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What is forced convection? How does it differ from natural convection? Is convection that is caused by winds forced or natural convection?

Short Answer

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Short Answer: Forced convection is the process in which heat is transferred through a fluid due to an external force, such as a mechanical device, while natural convection occurs without the need for an external force, as it is caused by the difference in temperature within the fluid. Convection caused by winds can be considered a form of natural convection, as it does not involve any mechanical devices or external forces; instead, it is driven by differences in atmospheric pressure and temperature.

Step by step solution

01

Define Forced Convection

Forced convection is the process in which heat is transferred through a fluid (liquid or gas) due to an external force, such as a mechanical device like a fan or a pump. This external force creates a flow of the fluid, which helps in moving heat from one location to another. It is widely used in various engineering applications, such as cooling electronic devices, automotive radiators, and air-conditioning systems.
02

Define Natural Convection

Natural convection, on the other hand, is the process in which heat is transferred through a fluid (liquid or gas) without the need for an external force. In this case, the fluid movement is caused purely by the difference in temperature between different parts of the fluid itself. When a fluid is heated, it becomes less dense and rises, while the cooler, denser fluid around it sinks, creating a natural circulation and enabling the heat transfer.
03

Differentiate Forced and Natural Convection

The primary difference between forced and natural convection lies in the method of fluid flow. In forced convection, heat transfer occurs due to an external force, which accelerates the fluid flow, whereas, in natural convection, heat transfer occurs due to the buoyancy-driven fluid flow caused by the temperature differences within the fluid.
04

Determine Whether Convection Caused by Winds is Forced or Natural Convection

Convection caused by winds can be considered a form of natural convection, as it doesn't involve any mechanical devices or external forces. Winds are created due to the differences in atmospheric pressure and temperature, making them an example of natural convective heat transfer. Although winds can be strong and turbulence can enhance heat transfer, it is still classified as natural convection since no external force is employed to drive the process.

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Most popular questions from this chapter

How does turbulent flow differ from laminar flow? For which flow is the heat transfer coefficient higher?

In turbulent flow, one can estimate the Nusselt number using the analogy between heat and momentum transfer (Colburn analogy). This analogy relates the Nusselt number to the coefficient of friction, \(C_{p}\) as (a) \(\mathrm{Nu}=0.5 C_{f} \operatorname{Re} \mathrm{Pr}^{1 / 3}\) (c) \(\mathrm{Nu}=C_{f} \operatorname{Re} \mathrm{Pr}^{1 / 3}\) (e) \(\mathrm{Nu}=C_{f} \operatorname{Re}^{1 / 2} \operatorname{Pr}^{1 / 3}\) (d) \(\mathrm{Nu}=C_{f} \operatorname{Re} P r^{2 / 3}\)

A \(5-\mathrm{m} \times 5-\mathrm{m}\) flat plate maintained at a constant temperature of \(80^{\circ} \mathrm{C}\) is subjected to parallel flow of air at \(1 \mathrm{~atm}, 20^{\circ} \mathrm{C}\), and \(10 \mathrm{~m} / \mathrm{s}\). The total drag force acting on the upper surface of the plate is measured to be \(2.4 \mathrm{~N}\). Using the momentum-heat transfer analogy, determine the average convection heat transfer coefficient and the rate of heat transfer between the upper surface of the plate and the air. Evaluate the air properties at \(50^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\).

Two metal plates are connected by a long ASTM A479 904L stainless steel bar. A hot gas, at \(400^{\circ} \mathrm{C}\), flows between the plates and across the bar. The bar has a square cross section with a width of \(2 \mathrm{~cm}\), and the length of the bar exposed to the hot gas is \(10 \mathrm{~cm}\). The average convection heat transfer coefficient for the bar in crossflow is correlated with the gas velocity as \(h=13.6 V^{0.675}\), where \(h\) and \(V\) have the units \(\mathrm{W} / \mathrm{m}^{2}, \mathrm{~K}\) and \(\mathrm{m} / \mathrm{s}\), respectively. The maximum use temperature for the ASTM A479 904L is \(260^{\circ} \mathrm{C}\) (ASME Code for Process Piping, ASME B31.3-2014, Table A-1M). The temperature of the bar is maintained by a cooling mechanism with the capability of removing heat at a rate of 100 W. Determine the maximum velocity that the gas can achieve without heating the stainless steel bar above the maximum use temperature set by the ASME Code for Process Piping.

Consider an airplane cruising at an altitude of \(10 \mathrm{~km}\) where standard atmospheric conditions are \(-50^{\circ} \mathrm{C}\) and $26.5 \mathrm{kPa}\( at a speed of \)800 \mathrm{~km} / \mathrm{h}$. Each wing of the airplane can be modeled as a \(25-\mathrm{m} \times 3-\mathrm{m}\) flat plate, and the friction coefficient of the wings is \(0.0016\). Using the momentum-heat transfer analogy, determine the heat transfer coefficient for the wings at cruising conditions. Answer: $89.6 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$

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