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Hot carbon dioxide exhaust gas at \(1 \mathrm{~atm}\) is being cooled by flat plates. The gas at \(220^{\circ} \mathrm{C}\) flows in parallel over the upper and lower surfaces of a \(1.5\)-m-long flat plate at a velocity of $3 \mathrm{~m} / \mathrm{s}$. If the flat plate surface temperature is maintained at \(80^{\circ} \mathrm{C}\), determine \((a)\) the local convection heat transfer coefficient at \(1 \mathrm{~m}\) from the leading edge, \((b)\) the average convection heat transfer coefficient over the entire plate, and (c) the total heat flux transfer to the plate.

Short Answer

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Question: A flat plate with a length of 1.5 meters and a width of 1 meter is maintained at a surface temperature of 80°C and is exposed to a flow of carbon dioxide at 220°C and 2.5 m/s. Calculate (a) the local convection heat transfer coefficient at 1 meter from the leading edge, (b) the average convection heat transfer coefficient over the entire plate length, and (c) the total heat flux transfer to the plate.

Step by step solution

01

Determine the film temperature

Calculate the film temperature, \(T_f\), as the average of the surface temperature (\(T_s\)) and the gas temperature (\(T_g\)): $$T_f = \frac{T_s + T_g}{2}$$ where \(T_s = 80^{\circ}\mathrm{C}\) and \(T_g = 220^{\circ}\mathrm{C}\). Convert both temperatures to Kelvin by adding 273.15.
02

Find the Reynolds number

To find the Reynolds number, \(Re\), we will use the following formula: $$Re = \frac{\rho u L}{\mu}$$ Where \(\rho\) is the density of the gas, \(u\) is the velocity, \(L\) is the plate length, and \(\mu\) is the dynamic viscosity. Calculate the Reynolds number at \(1 \mathrm{~m}\) and \(1.5 \mathrm{~m}\). You can find the properties of carbon dioxide at the film temperature in a gas property table, including density and dynamic viscosity.
03

Determine local and average Nusselt numbers

Now that we have the Reynolds numbers, we need to find the local and average Nusselt numbers, which are dimensionless numbers used to calculate the convection heat transfer coefficient. For flow over a flat plate, we will use the following correlation to find the local Nusselt number (\(Nu_x\)) at \(1 \mathrm{~m}\): $$Nu_x = 0.664 Re_x^{1/2} Pr^{1/3}$$ To find the average Nusselt number (\(Nu_L\)) over the entire plate, we will use the following correlation: $$Nu_L = 0.664 Re_L^{1/2} Pr^{1/3}$$ Please note that \(Re_x\) and \(Re_L\) represent the Reynolds numbers calculated in Step 2 at \(1 \mathrm{~m}\) and \(1.5 \mathrm{~m}\), respectively. In both formulas, \(Pr\) is the Prandtl number, which can be found using gas property tables at the film temperature.
04

Calculate local and average convection heat transfer coefficients

Now we can calculate the local convection heat transfer coefficient, \(h_x\), at \(1 \mathrm{~m}\) and the average convection heat transfer coefficient, \(h_L\), over the entire plate using the following equations: $$h_x = \frac{Nu_x \cdot k}{x}$$ $$h_L = \frac{Nu_L \cdot k}{L}$$ Where \(k\) is the thermal conductivity of the gas, which can be found using gas property tables at the film temperature.
05

Determine the total heat flux transfer to the plate

Lastly, we can find the total heat transfer rate, \(q'\), using the following equation: $$q' = h_L A \Delta T$$ Where \(A\) is the surface area of the plate, and \(\Delta T = T_g - T_s\). In this problem, \(A\) can be calculated as the product of the plate's length and width. The plate width is not provided in the exercise, but let's assume it is \(1 \mathrm{~m}\) for simplicity. Now find the total heat flux transfer to the plate following the steps above.

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Most popular questions from this chapter

Air \(\left(1 \mathrm{~atm}, 5^{\circ} \mathrm{C}\right)\) with a free-stream velocity of \(2 \mathrm{~m} / \mathrm{s}\) flows in parallel with a stationary thin \(1-\mathrm{m} \times 1-\mathrm{m}\) flat plate over the top and bottom surfaces. The flat plate has a uniform surface temperature of $35^{\circ} \mathrm{C}\(. Determine \)(a)\( the average friction coefficient, \)(b)$ the average convection heat transfer coefficient, and (c) the average convection heat transfer coefficient using the modified Reynolds analogy, and compare with the result obtained in \((b)\).

A transformer that is \(10-\mathrm{cm}\) long, \(6.2 \mathrm{-cm}\) wide, and \(5-\mathrm{cm}\) high is to be cooled by attaching a $10-\mathrm{cm} \times 6.2-\mathrm{cm}\(-wide polished aluminum heat sink (emissivity \)=0.03$ ) to its top surface. The heat sink has seven fins, which are \(5-\mathrm{mm}\) high, 2 -mm thick, and 10 -cm long. A fan blows air at \(25^{\circ} \mathrm{C}\) parallel to the passages between the fins. The heat sink is to dissipate $12 \mathrm{~W}$ of heat, and the base temperature of the heat sink is not to exceed \(60^{\circ} \mathrm{C}\). Assuming the fins and the base plate to be nearly isothermal and the radiation heat transfer to be negligible, determine the minimum free-stream velocity the fan needs to supply to avoid overheating. Assume the flow is laminar over the entire finned surface of the transformer.

In a piece of cryogenic equipment, two metal plates are connected by a long ASTM A437 B4B stainless steel bolt. Cold gas, at \(-70^{\circ} \mathrm{C}\), flows between the plates and across the cylindrical bolt. The gas has a thermal conductivity of \(0.02 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), a kinematic viscosity of \(9.3 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\), and a Prandtl number of \(0.74\). The diameter of the bolt is \(9.5 \mathrm{~mm}\), and the length of the bolt exposed to the gas is \(10 \mathrm{~cm}\). The minimum temperature suitable for the ASTM A437 B4B stainless steel bolt is \(-30^{\circ} \mathrm{C}\) (ASME Code for Process Piping, ASME B31.3-2014, Table A-2M). The temperature of the bolt is maintained by a heating mechanism capable of providing heat at \(15 \mathrm{~W}\). Determine the maximum velocity that the gas can achieve without cooling the bolt below the minimum suitable temperature of \(-30^{\circ} \mathrm{C}\).

A heated long cylindrical rod is placed in a crossflow of air at $20^{\circ} \mathrm{C}(1 \mathrm{~atm})\( with velocity of \)10 \mathrm{~m} / \mathrm{s}$. The rod has a diameter of \(5 \mathrm{~mm}\), and its surface has an emissivity of \(0.95\). If the surrounding temperature is \(20^{\circ} \mathrm{C}\) and the heat flux dissipated from the rod is \(16,000 \mathrm{~W} / \mathrm{m}^{2}\), determine the surface temperature of the rod. Evaluate the air properties at \(70^{\circ} \mathrm{C}\).

Jakob (1949) suggests the following correlation be used for square tubes in a liquid crossflow situation: $$ \mathrm{Nu}=0.102 \mathrm{Re}^{0.625} \mathrm{Pr}^{1 / 3} $$ Water \((k=0.61 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \mathrm{Pr}=6)\) flows across a \(1-\mathrm{cm}-\) square tube with a Reynolds number of 10,000 . The convection heat transfer coefficient is (a) \(5.7 \mathrm{~kW} / \mathrm{m}^{2} \cdot \mathrm{K}\) (b) \(8.3 \mathrm{~kW} / \mathrm{m}^{2} \cdot \mathrm{K}\) (c) \(11.2 \mathrm{~kW} / \mathrm{m}^{2} \cdot \mathrm{K}\) (d) \(15.6 \mathrm{~kW} / \mathrm{m}^{2} \cdot \mathrm{K}\) (e) \(18.1 \mathrm{~kW} / \mathrm{m}^{2} \cdot \mathrm{K}\)

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