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Express the continuity equation for steady twodimensional flow with constant properties, and explain what each term represents.

Short Answer

Expert verified
Answer: The simplified continuity equation for a steady, two-dimensional flow with constant properties is given by: ∇ ⋅ V = ∂u/∂x + ∂v/∂y = 0 It represents the conservation of mass in the fluid dynamics, stating that the mass entering and leaving the control volume is constant, under the assumptions of steady, incompressible, and two-dimensional flow with constant properties. The terms ∂u/∂x and ∂v/∂y represent the rate of change of the velocity components in their respective directions.

Step by step solution

01

1. Understanding the Continuity Equation

The continuity equation is a mathematical representation of the conservation of mass in fluid dynamics. It states that the mass flowing into a control volume is equal to the mass flowing out of it, assuming no accumulation or loss of mass within the volume. For a steady two-dimensional flow with constant properties, this continuity equation can be expressed in a simplified form.
02

2. Expressing the Continuity Equation

Considering incompressible flow and in terms of velocity components, we can express the continuity equation as: ∇ ⋅ V = ∂u/∂x + ∂v/∂y = 0 Where V represents the velocity vector (u, v), u and v are the velocity components in the x and y directions, respectively, and ∇⋅ represents the divergence operator.
03

3. Explaining Each Term

Now, let's break down each term in the continuity equation: - V = (u, v): This is the velocity vector of the fluid, which has two components, u in the x-direction and v in the y-direction. - ∇⋅: This is the divergence operator, which is used to calculate the rate of change of a fluid property (in this case, mass) in a given direction. It acts on the velocity vector V and results in a scalar value. - ∂u/∂x: This is the partial derivative of the x-component of the velocity with respect to the x-direction. It represents the rate of change of the x-component of velocity as you move in the x-direction. - ∂v/∂y: This is the partial derivative of the y-component of the velocity with respect to the y-direction. It represents the rate of change of the y-component of velocity as you move in the y-direction. - ∇ ⋅ V = ∂u/∂x + ∂v/∂y = 0: The sum of the rates of change of the velocity components in their respective directions is equal to zero. This implies that the mass entering and leaving the control volume is constant, which holds for a steady, incompressible, and two-dimensional flow with constant properties.

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Most popular questions from this chapter

Two metal plates are connected by a long ASTM A479 904L stainless steel bar. A hot gas, at \(400^{\circ} \mathrm{C}\), flows between the plates and across the bar. The bar has a square cross section with a width of \(2 \mathrm{~cm}\), and the length of the bar exposed to the hot gas is \(10 \mathrm{~cm}\). The average convection heat transfer coefficient for the bar in crossflow is correlated with the gas velocity as \(h=13.6 V^{0.675}\), where \(h\) and \(V\) have the units \(\mathrm{W} / \mathrm{m}^{2}, \mathrm{~K}\) and \(\mathrm{m} / \mathrm{s}\), respectively. The maximum use temperature for the ASTM A479 904L is \(260^{\circ} \mathrm{C}\) (ASME Code for Process Piping, ASME B31.3-2014, Table A-1M). The temperature of the bar is maintained by a cooling mechanism with the capability of removing heat at a rate of 100 W. Determine the maximum velocity that the gas can achieve without heating the stainless steel bar above the maximum use temperature set by the ASME Code for Process Piping.

The upper surface of a \(1-\mathrm{m} \times 1-\mathrm{m}\) ASTM B 152 copper plate is being cooled by air at \(20^{\circ} \mathrm{C}\). The air is flowing parallel over the plate surface at a velocity of $0.5 \mathrm{~m} / \mathrm{s}$. The local convection heat transfer coefficient along the plate surface is correlated with the correlation \(h_{x}=1.36 x^{-0.5}\), where \(h_{x}\) and \(x\) have the units \(\mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and \(\mathrm{m}\), respectively. The maximum use temperature for the ASTM B152 copper plate is \(260^{\circ} \mathrm{C}\) (ASME Code for Process Piping, ASME B31.3-2014, Table A-1M). Evaluate the average convection heat transfer coefficient \(h\) for the entire plate. If the rate of convection heat transfer from the plate surface is \(700 \mathrm{~W}\), would the use of ASTM B152 plate be in compliance with the ASME Code for Process Piping?

A long steel strip is being conveyed through a 3 -m-long furnace to be heat treated at a speed of \(0.01 \mathrm{~m} / \mathrm{s}\). The steel strip $\left(k=21 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=8000 \mathrm{~kg} / \mathrm{m}^{3}\right.\(, and \)\left.c_{p}=570 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\( has a thickness of \)5 \mathrm{~mm}$, and it enters the furnace at an initial temperature of \(20^{\circ} \mathrm{C}\). Inside the furnace, the air temperature is maintained at \(900^{\circ} \mathrm{C}\) with a convection heat transfer coefficient of $80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. Using appropriate software, determine the surface temperature gradient of the steel strip as a function of location inside the furnace. By varying the location in the furnace for \(0 \leq x \leq 3 \mathrm{~m}\) with increments of \(0.2 \mathrm{~m}\), plot the surface temperature gradient of the strip as a function of furnace location. Hint: Use the lumped system analysis to calculate the plate surface temperature. Make sure to verify the application of this method to this problem.

An electrical water \((k=0.61 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) heater uses natural convection to transfer heat from a \(1-\mathrm{cm}\)-diameter by \(0.65\)-m-long, \(110 \mathrm{~V}\) electrical resistance heater to the water. During operation, the surface temperature of this heater is \(120^{\circ} \mathrm{C}\) while the temperature of the water is \(35^{\circ} \mathrm{C}\), and the Nusselt number (based on the diameter) is 6 . Considering only the side surface of the heater (and thus \(A=\pi D L\) ), the current passing through the electrical heating element is (a) \(3.2 \mathrm{~A}\) (b) \(3.7 \mathrm{~A}\) (c) \(4.6 \mathrm{~A}\) (d) \(5.8 \mathrm{~A}\) (e) \(6.6 \mathrm{~A}\)

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