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What is turbulent thermal conductivity? What is it caused by?

Short Answer

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Answer: Turbulent thermal conductivity is the ability of a fluid to conduct heat through the transport of fluid particles in turbulent flow. Factors contributing to turbulent thermal conductivity include fluid velocity, density, specific heat, viscosity, and temperature gradient.

Step by step solution

01

Definition of Turbulent Thermal Conductivity

Turbulent thermal conductivity represents the ability of a fluid to conduct heat through the transport of fluid particles in turbulent flow. It is an important parameter in the analysis of heat transfer in turbulent flows and enhances the overall thermal conductivity in a fluid.
02

Causes of Turbulent Thermal Conductivity

Turbulent thermal conductivity is caused by the following factors: 1. Fluid Velocity: As the fluid's velocity increases, the chaotic movement of fluid particles also increases, leading to a higher degree of turbulence. This increased turbulence enhances the rate of heat transfer through the movement of these particles, which results in a higher turbulent thermal conductivity. 2. Fluid Density and Specific Heat: The density and specific heat of a fluid directly affect the turbulent thermal conductivity. A higher density or specific heat allows the fluid to store and transport more thermal energy, thus increasing its turbulent thermal conductivity. 3. Viscosity: If the fluid has a high viscosity, the resistance to the flow of particles is also higher. This resistance can suppress turbulence and may reduce the turbulent thermal conductivity. Conversely, in low-viscosity fluids, turbulent thermal conductivity can increase as there is less resistance to the flow of particles. 4. Temperature Gradient: A large temperature gradient between different regions of the fluid can cause a stronger driving force for heat transfer. This driving force, along with turbulence, can increase the overall heat transfer rate and turbulent thermal conductivity within the fluid. In summary, turbulent thermal conductivity is the ability of a fluid to conduct heat in a turbulent flow and is caused by factors such as fluid velocity, density, specific heat, viscosity, and temperature gradient.

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Most popular questions from this chapter

How does turbulent flow differ from laminar flow? For which flow is the heat transfer coefficient higher?

Two metal plates are connected by a long ASTM B 98 copper-silicon bolt. A hot gas at \(200^{\circ} \mathrm{C}\) flows between the plates and across the cylindrical bolt. The diameter of the bolt is \(9.5 \mathrm{~mm}\), and the length of the bolt exposed to the hot gas is \(10 \mathrm{~cm}\). The average convection heat transfer coefficient for the bolt in crossflow is correlated with the gas velocity as \(h=24.6 \mathrm{~V}^{0.62}\), where \(h\) and \(V\) have the units \(\mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and $\mathrm{m} / \mathrm{s}$, respectively. The maximum use temperature for the ASTM B98 bolt is \(149^{\circ} \mathrm{C}\) (ASME Code for Process Piping, ASME B31.3-2014, Table A-2M). If the gas velocity is \(10.4 \mathrm{~m} / \mathrm{s}\), determine the minimum heat removal rate required to keep the bolt surface from going above the maximum use temperature.

The upper surface of an ASME SB-96 coppersilicon plate is subjected to convection with hot air flowing at \(7.5 \mathrm{~m} / \mathrm{s}\) parallel over the plate surface. The length of the plate is \(1 \mathrm{~m}\), and the temperature of the hot air is \(200^{\circ} \mathrm{C}\). The ASME Boiler and Pressure Vessel Code (ASME BPVC.IV-2015, HF-300) limits equipment constructed with ASME SB-96 plate to be operated at a temperature not exceeding \(93^{\circ} \mathrm{C}\). In the interest of designing a cooling mechanism to keep the plate surface temperature from exceeding \(93^{\circ} \mathrm{C}\), determine the variation of the local heat flux on the plate surface for $0

For steady two-dimensional flow, what are the boundary layer approximations?

Consider a flow over a surface with the velocity and temperature profiles given as $$ \begin{aligned} &u(y)=C_{1}\left(y+y^{2}-y^{3}\right) \\ &T(y)=C_{2}-e^{-2 C_{2} y} \end{aligned} $$ where the coefficients \(C_{1}\) and \(C_{2}\) are constants. Determine the expressions for the friction coefficient \(\left(C_{f}\right)\) and the convection heat transfer coefficient \((h)\).

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