

Let us consider

localid="1657357736690" Ax¯2=Rxx2Ax2+Rxy2Az2+2RxxRxyAxAy+2RxyRxzAyAz+2RxzRxxAzAx

Similarly, we can write

Ay¯2=Ryy2Ax2+Rxy2Ay2+Rxz2Az2+2RxxRxyAxAy+2RxyRxzAyAz+2RxzRxxAzAxAz¯2=Rzz2Az2+Rzy2Ay2+Rzx2Ax2+2RzzRzyAzAy+2RzyRzxAyAz+2RzxRzzAzAy

So,

Ax¯2+Ay¯2+Az¯2=Rxx2+Ryx2+Rzx2Ax2+Rxy2+Ryy2+Rzy2Ay2Rxz2+Ryz2+Rzz2Az2+RxxRxy+RxyRyy+RzxRzyAyAx+2RxyRxz+RyyRyz+RzyRzzAyAz+2RxyRxz+RyyRyz+RzyRzzAyAz+2RxzRxx+RyzRyx+RzzRzxAzAx

On comparing this equation with equation (1), we get

2RxyRxz+RyyRyz+RzyRzz=02RxzRxx+RyzRyx+RzzRzx=02RxyRxz+RyyRyz+RzyRzz=02RxxRxy+RxyRyy+RzxRzy=0

And also, we obtain,

Rxx2+Ryx2+Rzx2=0Rxy2+Ryy2+Rzy2=0Rxz2+Ryz2+Rzz2=0

Thus these results are the constraints of rotation matrix.

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