Chapter 7: Problem 10
What is flow separation? What causes it? What is the effect of flow separation on the drag coefficient?
Chapter 7: Problem 10
What is flow separation? What causes it? What is the effect of flow separation on the drag coefficient?
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Get started for freeWater vapor at \(250^{\circ} \mathrm{C}\) is flowing with a velocity of $5 \mathrm{~m} / \mathrm{s}\( in parallel over a \)2-\mathrm{m}$-long flat plate where there is an unheated starting length of \(0.5 \mathrm{~m}\). The heated section of the flat plate is maintained at a constant temperature of \(50^{\circ} \mathrm{C}\). Determine \((a)\) the local convection heat transfer coefficient at the trailing edge, \((b)\) the average convection heat transfer coefficient for the heated section, and \((c)\) the rate of heat transfer per unit width for the heated section.
What does the friction coefficient represent in flow over a flat plate? How is it related to the drag force acting on the plate?
Solar radiation is incident on the glass cover of a solar collector at a rate of \(700 \mathrm{~W} / \mathrm{m}^{2}\). The glass transmits 88 percent of the incident radiation and has an emissivity of \(0.90\). The entire hot water needs of a family in summer can be met by two collectors \(1.2-\mathrm{m}\) high and \(1-\mathrm{m}\) wide. The two collectors are attached to each other on one side so that they appear like a single collector $1.2-\mathrm{m} \times 2-\mathrm{m}$ in size. The temperature of the glass cover is measured to be \(35^{\circ} \mathrm{C}\) on a day when the surrounding air temperature is \(25^{\circ} \mathrm{C}\) and the wind is blowing at $30 \mathrm{~km} / \mathrm{h}$. The effective sky temperature for radiation exchange between the glass cover and the open sky is \(-40^{\circ} \mathrm{C}\). Water enters the tubes attached to the absorber plate at a rate of $1 \mathrm{~kg} / \mathrm{min}$. Assuming the back surface of the absorber plate to be heavily insulated and the only heat loss to occur through the glass cover, determine \((a)\) the total rate of heat loss from the collector, \((b)\) the collector efficiency, which is the ratio of the amount of heat transferred to the water to the solar energy incident on the collector, and \((c)\) the temperature rise of water as it flows through the collector.
Air at \(20^{\circ} \mathrm{C}\) flows over a 4-m-long and 3-m-wide surface of a plate whose temperature is \(80^{\circ} \mathrm{C}\) with a velocity of $5 \mathrm{~m} / \mathrm{s}$. The rate of heat transfer from the laminar flow region of the surface is (a) \(950 \mathrm{~W}\) (b) \(1037 \mathrm{~W}\) (c) \(2074 \mathrm{~W}\) (d) \(2640 \mathrm{~W}\) (e) \(3075 \mathrm{~W}\) (For air, use $k=0.02735 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \operatorname{Pr}=0.7228, \nu=1.798 \times\( \)10^{-5} \mathrm{~m}^{2} / \mathrm{s}$ )
Consider laminar flow over a flat plate. Will the friction coefficient change with distance from the leading edge? How about the heat transfer coefficient?
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