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Water enters a 5-mm-diameter and 13-m-long tube at \(45^{\circ} \mathrm{C}\) with a velocity of \(0.3 \mathrm{~m} / \mathrm{s}\). The tube is maintained at a constant temperature of \(8^{\circ} \mathrm{C}\). The exit temperature of the water is (a) \(4.4^{\circ} \mathrm{C}\) (b) \(8.9^{\circ} \mathrm{C}\) (c) \(10.6^{\circ} \mathrm{C}\) (d) \(12.0^{\circ} \mathrm{C}\) (e) \(14.1^{\circ} \mathrm{C}\) (For water, use $k=0.607 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \operatorname{Pr}=6.14, \nu=0.894 \times\( \)10^{-6} \mathrm{~m}^{2} / \mathrm{s}, c_{p}=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \rho=997 \mathrm{~kg} / \mathrm{m}^{3}$.)

Short Answer

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#tag_title#Step 2: Determine the flow type#tag_content#Based on the calculated Reynolds number, we can determine the type of flow in the tube. Generally, if Re < 2000, the flow is considered laminar, and if Re > 4000, the flow is considered turbulent. For intermediate values of Re (2000 < Re < 4000), the flow is considered transitional but is typically treated as turbulent for practical purposes. #tag_title#Step 3: Calculate the Nusselt number#tag_content#The Nusselt number is a dimensionless quantity that represents the ratio of convective heat transfer to conductive heat transfer. Depending on the type of flow (laminar or turbulent), we will use different correlations to calculate the Nusselt number. The most common correlations are the Sieder-Tate equation for turbulent flow and the Graetz-Nusselt equation for laminar flow. #tag_title#Step 4: Calculate the heat transfer coefficient#tag_content#The heat transfer coefficient (h) can be calculated using the Nusselt number, thermal conductivity of water (k), and tube diameter (d) with the following formula: h = \(\frac{Nu \cdot k}{d}\) #tag_title#Step 5: Calculate the heat transfer rate#tag_content#Using the heat transfer coefficient, we can calculate the heat transfer rate (Q) using the following formula: Q = \(\)hA\(\Delta T\) where A is the surface area of the tube and \(\Delta T\) is the temperature difference between the tube wall and the water. The surface area of the tube can be calculated as A = \(2 \pi rL\), where r is the radius of the tube and L is the length of the tube. #tag_title#Step 6: Calculate the exit temperature of water#tag_content#Finally, we can calculate the exit temperature of the water using the heat transfer rate, mass flow rate of water (m), and specific heat capacity of water (Cp) using the following formula: \(\Delta T = \frac{Q}{m \cdot Cp}\) The exit temperature of the water can be calculated by adding the temperature change to the initial temperature.

Step by step solution

01

Calculate the Reynolds number

The Reynolds number is a dimensionless quantity that determines the type of flow in the tube, i.e., laminar or turbulent. We can calculate the Reynolds number using the formula: Re = \(\frac{\rho vd}{\nu}\) where \(\rho = 997 \ \mathrm{kg/m^3}\) is the density of water, \(v = 0.3 \ \mathrm{m/s}\) is the velocity, \(d = 0.005 \ \mathrm{m}\) is the diameter of the tube, and \(\nu = 0.894 \times 10^{-6} \ \mathrm{m^2/s}\) is the kinematic viscosity of water.

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Most popular questions from this chapter

Consider a 10-m-long smooth rectangular tube, with \(a=50 \mathrm{~mm}\) and \(b=25 \mathrm{~mm}\), that is maintained at a constant surface temperature. Liquid water enters the tube at \(20^{\circ} \mathrm{C}\) with a mass flow rate of \(0.01 \mathrm{~kg} / \mathrm{s}\). Determine the tube surface temperature necessary to heat the water to the desired outlet temperature of $80^{\circ} \mathrm{C}$.

Air flows in an isothermal tube under fully developed conditions. The inlet temperature is \(60^{\circ} \mathrm{F}\) and the tube surface temperature is \(120^{\circ} \mathrm{F}\). The tube is \(10 \mathrm{ft}\) long, and the inner diameter is 2 in. The air mass flow rate is \(18.2 \mathrm{lbm} / \mathrm{h}\). Calculate the exit temperature of the air and the total rate of heat transfer from the tube wall to the air. Evaluate the air properties at a temperature \(80^{\circ} \mathrm{F}\). Is this a good assumption?

Consider the velocity and temperature profiles for airflow in a tube with a diameter of \(8 \mathrm{~cm}\) that can be expressed as $$ \begin{aligned} &u(r)=0.2\left[\left(1-(r / R)^{2}\right)\right] \\ &T(r)=250+200(r / R)^{3} \end{aligned} $$ with units in \(\mathrm{m} / \mathrm{s}\) and \(\mathrm{K}\), respectively. If the convection heat transfer coefficient is \(100 \mathrm{~W} / \mathrm{m}^{2}\). \(\mathrm{K}\), determine the mass flow rate and surface heat flux using the given velocity and temperature profiles. Evaluate the air properties at \(20^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\).

Water at \(15^{\circ} \mathrm{C}\) is flowing through a 200 -m-long standard 1-in Schedule 40 cast iron pipe with a mass flow rate of $0.5 \mathrm{~kg} / \mathrm{s}$. If accuracy is an important issue, use the appropriate equation to determine \((a)\) the pressure loss and \((b)\) the pumping power required to overcome the pressure loss. Assume flow is fully developed. Is this a good assumption?

Consider a 25-mm-diameter and 15-m-long smooth tube that is maintained at a constant surface temperature. Fluids enter the tube at \(50^{\circ} \mathrm{C}\) with a mass flow rate of \(0.01 \mathrm{~kg} / \mathrm{s}\). Determine the tube surface temperatures necessary to heat water, engine oil, and liquid mercury to the desired outlet temperature of \(150^{\circ} \mathrm{C}\).

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