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Consider the flow of mercury (a liquid metal) in a tube. How will the hydrodynamic and thermal entry lengths compare if the flow is laminar? How would they compare if the flow were turbulent?

Short Answer

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Question: Compare the hydrodynamic and thermal entry lengths for the flow of mercury in a tube under laminar and turbulent flow conditions. Answer: In both laminar and turbulent flows of mercury, the hydrodynamic entry length is longer than the thermal entry length. This is due to the small Prandtl number of mercury, which results in shorter thermal entry lengths.

Step by step solution

01

Understand Hydrodynamic and Thermal Entry Lengths

The hydrodynamic entry length is the distance from the tube inlet where the fluid velocity profile becomes fully developed. In other words, it's the distance it takes for the fluid velocity profile to stabilize after entering the tube. The thermal entry length is the distance from the inlet where the temperature profile of the fluid becomes fully developed. Similar to the hydrodynamic entry length, it's the distance it takes for the fluid temperature profile to stabilize after entering the tube.
02

Hydrodynamic Entry Length in Laminar and Turbulent Flows

The hydrodynamic entry length can be estimated using the following relation: L_h = 0.05 * Re * D, where L_h is the hydrodynamic entry length, Re is the Reynolds number, and D is the tube diameter. In laminar flow (Re < 2100), the entry length is relatively short, while for turbulent flow (Re > 4000), the entry length becomes much larger.
03

Thermal Entry Length in Laminar and Turbulent Flows

The thermal entry length can be estimated using the following relation: L_t = 0.05 * Re * Pr * D, where L_t is the thermal entry length, Re is the Reynolds number, Pr is the Prandtl number (dimensionless number relating the relative importance of momentum and thermal diffusion in a fluid), and D is the tube diameter. In laminar flow, the Prandtl number for mercury is around 0.02, indicating that the thermal entry length is considerably shorter than the hydrodynamic entry length. In turbulent flow, the Prandtl number for mercury remains small, meaning that the thermal entry length is still shorter than the hydrodynamic entry length.
04

Comparing Entry Lengths in Laminar and Turbulent Flows

Based on the equations for hydrodynamic and thermal entry lengths and properties of mercury, we can conclude the following: - In laminar flow, the hydrodynamic entry length will be longer than the thermal entry length, because the Prandtl number of mercury is small (0.02), making the thermal entry length shorter. - In turbulent flow, the hydrodynamic entry length will still be longer than the thermal entry length, as the Prandtl number for mercury remains small. So, in both laminar and turbulent flows of mercury, the hydrodynamic entry length is longer than the thermal entry length.

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Most popular questions from this chapter

Liquid water flows in a circular tube at a mass flow rate of $7 \mathrm{~g} / \mathrm{s}\(. The water enters the tube at \)5^{\circ} \mathrm{C}$, and the average convection heat transfer coefficient for the internal flow is $20 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. The tube is \)3 \mathrm{~m}$ long and has an inner diameter of \(25 \mathrm{~mm}\). The tube surface is maintained at a constant temperature. The inner surface of the tube is lined with polyvinylidene chloride (PVDC) lining. According to the ASME Code for Process Piping (ASME B31.3-2014, Table A.323.4.3), the recommended maximum temperature for PVDC lining is \(79^{\circ} \mathrm{C}\). If the water exits the tube at \(15^{\circ} \mathrm{C}\), determine the heat rate transferred to the water. Would the inner surface temperature of the tube exceed the recommended maximum temperature for PVDC lining?

Water $\left(\mu=9.0 \times 10^{-4} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}, \rho=1000 \mathrm{~kg} / \mathrm{m}^{3}\right)$ enters a \(4-\mathrm{cm}\)-diameter and 3 -m-long tube whose walls are maintained at \(100^{\circ} \mathrm{C}\). The water enters this tube with a bulk temperature of \(25^{\circ} \mathrm{C}\) and a volume flow rate of $3 \mathrm{~m}^{3} / \mathrm{h}$. The Reynolds number for this internal flow is (a) 29,500 (b) 38,200 (c) 72,500 (d) 118,100 (e) 122,9000

Consider the velocity and temperature profiles for a fluid flow in a tube with a diameter of \(50 \mathrm{~mm}\) that can be expressed as $$ \begin{aligned} &u(r)=0.05\left[1-(r / R)^{2}\right] \\ &T(r)=400+80(r / R)^{2}-30(r / R)^{3} \end{aligned} $$ with units in \(\mathrm{m} / \mathrm{s}\) and \(\mathrm{K}\), respectively. Determine the average velocity and the mean (average) temperature from the given velocity and temperature profiles.

A house built on a riverside is to be cooled in summer by utilizing the cool water of the river, which flows at an average temperature of $15^{\circ} \mathrm{C}\(. A 15 -m-long section of a circular duct of \)20 \mathrm{~cm}$ diameter passes through the water. Air enters the underwater section of the duct at \(25^{\circ} \mathrm{C}\) at a velocity of \(3 \mathrm{~m} / \mathrm{s}\). Assuming the surface of the duct to be at the temperature of the water, determine the outlet temperature of air as it leaves the underwater portion of the duct. Also, for an overall fan efficiency of 55 percent, determine the fan power input needed to overcome the flow resistance in this section of the duct.

Water is flowing in fully developed conditions through a \(3-\mathrm{cm}\)-diameter smooth tube with a mass flow rate of $0.02 \mathrm{~kg} / \mathrm{s}\( at \)15^{\circ} \mathrm{C}\(. Determine \)(a)$ the maximum velocity of the flow in the tube and \((b)\) the pressure gradient for the flow.

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