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Consider three similar double-pane windows with air gap widths of 5,10 , and \(20 \mathrm{~mm}\). For which case will the heat transfer through the window be a minimum?

Short Answer

Expert verified
Answer: The heat transfer through the double-pane window is at a minimum in Case 3, where the air gap width is 20 mm.

Step by step solution

01

Understanding the relation between heat transfer and air gap width

In a double-pane window, the main mode of heat transfer through the air gap is conduction. As the air gap width increases, the overall resistance to heat transfer increases, which means that the heat transfer will decrease. Consequently, we expect the case with the largest air gap width to have a minimum heat transfer.
02

Comparing different cases

We can compare the heat transfers for each case, based on the air gap widths: - Case 1: 5 mm - Case 2: 10 mm - Case 3: 20 mm As discussed in Step 1, the heat transfer decreases as the air gap width increases. Therefore, we can say that the heat transfer in Case 3 (with the 20 mm air gap) would be less than that in Case 2 (with the 10 mm air gap), and the heat transfer in Case 2 would be less than that in Case 1 (with the 5 mm air gap).
03

Determining the case with the minimum heat transfer

As we found in Step 2, the heat transfer through the double-pane window decreases as the air gap width increases. Consequently, the case with the minimum heat transfer will be the case with the largest air gap width. In our three cases, the largest air gap width is 20 mm, which is Case 3. Therefore, the heat transfer through the double-pane window will be a minimum for Case 3.

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Most popular questions from this chapter

Consider a \(1.2\)-m-high and 2-m-wide doublepane window consisting of two \(3-\mathrm{mm}\)-thick layers of glass $(k=0.78 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\( separated by a \)2.5$-cm-wide airspace. Determine the steady rate of heat transfer through this window and the temperature of its inner surface for a day during which the room is maintained at \(20^{\circ} \mathrm{C}\) while the temperature of the outdoors is \(0^{\circ} \mathrm{C}\). Take the heat transfer coefficients on the inner and outer surfaces of the window to be \(h_{1}=10 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and $h_{2}=25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, and disregard any heat transfer by radiation. Evaluate air properties at a film temperature of \(10^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) pressure. Is this a good assumption?

The overall \(U\)-factor of a fixed wood-framed window with double glazing is given by the manufacturer to be $U=2.76 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\( under the conditions of still air inside and winds of \)12 \mathrm{~km} / \mathrm{h}\( outside. What will the \)U$-factor be when the wind velocity outside is doubled? Answer: $2.88 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$

An electric resistance space heater is designed such that it resembles a rectangular box \(50 \mathrm{~cm}\) high, \(80 \mathrm{~cm}\) long, and $15 \mathrm{~cm}\( wide filled with \)45 \mathrm{~kg}$ of oil. The heater is to be placed against a wall, and thus heat transfer from its back surface is negligible. The surface temperature of the heater is not to exceed $75^{\circ} \mathrm{C}\( in a room at \)25^{\circ} \mathrm{C}$ for safety considerations. Disregarding heat transfer from the bottom and top surfaces of the heater in anticipation that the top surface will be used as a shelf, determine the power rating of the heater in W. Take the emissivity of the outer surface of the heater to be \(0.8\) and the average temperature of the ceiling and wall surfaces to be the same as the room air temperature. Also, determine how long it will take for the heater to reach steady operation when it is first turned on (i.e., for the oil temperature to rise from \(25^{\circ} \mathrm{C}\) to \(75^{\circ} \mathrm{C}\) ). State your assumptions in the calculations.

A \(0.2-\mathrm{m}\)-long and \(25-\mathrm{mm}\)-thick vertical plate $(k=1.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})$ separates the hot water from the cold air at \(2^{\circ} \mathrm{C}\). The plate surface exposed to the hot water has a temperature of \(100^{\circ} \mathrm{C}\), and the surface exposed to the cold air has an emissivity of \(0.73\). Determine the temperature of the plate surface exposed to the cold air \(\left(T_{s, c}\right)\). Hint: The \(T_{s, c}\) has to be found iteratively. Start the iteration process with an initial guess of \(51^{\circ} \mathrm{C}\) for the \(T_{s, c^{*}}\)

A 0.2-m-long and 25-mm-thick vertical plate $(k=15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})$ separates the hot water from the cold water. The plate surface exposed to the hot water has a temperature of $100^{\circ} \mathrm{C}\(, and the temperature of the cold water is \)7^{\circ} \mathrm{C}$. Determine the temperature of the plate surface exposed to the cold water \(\left(T_{s, c}\right)\). Hint: The \(T_{s, c}\) has to be found iteratively. Start the iteration process with an initial guess of \(53.5^{\circ} \mathrm{C}\) for the \(T_{s, c}\).

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