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Air at \(15^{\circ} \mathrm{C}\) flows over a flat plate subjected to a uniform heat flux of \(240 \mathrm{~W} / \mathrm{m}^{2}\) with a velocity of $3.5 \mathrm{~m} / \mathrm{s}\(. The surface temperature of the plate \)6 \mathrm{~m}$ from the leading edge is (a) \(40.5^{\circ} \mathrm{C}\) (b) \(41.5^{\circ} \mathrm{C}\) (c) \(58.2^{\circ} \mathrm{C}\) (d) \(95.4^{\circ} \mathrm{C}\) (e) \(134^{\circ} \mathrm{C}\) (For air, use $k=0.02551 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \operatorname{Pr}=0.7296, \nu=1.562 \times\( \)10^{-5} \mathrm{~m}^{2} / \mathrm{s}$ )

Short Answer

Expert verified
Question: The surface temperature of the flat plate at \(6 \mathrm{~m}\) from the leading edge is closest to: a) 21°C b) 24°C c) 27°C d) 30°C e) 33°C

Step by step solution

01

Calculate Reynolds number at x = 6m

To find the Reynolds number at the specific point on the plate where we need to find the surface temperature, we use the formula, $$Re_x = \frac{u \cdot x}{ν}$$ where \(u = 3.5 \mathrm{~m} / \mathrm{s}\) (velocity of air), \(x = 6 \mathrm{~m}\) (distance along the plate), \(ν = 1.562 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}\) (kinematic viscosity of air).
02

Check if the flow is laminar or turbulent

A critical Reynolds number of approximately \(5 \times 10^5\) is used to differentiate between laminar and turbulent boundary layers. If \(Re_x < 5 \times 10^5\), the flow is laminar; otherwise, it's turbulent.
03

Calculate Nusselt number

If the flow is laminar, then the Nusselt number for a flat plate subjected to constant heat flux can be calculated using the formula: $$Nu_x=\sqrt{0.037 Re_x Pr^{1/3}-0.037·1000}$$ If turbulent, the Nusselt number can be calculated using an appropriate correlation.
04

Find the convection heat transfer coefficient (h)

To find the heat transfer coefficient (h), we use the formula, $$h = \frac{Nu_x * k}{x}$$ where \(Nu_x\) is the Nusselt number, \(k = 0.02551 \mathrm{W} / \mathrm{m} \cdot \mathrm{K}\) is the thermal conductivity of air.
05

Calculate the temperature difference ΔT

The temperature difference between the plate and the air along the length of the plate can be found using the formula $$ΔT = \frac{q_s}{h}$$ where \(q_s = 240 \mathrm{~W} / \mathrm{m}^{2}\) is the heat flux over the flat plate.
06

Find the surface temperature of the plate (T_plate)

Finally, the surface temperature of the plate at \(6 \mathrm{~m}\) from the leading edge can be calculated using the formula $$T_{plate} = T_{air} + ΔT$$ where \(T_{air} = 15^{\circ} \mathrm{C}\) is the temperature of the air. Compare the calculated surface temperature with the options given (a, b, c, d, e) to find the correct answer.

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Most popular questions from this chapter

Hydrogen gas at \(1 \mathrm{~atm}\) is flowing in parallel over the upper and lower surfaces of a 3 -m-long flat plate at a velocity of $2.5 \mathrm{~m} / \mathrm{s}\(. The gas temperature is \)120^{\circ} \mathrm{C}$, and the surface temperature of the plate is maintained at \(30^{\circ} \mathrm{C}\). Using appropriate software, investigate the local convection heat transfer coefficient and the local total convection heat flux along the plate. By varying the location along the plate for \(0.2 \leq x \leq 3 \mathrm{~m}\), plot the local convection heat transfer coefficient and the local total convection heat flux as functions of \(x\). Assume flow is laminar, but make sure to verify this assumption.

The local atmospheric pressure in Denver, Colorado (elevation $1610 \mathrm{~m}\( ), is \)83.4 \mathrm{kPa}\(. Air at this pressure and \)20^{\circ} \mathrm{C}\( flows with a velocity of \)8 \mathrm{~m} / \mathrm{s}$ over a \(1.5-\mathrm{m} \times 6-\mathrm{m}\) flat plate whose temperature is \(140^{\circ} \mathrm{C}\). Determine the rate of heat transfer from the plate if the air flows parallel to \((a)\) the 6 -m-long side and \((b)\) the \(1.5-\mathrm{m}\) side.

What does the friction coefficient represent in flow over a flat plate? How is it related to the drag force acting on the plate?

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