Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What are the two basic methods of solution of transient problems based on finite differencing? How do heat transfer terms in the energy balance formulation differ in the two methods?

Short Answer

Expert verified
Question: Explain the differences in heat transfer terms between the explicit and implicit methods in solving transient problems in finite difference systems. Answer: The differences in heat transfer terms between the explicit and implicit methods in solving transient problems in finite difference systems lie in their time and space differencing approaches. In the explicit method, forward time and central space differencing are used, allowing for future values to be calculated explicitly based on the current values. In the implicit method, backward time and central space differencing are employed, resulting in a system of linear equations that involve both current and future time step values.

Step by step solution

01

Understand the explicit method

In the explicit method, the finite difference approximation of the dependent variable (e.g., temperature) at a future time step is calculated using the information from the current time step. The algorithm allows us to determine the future values of the variable explicitly based on the current values.
02

Compute heat transfer terms in Explicit method

In the explicit method, the heat transfer terms in the energy balance equation are approximated using forward time and central space differencing. For example, in a 1D heat conduction problem with the heat equation: \(\frac{\partial T}{\partial t} = \alpha \frac{\partial^2 T}{\partial x^2}\) The heat transfer terms in the explicit method would be: \(\frac{T^{n+1}_{i}-T^{n}_{i}}{\Delta t} = \alpha \frac{T^n_{i+1}-2T^n_{i}+T^n_{i-1}}{(\Delta x)^2}\) Here, \(T^n_i\) represents temperature at the current time step \(n\) and position \(i\), and \(T^{n+1}_i\) denotes the temperature at the next time step \((n+1)\).
03

Understand the implicit method

The implicit method, also known as the backward Euler method, updates the dependent variable (e.g., temperature) at a future time step using the information from both the current and future time steps. In this method, we solve a system of linear equations to obtain the future values of the variables.
04

Compute heat transfer terms in Implicit method

In the implicit method, the heat transfer terms in the energy balance equation are approximated using backward time and central space differencing. Using the 1D heat conduction problem, the heat transfer terms in the implicit method would be: \(\frac{T^{n+1}_{i}-T^n_{i}}{\Delta t} = \alpha \frac{T^{n+1}_{i+1}-2T^{n+1}_{i}+T^{n+1}_{i-1}}{(\Delta x)^2}\) Here, both the temperature at the next time step \((n+1)\) and the current time step \(n\) are used to compute the heat transfer terms.
05

Compare the heat transfer terms in the explicit and implicit methods

The key difference between the heat transfer terms in the explicit and implicit methods lies in the time and space differencing approaches. In the explicit method, we use forward time and central space differencing, which allows us to find the solution for the next time step explicitly based on the current values. In the implicit method, we employ backward time and central space differencing, resulting in a system of linear equations that involve both current and future time step values. In summary, both the explicit and implicit methods solve transient problems in finite difference systems using different approaches to heat transfer terms in the energy balance equation. The explicit method calculates future values explicitly using current time step values, while the implicit method requires solving a system of linear equations involving both current and future time step values.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider a large uranium plate of thickness \(L=9 \mathrm{~cm}\), thermal conductivity \(k=28 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and thermal diffusivity \(\alpha=12.5 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) that is initially at a uniform temperature of \(100^{\circ} \mathrm{C}\). Heat is generated uniformly in the plate at a constant rate of $\dot{e}=10^{6} \mathrm{~W} / \mathrm{m}^{3}\(. At time \)t=0$, the left side of the plate is insulated while the other side is subjected to convection with an environment at \(T_{\infty}=20^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(h=35 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Using the explicit finite difference approach with a uniform nodal spacing of $\Delta x=1.5 \mathrm{~cm}\(, determine \)(a)$ the temperature distribution in the plate after \(5 \mathrm{~min}\) and \((b)\) how long it will take for steady conditions to be reached in the plate.

A cylindrical aluminum fin with adiabatic tip is attached to a wall with surface temperature of \(300^{\circ} \mathrm{C}\), and it is exposed to an ambient air condition of \(15^{\circ} \mathrm{C}\) with convection heat transfer coefficient of \(150 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The fin has a uniform cross section with diameter of \(1 \mathrm{~cm}\), length of $5 \mathrm{~cm}\(, and thermal conductivity of \)237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. Assuming steady one-dimensional heat transfer along the fin and the nodal spacing to be uniformly \(10 \mathrm{~mm},(a)\) obtain the finite difference equations for use with the Gauss-Seidel iterative method, and \((b)\) determine the nodal temperatures using the Gauss-Seidel iterative method, and compare the results with the analytical solution.

What are the basic steps involved in solving a system of equations with the Gauss-Seidel method?

Why do the results obtained using a numerical method differ from the exact results obtained analytically? What are the causes of this difference?

In many engineering applications variation in thermal properties is significant, especially when there are large temperature gradients or the material is not homogeneous. To account for these variations in thermal properties, develop a finite difference formulation for an internal node in the case of a three-dimensional, steady-state heat conduction equation with variable thermal conductivity.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free