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Under what conditions does natural convection enhance forced convection, and under what conditions does it hurt forced convection?

Short Answer

Expert verified
Answer: Natural convection enhances forced convection when their fluid motions act in the same direction, typically occurring when the temperature difference between the surface and the fluid creates a buoyancy force that complements the external force causing forced convection. Natural convection hurts forced convection when their fluid motions act in opposite directions, which happens when the temperature difference between the surface and the fluid generates a buoyancy force that opposes the external force causing forced convection.

Step by step solution

01

Introduction to Convection

Convection is the mode of heat transfer that occurs in fluids (such as liquids and gases) due to the combined effects of fluid motion and heat diffusion. Convection can either be natural or forced, depending on what causes the fluid motion.
02

Natural Convection

Natural convection occurs when fluid motion is caused by variations in density due to temperature differences within the fluid. In the presence of a gravitational field, the warmer, less dense fluid will rise, while the cooler, denser fluid will sink, resulting in a cyclic motion. The heat transfer rate in natural convection depends on the fluid properties, temperature difference, and gravity.
03

Forced Convection

Forced convection occurs when fluid motion is induced by external forces, such as fans or pumps. This type of convection is independent of temperature differences in the fluid. The heat transfer rate in forced convection depends on fluid properties, flow speed, and the surface's geometry over which fluid moves.
04

Enhancement of Forced Convection by Natural Convection

Natural convection enhances forced convection when their fluid motions act in the same direction, leading to an increased overall heat transfer rate. This typically happens when the temperature difference between the surface and the fluid creates a buoyancy force that complements the external force causing forced convection.
05

Detrimental Effect of Natural Convection on Forced Convection

Natural convection hurts forced convection when their fluid motions act in opposite directions. It leads to a decreased overall heat transfer rate as the two forces work against each other. This situation typically occurs when the temperature difference between the surface and the fluid generates a buoyancy force that opposes the external force causing forced convection.
06

Conclusion

Natural convection can either enhance or hurt forced convection, depending on the direction of the fluid motion caused by each type of convection. When both motions act in the same direction, natural convection enhances forced convection, leading to a higher overall heat transfer rate. Conversely, when the fluid motions act in opposite directions, natural convection hurts forced convection and results in a lower heat transfer rate. The conditions under which natural convection has a positive or negative impact on forced convection depend on factors like surface and fluid temperatures, fluid properties, and gravity.

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Most popular questions from this chapter

The components of an electronic system dissipating \(150 \mathrm{~W}\) are located in a 5 -ft-long horizontal duct whose cross section is 6 in \(\times 6\) in. The components in the duct are cooled by forced air, which enters at \(85^{\circ} \mathrm{F}\) at a rate of \(22 \mathrm{cfm}\) and leaves at \(100^{\circ} \mathrm{F}\). The surfaces of the sheet metal duct are not painted, and thus radiation heat transfer from the outer surfaces is negligible. If the ambient air temperature is \(80^{\circ} \mathrm{F}\), determine \((a)\) the heat transfer from the outer surfaces of the duct to the ambient air by natural convection and \((b)\) the average temperature of the duct. Evaluate air properties at a film temperature of $100^{\circ} \mathrm{F}\( and \)1 \mathrm{~atm}$ pressure. Is this a good assumption?

A 6-m-internal-diameter spherical tank made of \(1.5\)-cm-thick stainless steel \((k=15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is used to store iced water at \(0^{\circ} \mathrm{C}\) in a room at \(20^{\circ} \mathrm{C}\). The walls of the room are also at \(20^{\circ} \mathrm{C}\). The outer surface of the tank is black (emissivity \(\varepsilon=1\) ), and heat transfer between the outer surface of the tank and the surroundings is by natural convection and radiation. Assuming the entire steel tank to be at \(0^{\circ} \mathrm{C}\) and thus the thermal resistance of the tank to be negligible, determine \((a)\) the rate of heat transfer to the iced water in the tank and \((b)\) the amount of ice at \(0^{\circ} \mathrm{C}\) that melts during a 24-h period. The heat of fusion of water is \(333.7 \mathrm{~kJ} / \mathrm{kg}\). Answers: (a) $15.4 \mathrm{~kW}\(, (b) \)3988 \mathrm{~kg}$

A \(0.2-\mathrm{m}\)-long and \(25-\mathrm{mm}\)-thick vertical plate $(k=1.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})$ separates the hot water from the cold air at \(2^{\circ} \mathrm{C}\). The plate surface exposed to the hot water has a temperature of \(100^{\circ} \mathrm{C}\), and the surface exposed to the cold air has an emissivity of \(0.73\). Determine the temperature of the plate surface exposed to the cold air \(\left(T_{s, c}\right)\). Hint: The \(T_{s, c}\) has to be found iteratively. Start the iteration process with an initial guess of \(51^{\circ} \mathrm{C}\) for the \(T_{s, c^{*}}\)

A 0.1-W small cylindrical resistor mounted on a lower part of a vertical circuit board is \(0.3\) in long and has a diameter of \(0.2 \mathrm{in}\). The view of the resistor is largely blocked by another circuit board facing it, and the heat transfer through the connecting wires is negligible. The air is free to flow through the large parallel flow passages between the boards as a result of natural convection currents. If the air temperature near the resistor is \(120^{\circ} \mathrm{F}\), determine the approximate surface temperature of the resistor. Evaluate air properties at a film temperature of \(170^{\circ} \mathrm{F}\) and \(1 \mathrm{~atm}\) pressure. Is this a good assumption? Answer: \(211^{\circ} \mathrm{F}\)

A 4-m-diameter spherical tank contains iced water at \(0^{\circ} \mathrm{C}\). The tank is thin-shelled, and thus its outer surface temperature may be assumed to be same as the temperature of the iced water inside. Now the tank is placed in a large lake at \(20^{\circ} \mathrm{C}\). The rate at which the ice melts is (a) \(0.42 \mathrm{~kg} / \mathrm{s}\) (b) \(0.58 \mathrm{~kg} / \mathrm{s}\) (c) \(0.70 \mathrm{~kg} / \mathrm{s}\) (d) \(0.83 \mathrm{~kg} / \mathrm{s}\) (e) \(0.98 \mathrm{~kg} / \mathrm{s}\) (For lake water, use $k=0.580 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \operatorname{Pr}=9.45\(, \)\left.\nu=0.1307 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}, \beta=0.138 \times 10^{-3} \mathrm{~K}^{-1}\right)$

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