Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The hot water needs of a household are to be met by heating water at \(55^{\circ} \mathrm{F}\) to \(180^{\circ} \mathrm{F}\) by a parabolic solar collector at a rate of \(5 \mathrm{lbm} / \mathrm{s}\). Water flows through a \(1.25\)-in-diameter thin aluminum tube whose outer surface is anodized black in order to maximize its solar absorption ability. The centerline of the tube coincides with the focal line of the collector, and a glass sleeve is placed outside the tube to minimize the heat losses. If solar energy is transferred to water at a net rate of \(350 \mathrm{Btu} / \mathrm{h}\) per \(\mathrm{ft}\) length of the tube, determine the required length of the parabolic collector to meet the hot water requirements of this house. Also, determine the surface temperature of the tube at the exit.

Short Answer

Expert verified
The required length of the parabolic solar collector is 6,430 feet, and the surface temperature of the tube at the exit is approximately 180°F.

Step by step solution

01

Calculate the energy needed to heat the water

First, we need to find the energy required to heat the water from its initial temperature of 55°F to the desired temperature of 180°F. For this, we can use the formula: Energy = mass flow rate × specific heat × (Final temperature - Initial temperature) The specific heat of water can be approximated to \(1 \thinspace Btu / (lbm \thinspace °F)\). Energy = \((5 \thinspace lbm/s) × (1 \thinspace Btu/(lbm \thinspace °F)) × (180 °F - 55 °F)\) Energy = \((5 \thinspace lbm/s) × (1 \thinspace Btu/(lbm \thinspace °F)) × (125 °F)\) Energy = \(625 \thinspace Btu/s\)
02

Calculate the energy that the solar collector can provide

We are given that the solar collector can provide 350 Btu/h per foot of the tube. First, we need to convert the energy rate from Btu/h to Btu/s: Energy_rate = \(350 \thinspace Btu/h \times (1 \thinspace h / 3600 \thinspace s)\) Energy_rate = \(0.0972 \thinspace Btu/s \thinspace ft\)
03

Determine the required length of the collector

Now, we need to find the length of the collector required to provide the needed energy to heat the water. We can use the formula: Length = Energy / Energy_rate Length = \(625 \thinspace Btu/s / 0.0972 \thinspace Btu/s \thinspace ft\) Length = \(6430 \thinspace ft\) So, the required length of the parabolic collector to meet the hot water requirements of the house is 6,430 feet.
04

Calculate the surface temperature of the tube at the exit

To calculate the surface temperature of the tube at the exit, we need to assume that the temperature difference between the tube surface and the water inside is negligible. This assumption is valid because of the good thermal conductivity of aluminum and the negligible heat losses due to the glass sleeve. Thus, we can assume: Exit surface temperature of the tube ≈ the final temperature of the water The final temperature of the water is 180°F; therefore, the surface temperature of the tube at the exit is also approximately 180°F. In conclusion, the required length of the parabolic collector is 6,430 feet, and the surface temperature of the tube at the exit is approximately 180°F.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Hot air at \(60^{\circ} \mathrm{C}\) leaving the furnace of a house enters a \(12-\mathrm{m}\)-long section of a sheet metal duct of rectangular cross section \(20 \mathrm{~cm} \times 20 \mathrm{~cm}\) at an average velocity of $4 \mathrm{~m} / \mathrm{s}$. The thermal resistance of the duct is negligible, and the outer surface of the duct, whose emissivity is \(0.3\), is exposed to the cold air at \(10^{\circ} \mathrm{C}\) in the basement, with a convection heat transfer coefficient of \(10 \mathrm{~W} / \mathrm{m}^{2}\). . Taking the walls of the basement to be at \(10^{\circ} \mathrm{C}\) also, determine \((a)\) the temperature at which the hot air will leave the basement and \((b)\) the rate of heat loss from the hot air in the duct to the basement. Evaluate air properties at a bulk mean temperature of \(50^{\circ} \mathrm{C}\). Is this a good assumption?

Consider a 25-mm-diameter and 15-m-long smooth tube that is maintained at a constant surface temperature. Fluids enter the tube at \(50^{\circ} \mathrm{C}\) with a mass flow rate of \(0.01 \mathrm{~kg} / \mathrm{s}\). Determine the tube surface temperatures necessary to heat water, engine oil, and liquid mercury to the desired outlet temperature of \(150^{\circ} \mathrm{C}\).

Water at $10^{\circ} \mathrm{C}\left(\rho=999.7 \mathrm{~kg} / \mathrm{m}^{3}\right.\( and \)\mu=1.307 \times\( \)10^{-3} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}\( ) is flowing in a \)0.20-\mathrm{cm}$-diameter, 15 -m-long pipe steadily at an average velocity of $1.2 \mathrm{~m} / \mathrm{s}\(. Determine \)(a)\( the pressure drop and \)(b)$ the pumping power requirement to overcome this pressure drop. Assume flow is fully developed. Is this a good assumption? Answers: (a) \(188 \mathrm{kPa}\), (b) $0.71 \mathrm{~W}$

How is the friction factor for flow in a tube related to the pressure drop? How is the pressure drop related to the pumping power requirement for a given mass flow rate?

A liquid hydrocarbon enters a \(2.5\)-cm-diameter tube that is \(5.0 \mathrm{~m}\) long. The liquid inlet temperature is \(20^{\circ} \mathrm{C}\) and the tube wall temperature is \(60^{\circ} \mathrm{C}\). Average liquid properties are $c_{p}=2.0 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}, \mu=10 \mathrm{mPa} \cdot \mathrm{s}\(, and \)\rho=900 \mathrm{~kg} / \mathrm{m}^{3}$. At a flow rate of \(1200 \mathrm{~kg} / \mathrm{h}\), the liquid outlet temperature is measured to be \(30^{\circ} \mathrm{C}\). Estimate the liquid outlet temperature when the flow rate is reduced to \(400 \mathrm{~kg} / \mathrm{h}\). Hint: For heat transfer in tubes, \(\mathrm{Nu} \propto \mathrm{Re}^{1 / 3}\) in laminar flow and \(\mathrm{Nu} \propto \mathrm{Re}^{4 / 5}\) in turbulent flow.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free