Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In any forced or natural convection situation, the velocity of the flowing fluid is zero where the fluid wets any stationary surface. The magnitude of heat flux where the fluid wets a stationary surface is given by (a) \(k\left(T_{\text {fluid }}-T_{\text {wall }}\right)\) (b) \(\left.k \frac{d T}{d y}\right|_{\text {wall }}\) (c) \(\left.k \frac{d^{2} T}{d y^{2}}\right|_{\text {wall }}\) (d) \(\left.h \frac{d T}{d y}\right|_{\text {wall }}\) (e) None of them

Short Answer

Expert verified
Answer: (a) \(k\left(T_{\text {fluid }}-T_{\text {wall }}\right)\)

Step by step solution

01

Understanding heat flux

Heat flux is the rate of heat transfer per unit area. It gives us an idea of how much heat is being transferred where the fluid wets a stationary surface in forced or natural convection.
02

Understand the given options

We have been given several options for the equation of heat flux in this situation: (a) \(k\left(T_{\text {fluid }}-T_{\text {wall }}\right)\) is representing the heat flux using the temperature difference between the fluid and the wall, and the thermal conductivity k. (b) \(\left.k \frac{d T}{d y}\right|_{\text {wall }}\) is representing the heat flux using the temperature gradient at the wall, and the thermal conductivity k. (c) \(\left.k \frac{d^{2} T}{d y^{2}}\right|_{\text {wall }}\) is representing the heat flux using the second derivative of temperature with respect to y at the wall, and the thermal conductivity k. (d) \(\left.h \frac{d T}{d y}\right|_{\text {wall }}\) is representing the heat flux using the temperature gradient at the wall, and the heat transfer coefficient, h. (e) None of them means that none of the given options represent the correct equation for heat flux in this scenario.
03

Determine the correct equation

The key aspect of this problem is that we are dealing with convection heat transfer where fluid is flowing over a stationary surface. In convection heat transfer situations, the heat transfer is strongly dependent on the temperature difference between the surface and the fluid, and also the heat transfer coefficient which includes the effect of fluid velocity. Hence, the correct option for the problem would reflect the product of heat transfer coefficient and temperature difference. Therefore, the correct answer is: (a) \(k\left(T_{\text {fluid }}-T_{\text {wall }}\right)\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Water vapor at \(0^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) is flowing over a flat plate at a velocity of \(10 \mathrm{~m} / \mathrm{s}\). Using appropriate software, determine the effect of the location along the plate \((x)\) on the velocity and thermal boundary layer thicknesses. By varying \(x\) for $0

What is Newtonian fluid? Is water a Newtonian fluid?

A long steel strip is being conveyed through a 3 -m-long furnace to be heat treated at a speed of \(0.01 \mathrm{~m} / \mathrm{s}\). The steel strip $\left(k=21 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=8000 \mathrm{~kg} / \mathrm{m}^{3}\right.\(, and \)\left.c_{p}=570 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\( has a thickness of \)5 \mathrm{~mm}$, and it enters the furnace at an initial temperature of \(20^{\circ} \mathrm{C}\). Inside the furnace, the air temperature is maintained at \(900^{\circ} \mathrm{C}\) with a convection heat transfer coefficient of $80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. Using appropriate software, determine the surface temperature gradient of the steel strip as a function of location inside the furnace. By varying the location in the furnace for \(0 \leq x \leq 3 \mathrm{~m}\) with increments of \(0.2 \mathrm{~m}\), plot the surface temperature gradient of the strip as a function of furnace location. Hint: Use the lumped system analysis to calculate the plate surface temperature. Make sure to verify the application of this method to this problem.

Air ( \(1 \mathrm{~atm}, 5^{\circ} \mathrm{C}\) ) with free stream velocity of \(2 \mathrm{~m} / \mathrm{s}\) is flowing in parallel to a stationary thin \(1-\mathrm{m} \times 1-\mathrm{m}\) flat plate over the top and bottom surfaces. The flat plate has a uniform surface temperature of $35^{\circ} \mathrm{C}\(. If the friction force asserted on the flat plate is \)0.1 \mathrm{~N}$, determine the rate of heat transfer from the plate. Evaluate the air properties at \(20^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\).

What is a similarity variable, and what is it used for? For what kinds of functions can we expect a similarity solution for a set of partial differential equations to exist?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free