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Express the cylindrical unit vectors s^,ϕ^,z^ in terms of x^,y^,z^ (that is, derive Eq. 1.75). "Invert" your formulas to get x^,y^,z^in terms of s^,ϕ^,z^

Short Answer

Expert verified

It is obtained thatx=cosψs-sinψϕ,y=sinψs+cosψs,andz=z.

Step by step solution

01

Define cylindrical coordinates

In cylindrical coordinates, the point is represented as P=(s,ϕ,z) , where P=(s,ϕ,z) is distance of point P from z axis, the azimuthal angle, and coordinate of point P on z-axis respectively, as shown in following figure:

From the figure, write:

x=scosϕy=ssinϕz=z

The unit vectors in cylindrical coordinates are:

s=cosϕx+sinϕyϕ=-sinϕx+cosϕyz=z

The displacement vector is given as dl=dxx^+dyy^+dzz^.Differentiate transformation equation with respect to s .

dx=cosϕdsdy=sinϕdsdz=0Thedisplacementvectornowbecomes:dl=cosϕdsx+sinϕdsy+0z=dscosϕx+sinϕyCompareaboveequationwithdl=dss,wegets=cosϕy+sinϕy

02

Step: 2 Compute unit vector s^ .

The displacement vector is given asdlϕ=dxx^,dyy^,dzz^ . Differentiate transformation equation with respect to ϕ.

dx=ssinϕdϕdy=scosϕdϕdz=0

The displacement vector now becomes:

dl=ssinϕdϕx^+scosϕdϕy^+0z^=ds(ssinϕdϕ)x^+(scosϕdϕ)y^

Compare above equation with dl=sdϕϕ^ , we get,

s^=(-sinϕ)x^+(cosϕ)y^

03

Step: 3 Compute unit vector  x^

Ass=cosϕx+sinϕy,multiplecosφonbothsidesofs=cosϕx+sinϕyas,cosφs=cos2ϕx+sinϕcosϕyNow,multiplysinϕonbothsidesofϕ=-sinϕx+cosϕyas,sinφϕ=-sin2ϕx+sinϕcosϕy

subtractsinφϕ=-sin2ϕx+sinϕcosϕyfromcosφs=cosϕx+sinϕcosϕyas,cosφs=-sinφϕ=cos2ϕ+sin2ϕxx=cosφs-sinφϕ
04

Step: 4 Compute unit vector y^ 

Ass=cosϕx+sinϕy,multiplysinϕonbothsidesofs=cosϕx+sinϕyas,sinϕx=sinϕcosϕx+sin2ϕyNow,multiplycosϕonbothsidesofϕ=-sinϕx+cosϕyas,cosϕϕ=--sinϕcosϕx+cos2ϕyAddequationscosϕϕ=-sinϕcosϕx+cos2ϕyandsinϕx=sinϕcosϕx+sin2ϕyas,sinφx+cosφϕ=cos2ϕ+sin2ϕyy=sinφs+cosφϕTherefore,therequiredequationsarex=cosφs-sinφx;y=sinφs+cosφϕandz=z.

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