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Consider steady two-dimensional heat transfer in a square cross section $(3 \mathrm{~cm} \times 3 \mathrm{~cm})$ with the prescribed temperatures at the top, right, bottom, and left surfaces to be $100^{\circ} \mathrm{C}, 200^{\circ} \mathrm{C}, 300^{\circ} \mathrm{C}\(, and \)500^{\circ} \mathrm{C}$, respectively. Using a uniform mesh size \(\Delta x=\Delta y\), determine \((a)\) the finite difference equations and \((b)\) the nodal temperatures with the GaussSeidel iterative method.

Short Answer

Expert verified
Answer: The key steps in solving the steady two-dimensional heat transfer problem are: 1) Determining mesh size and node points, 2) Applying the finite difference equations, 3) Applying boundary conditions, 4) Applying the Gauss-Seidel iterative method, and 5) Determining the nodal temperatures.

Step by step solution

01

Determine Mesh Size and Node Points

Use the given uniform mesh size, which is \(\Delta x = \Delta y\). Since the dimensions are \(3\,\mathrm{cm} \times 3\, \mathrm{cm}\), choose the convenient mesh size, such as: \(\Delta x = \Delta y = 1\, \mathrm{cm}\). Then, the square can be divided into 9 nodes labeled as \((1,1)\) to \((3,3)\) and arranged in a 3x3 matrix.
02

Apply the Finite Difference Equations

Use the finite difference equation for steady two-dimensional heat transfer, given as: \(\frac{T_{i+1,j} - 2T_{i,j} + T_{i-1,j}}{(\Delta x)^2} + \frac{T_{i,j+1} - 2T_{i,j} + T_{i,j-1}}{(\Delta y)^2} = 0\) Since \(\Delta x = \Delta y\), the equation becomes: \(T_{i+1,j} - 2T_{i,j} + T_{i-1,j} + T_{i,j+1} - 2T_{i,j} + T_{i,j-1} = 0\) The above equation can be simplified to: \(4T_{i,j} = T_{i+1,j} + T_{i-1,j} + T_{i,j+1} + T_{i,j-1}\)
03

Apply Boundary Conditions

Use the given boundary temperatures to replace the corresponding terms in the finite difference equation, starting from the corners and moving inwards. For example, when \(i=1, j=1\), the equation is: \(4T_{1,1} = T_{2,1}+500+T_{1,2} + 300\) Similarly, determine the other boundary conditions while taking note of the values across each side.
04

Apply the Gauss-Seidel Iterative Method

Using the Gauss-Seidel iterative method, update the temperature values at each node point iteratively. Start with initial guesses for the internal nodal temperatures, like \(T_{ij}=0\). Update the internal temperatures using the boundary conditions and the finite difference equation. \(T^{k+1}_{i,j} = \frac{1}{4} (T^{k}_{i+1,j} + T^{k+1}_{i-1,j} + T^{k}_{i,j+1} + T^{k+1}_{i,j-1})\) Repeat this process until the convergence criterion is reached or the maximum number of iterations is completed. The convergence criterion can be based on the difference between successive iterations or the error in the solution's accuracy.
05

Determine Nodal Temperatures

After applying the Gauss-Seidel iterative method and reaching the desired convergence level, find the nodal temperatures corresponding to the converged values of \(T_{i,j}\) and output the results. In conclusion, following these steps will allow determining the finite difference equations and finding the nodal temperatures using the Gauss-Seidel iterative method for the steady two-dimensional heat transfer in a square cross-section.

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Most popular questions from this chapter

Consider a stainless steel spoon $(k=15.1 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\(, \)\varepsilon=0.6$ ) that is partially immersed in boiling water at \(100^{\circ} \mathrm{C}\) in a kitchen at \(32^{\circ} \mathrm{C}\). The handle of the spoon has a cross section of about $0.2 \mathrm{~cm} \times 1 \mathrm{~cm}\( and extends \)18 \mathrm{~cm}$ in the air from the free surface of the water. The spoon loses heat by convection to the ambient air with an average heat transfer coefficient of $h=13 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$ as well as by radiation to the surrounding surfaces at an average temperature of \(T_{\text {surr }}=295 \mathrm{~K}\). Assuming steady one- dimensional heat transfer along the spoon and taking the nodal spacing to be \(3 \mathrm{~cm},(a)\) obtain the finite difference formulation for all nodes, \((b)\) determine the temperature of the tip of the spoon by solving those equations, and (c) determine the rate of heat transfer from the exposed surfaces of the spoon.

Hot combustion gases of a furnace are flowing through a concrete chimney \((k=1.4 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) of rectangular cross section. The flow section of the chimney is $20 \mathrm{~cm} \times 40 \mathrm{~cm}\(, and the thickness of the wall is \)10 \mathrm{~cm}$. The average temperature of the hot gases in the chimney is \(T_{i}=280^{\circ} \mathrm{C}\), and the average convection heat transfer coefficient inside the chimney is \(h_{l}=75 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The chimney is losing heat from its outer surface to the ambient air at $T_{0}=15^{\circ} \mathrm{C}\( by convection with a heat transfer coefficient of \)h_{o}=18 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$ and to the sky by radiation. The emissivity of the outer surface of the wall is \(\varepsilon=0.9\), and the effective sky temperature is estimated to be \(250 \mathrm{~K}\). Using the finite difference method with \(\Delta x=\Delta y=10 \mathrm{~cm}\) and taking full advantage of symmetry, \((a)\) obtain the finite difference formulation of this problem for steady two-dimensional heat transfer, (b) determine the temperatures at the nodal points of a cross section, and \((c)\) evaluate the rate of heat loss for a \(1-m\)-long section of the chimney.

A cylindrical aluminum fin with adiabatic tip is attached to a wall with surface temperature of \(300^{\circ} \mathrm{C}\), and it is exposed to an ambient air condition of \(15^{\circ} \mathrm{C}\) with convection heat transfer coefficient of \(150 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The fin has a uniform cross section with diameter of \(1 \mathrm{~cm}\), length of $5 \mathrm{~cm}\(, and thermal conductivity of \)237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. Assuming steady one-dimensional heat transfer along the fin and the nodal spacing to be uniformly \(10 \mathrm{~mm},(a)\) obtain the finite difference equations for use with the Gauss-Seidel iterative method, and \((b)\) determine the nodal temperatures using the Gauss-Seidel iterative method, and compare the results with the analytical solution.

Consider a long solid bar \((k=28 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and \(\alpha=12 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) ) of square cross section that is initially at a uniform temperature of \(32^{\circ} \mathrm{C}\). The cross section of the bar is \(20 \mathrm{~cm} \times 20 \mathrm{~cm}\) in size, and heat is generated in it uniformly at a rate of $\dot{e}=8 \times 10^{5} \mathrm{~W} / \mathrm{m}^{3}$. All four sides of the bar are subjected to convection to the ambient air at \(T_{\infty}=30^{\circ} \mathrm{C}\) with a heat transfer coefficient of $h=45 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. Using the explicit finite difference method with a mesh size of \(\Delta x=\Delta y=10 \mathrm{~cm}\), determine the centerline temperature of the bar \((a)\) after \(20 \mathrm{~min}\) and \((b)\) after steady conditions are established.

Starting with an energy balance on the volume element, obtain the steady three-dimensional finite difference equation for a general interior node in rectangular coordinates for \(T(x, y, z)\) for the case of constant thermal conductivity and uniform heat generation.

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