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How does the Rayleigh number differ from the Grashof number?

Short Answer

Expert verified
Based on the provided solution, the main differences between Rayleigh number and Grashof number are: 1. Rayleigh number accounts for the thermal diffusivity of the fluid, while Grashof number does not. 2. Rayleigh number is a product of Grashof number and Prandtl number, considering both convective heat transfer and momentum transfer properties of the fluid. 3. Though both numbers describe the importance of buoyancy-driven flow in a fluid, Rayleigh number is a more comprehensive descriptor, including heat transfer aspects, whereas Grashof number primarily focuses on the effects of buoyancy.

Step by step solution

01

Define Rayleigh Number

The Rayleigh number is a dimensionless number used in fluid mechanics and heat transfer that characterizes the importance of buoyancy-driven flow (natural convection) relative to viscous forces in a fluid. It is given by the formula Ra = (g * β * ΔT * L^3) / (α * ν), where g is the gravitational acceleration, β is the thermal expansion coefficient, ΔT is the temperature difference between the hot and cold fluids, L is the characteristic length scale (usually the height of a fluid layer), α is the thermal diffusivity, and ν is the kinematic viscosity of the fluid.
02

Define Grashof Number

The Grashof number is another dimensionless number used in fluid mechanics and heat transfer to describe the importance of buoyancy-driven flow (natural convection) relative to viscous forces in a fluid. It is given by the formula Gr = (g * β * ΔT * L^3) / (ν^2), where g is the gravitational acceleration, β is the thermal expansion coefficient, ΔT is the temperature difference between the hot and cold fluids, L is the characteristic length scale, and ν is the kinematic viscosity of the fluid.
03

Compare Rayleigh Number and Grashof Number

Comparing the formulas of Rayleigh number and Grashof number, it can be noticed that both numbers describe the importance of buoyancy-driven flow in a fluid. However, the formula for the Rayleigh number includes the thermal diffusivity (α), while the Grashof number does not. Thermal diffusivity takes into account the ability of a fluid to conduct heat, which is an important aspect in convective heat transfer.
04

Establish the Relationship between Rayleigh Number and Grashof Number

The relationship between Rayleigh number (Ra) and Grashof number (Gr) can be established by incorporating the Prandtl number (Pr), which is the ratio of momentum diffusivity to thermal diffusivity. The Prandtl number can be defined as Pr = ν/α. Rearranging this expression to get α = ν/Pr, and then substituting this in the Rayleigh number formula, we get Ra = Gr * Pr, where Gr is the Grashof number and Pr is the Prandtl number.
05

Summarize the Differences

In summary, the main differences between the Rayleigh number and the Grashof number are: 1. Rayleigh number takes into account the thermal diffusivity of the fluid, while Grashof number does not. 2. Rayleigh number is directly proportional to the product of Grashof number and Prandtl number, so it considers both convective heat transfer and momentum transfer properties of the fluid. 3. Both numbers describe the importance of buoyancy-driven flow in a fluid; however, Rayleigh number provides a more comprehensive description that includes heat transfer aspects, while Grashof number mainly focuses on the effects of buoyancy.

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Most popular questions from this chapter

The side surfaces of a 3 -m-high cubic industrial furnace burning natural gas are not insulated, and the temperature at the outer surface of this section is measured to be \(110^{\circ} \mathrm{C}\). The temperature of the furnace room, including its surfaces, is \(30^{\circ} \mathrm{C}\), and the emissivity of the outer surface of the furnace is \(0.7\). It is proposed that this section of the furnace wall be insulated with glass wool insulation $(k=0.038 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})$ wrapped by a reflective sheet \((\varepsilon=0.2)\) in order to reduce the heat loss by 90 percent. Assuming the outer surface temperature of the metal section still remains at about \(110^{\circ} \mathrm{C}\), determine the thickness of the insulation that needs to be used. The furnace operates continuously throughout the year and has an efficiency of 78 percent. The price of the natural gas is \(\$ 1.10 /\) therm ( 1 therm \(=105,500 \mathrm{~kJ}\) of energy content). If the installation of the insulation will cost \(\$ 550\) for materials and labor, determine how long it will take for the insulation to pay for itself from the energy it saves.

A \(0.5-\mathrm{m}\)-long thin vertical copper plate is subjected to a uniform heat flux of \(1000 \mathrm{~W} / \mathrm{m}^{2}\) on one side, while the other side is exposed to air at \(5^{\circ} \mathrm{C}\). Determine the plate midpoint temperature for \((a)\) a highly polished surface and \((b)\) a black oxidized surface. Hint: The plate midpoint temperature \(\left(T_{L 2}\right)\) has to be found iteratively. Begin the calculations by using a film temperature of \(30^{\circ} \mathrm{C}\).

During a visit to a plastic sheeting plant, it was observed that a 45 -m-long section of a 2 -in nominal \((6.03-\mathrm{cm}\)-outerdiameter) steam pipe extended from one end of the plant to the other with no insulation on it. The temperature measurements at several locations revealed that the average temperature of the exposed surfaces of the steam pipe was $170^{\circ} \mathrm{C}\(, while the temperature of the surrounding air was \)20^{\circ} \mathrm{C}$. The outer surface of the pipe appeared to be oxidized, and its emissivity can be taken to be 0.7. Taking the temperature of the surrounding surfaces to be \(20^{\circ} \mathrm{C}\) also, determine the rate of heat loss from the steam pipe. Steam is generated in a gas furnace that has an efficiency of 84 percent, and the plant pays \(\$ 1.10\) per therm (1 therm \(=105,500 \mathrm{~kJ}\) ) of natural gas. The plant operates \(24 \mathrm{~h}\) a day, 365 days a year, and thus \(8760 \mathrm{~h}\) a year. Determine the annual cost of the heat losses from the steam pipe for this facility.

A vertical 4-ft-high and 6-ft-wide double-pane window consists of two sheets of glass separated by a 1 -in air gap at atmospheric pressure. If the glass surface temperatures across the air gap are measured to be $65^{\circ} \mathrm{F}\( and \)40^{\circ} \mathrm{F}$, determine the rate of heat transfer through the window by \((a)\) natural convection and (b) radiation. Also, determine the \(R\)-value of insulation of this window such that multiplying the inverse of the \(R\)-value by the surface area and the temperature difference gives the total rate of heat transfer through the window. The effective emissivity for use in radiation calculations between two large parallel glass plates can be taken to be \(0.82\).

Consider a \(1.2\)-m-high and 2-m-wide doublepane window consisting of two \(3-\mathrm{mm}\)-thick layers of glass $(k=0.78 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\( separated by a \)2.5$-cm-wide airspace. Determine the steady rate of heat transfer through this window and the temperature of its inner surface for a day during which the room is maintained at \(20^{\circ} \mathrm{C}\) while the temperature of the outdoors is \(0^{\circ} \mathrm{C}\). Take the heat transfer coefficients on the inner and outer surfaces of the window to be \(h_{1}=10 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and $h_{2}=25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, and disregard any heat transfer by radiation. Evaluate air properties at a film temperature of \(10^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) pressure. Is this a good assumption?

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