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What does the logarithmic mean temperature difference represent for flow in a tube whose surface temperature is constant? Why do we use the logarithmic mean temperature instead of the arithmetic mean temperature?

Short Answer

Expert verified
Answer: The logarithmic mean temperature difference (LMTD) is significant for designing and analyzing heat exchanger performance as it accurately represents the average temperature difference between the hot and cold fluids in a tube with constant surface temperature. The LMTD differs from the arithmetic mean temperature difference (AMTD) because it accounts for the varying temperature differences along the length of the tube, resulting in more precise heat transfer calculations, while AMTD does not accurately capture these changes, leading to inaccuracies.

Step by step solution

01

Understand the logarithmic mean temperature difference (LMTD)

The logarithmic mean temperature difference represents the average temperature difference between the hot and cold fluids along the length of the tube. It's important for designing and analyzing the performance of heat exchangers, where the surface temperature is constant, because it accounts for the change in temperature along the length of the tube properly. It is used to determine the heat transfer rate, which is important for choosing the appropriate size and design of a heat exchanger.
02

Understand the difference between LMTD and AMTD

The arithmetic mean temperature difference (AMTD) is the simple average of the temperature differences between the hot and cold fluids at the inlet and outlet of the tube. While AMTD is easy to calculate, it doesn't accurately account for the changes in temperature along the length of the tube, leading to inaccuracies in heat transfer calculations.
03

Explain why LMTD is preferable over AMTD in heat exchangers

The LMTD is preferable over the AMTD when dealing with heat exchangers because it accounts for the varying temperature differences along the length of the tube. The temperature difference between the fluids decreases as the heat is transferred, and the logarithmic mean temperature difference accurately captures this change more effectively than AMTD. This results in a more accurate estimate of the heat transfer rate, allowing for better design and analysis of the heat exchanger system. To sum up, the logarithmic mean temperature difference (LMTD) represents the average temperature difference between the hot and cold fluids in a tube with constant surface temperature, and it is used for designing and analyzing heat exchanger performance. The LMTD is preferable to the arithmetic mean temperature difference (AMTD) because it accurately captures the changing temperature differences along the length of the tube, resulting in more precise heat transfer calculations.

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Most popular questions from this chapter

A tube with a square-edged inlet configuration is subjected to uniform wall heat flux of \(8 \mathrm{~kW} / \mathrm{m}^{2}\). The tube has an inside diameter of \(0.622\) in and a flow rate of \(2.16 \mathrm{gpm}\). The liquid flowing inside the tube is an ethylene glycol-distilled water mixture with a mass fraction of \(2.27\). Determine the friction coefficient at a location along the tube where the Grashof number is Gr \(=35,450\). The physical properties of the ethylene glycol-distilled water mixture at the location of interest are $\operatorname{Pr}=13.8, \nu=18.4 \times 10^{-6} \mathrm{ft}^{2} / \mathrm{s}\(, and \)\mu_{b} / \mu_{s}=1.12$. Then recalculate the fully developed friction coefficient if the volume flow rate is increased by 50 percent while the rest of the parameters remain unchanged.

A fluid $\left(\rho=1000 \mathrm{~kg} / \mathrm{m}^{3}, \mu=1.4 \times 10^{-3} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}\right.\(, \)c_{p}=4.2 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\(, and \)k=0.58 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\( ) flows with an average velocity of \)0.3 \mathrm{~m} / \mathrm{s}$ through a \(14-\mathrm{m}\)-long tube with inside diameter of $0.01 \mathrm{~m}\(. Heat is uniformly added to the entire tube at the rate of \)1500 \mathrm{~W} / \mathrm{m}^{2}\(. Determine \)(a)$ the value of convection heat transfer coefficient at the exit, \((b)\) the value of \(T_{s}-T_{\text {m }}\), and (c) the value of \(T_{e}-T_{i}\).

consider fully developed flow in a circular pipe with negligible entrance effects. If the length of the pipe is doubled, the pressure drop will \((a)\) double, \((b)\) more than double, (c) less than double, \((d)\) reduce by half, or \((e)\) remain constant.

Liquid water flows in a circular tube at a mass flow rate of $7 \mathrm{~g} / \mathrm{s}\(. The water enters the tube at \)5^{\circ} \mathrm{C}$, and the average convection heat transfer coefficient for the internal flow is $20 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. The tube is \)3 \mathrm{~m}$ long and has an inner diameter of \(25 \mathrm{~mm}\). The tube surface is maintained at a constant temperature. The inner surface of the tube is lined with polyvinylidene chloride (PVDC) lining. According to the ASME Code for Process Piping (ASME B31.3-2014, Table A.323.4.3), the recommended maximum temperature for PVDC lining is \(79^{\circ} \mathrm{C}\). If the water exits the tube at \(15^{\circ} \mathrm{C}\), determine the heat rate transferred to the water. Would the inner surface temperature of the tube exceed the recommended maximum temperature for PVDC lining?

Consider the velocity and temperature profiles for a fluid flow in a tube with a diameter of \(50 \mathrm{~mm}\) that can be expressed as $$ \begin{aligned} &u(r)=0.05\left[1-(r / R)^{2}\right] \\ &T(r)=400+80(r / R)^{2}-30(r / R)^{3} \end{aligned} $$ with units in \(\mathrm{m} / \mathrm{s}\) and \(\mathrm{K}\), respectively. Determine the average velocity and the mean (average) temperature from the given velocity and temperature profiles.

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