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Find the gradients of the following functions:

(a) f(x,y,z)=x4+y3+z4

(b) f(x,y,z)=x2y3z4

(c) f(x,y,z)=exsin(y)ln(z)

Short Answer

Expert verified

(a) The gradient of the function is2xx^+3y2y^+4z3z^.

(b) Thegradient of the function is2xx^+3y2y^+4z3z^ .

(c) The gradient of the function is exsinylnzx^+excosylnzy^+exsinyzz^.

Step by step solution

01

Write the given information.

The given functions are,

(a) fx,y,z=x4+y3+z4

(b) fx,y,z=x2y3z4

(c) fx,y,z=exsinylnz

02

Define gradient of the function.

The gradient of the function is defined as its slope on the curve of that function for the given particular point.

03

Solve for the gradient of part (a). 

Write the given function.

fx,y,z=x4+y3+z4

Differentiate the above function as,

fx=2xfy=3y2fz=4z3

Then, the gradient of the function is written as,

f=fxx^+fyy^+fzz^=2xx^+3y2y^+4z3z^

Therefore, the gradient of the function is2xx^+3y2y^+4z3z^ .

04

Solve for the gradient of part (b).

Write the given function.

fx,y,z=x2y3z4

Differentiate the above function as,

fx=2xy2z4fy=3x2y2z4fz=4x2y3z3

Then, the gradient of the function is written as,

f=fxx^+fyy^+fzz^=2xy2z4x^+3x2y2z4y^+4x2y3z3z^

Therefore, the gradient of the function is 2xx^+3y2y^+4z3z^.

05

Solve for the gradient of part (c).

Write the given function.

fx,y,z=exsinylnz

Differentiate the above function as,

fx=exsinylnzfy=excosylnzfz=exsinyz

Then, the gradient of the function is written as,

f=fxx^+fyy^+fzz^=exsinylnzx^+excosylnzy^+exsinyzz^

Therefore, the gradient of the function is.

exsinylnzx^+excosylnzy^+exsinyzz^

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Most popular questions from this chapter

Suppose that f is a function of two variables (y and z) only. Show that the gradient f=(f/y)y^(f/z)z^transforms as a vector under rotations, Eq 1.29. [Hint: (f/y¯)=(f/y)(f/y¯)+(f/z)(z/y¯),and the analogous formula for f/z¯. We know that localid="1654595255202" y¯=ycosϕ+zsinϕand z=-ycos+zcos;”solve” these equations for y and z (as functions of localid="1654325243865" y¯and z(as functions of yand z), and compute the needed derivatives f/y,z/y, etc]

Although the gradient, divergence, and curl theorems are the fundamental integral theorems of vector calculus, it is possible to derive a number of corollaries from them. Show that:

(a)vTdτ=sTda. [Hint:Let v = cT, where c is a constant, in the divergence theorem; use the product rules.]

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theorem.]

(c)vT2U+TUdτ=sTUda . [Hint:Let in the

divergence theorem.]

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