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Using appropriate software, solve these systems of algebraic equations. (a) $$ \begin{aligned} 4 x_{1}-x_{2}+2 x_{3}+x_{4} &=-6 \\ x_{1}+3 x_{2}-x_{3}+4 x_{4} &=-1 \\ -x_{1}+2 x_{2}+5 x_{4} &=5 \\ 2 x_{2}-4 x_{3}-3 x_{4} &=-5 \end{aligned} $$ (b) $$ \begin{aligned} 2 x_{1}+x_{2}^{4}-2 x_{3}+x_{4} &=1 \\ x_{1}^{2}+4 x_{2}+2 x_{3}^{2}-2 x_{4} &=-3 \\ -x_{1}+x_{2}^{4}+5 x_{3} &=10 \\ 3 x_{1}-x_{3}^{2}+8 x_{4} &=15 \end{aligned} $$

Short Answer

Expert verified
Answer: The key differences in solving a system of linear and nonlinear equations using a computer software are the methods that the software uses, and the type and number of solutions that may be obtained. For linear systems, the solutions are unique and can be found through methods like matrix inversion. For nonlinear systems, the software may provide multiple solutions or numerical approximations, and the methods used can involve techniques like iterative solvers or symbolic manipulation. It is important to understand the software's limitations and syntax when solving both types of systems.

Step by step solution

01

(a) Solving the linear system using software

To solve the linear system of algebraic equations, input the following system in a software of your choice (Wolfram|Alpha, MATLAB, etc.): $$ \begin{aligned} 4 x_{1}-x_{2}+2 x_{3}+x_{4} &=-6 \\\ x_{1}+3 x_{2}-x_{3}+4 x_{4} &=-1 \\\ -x_{1}+2 x_{2}+5 x_{4} &=5 \\\ 2 x_{2}-4 x_{3}-3 x_{4} &=-5 \end{aligned} $$ The software will provide the solutions for the variables \(x_1, x_2, x_3,\) and \(x_4\). Note: Each software may have different syntax for inputting the system of equations. Refer to the software documentation or help files for the correct syntax.
02

(b) Solving the nonlinear system using software

To solve the nonlinear system of algebraic equations, input the following system in a software of your choice (Wolfram|Alpha, MATLAB, etc.): $$ \begin{aligned} 2 x_{1}+x_{2}^{4}-2 x_{3}+x_{4} &=1 \\\ x_{1}^{2}+4 x_{2}+2 x_{3}^{2}-2 x_{4} &=-3 \\\ -x_{1}+x_{2}^{4}+5 x_{3} &=10 \\\ 3 x_{1}-x_{3}^{2}+8 x_{4} &=15 \end{aligned} $$ The software will provide the solutions for the variables \(x_1, x_2, x_3,\) and \(x_4\). Note: For nonlinear systems, the software may provide multiple solutions or numerical approximations depending on its capabilities and settings. Ensure that you understand the particular software's limitations and follow its syntax when inputting the system of equations. Remember to verify the solutions provided by the software by substituting them back into the original equations to check if the equations are satisfied.

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Most popular questions from this chapter

Starting with an energy balance on a volume element, obtain the two- dimensional transient explicit finite difference equation for a general interior node in rectangular coordinates for \(T(x, y, t)\) for the case of constant thermal conductivity and no heat generation.

A hot surface at \(100^{\circ} \mathrm{C}\) is to be cooled by attaching \(3-\mathrm{cm}-\) long, \(0.25-\mathrm{cm}\)-diameter aluminum pin fins $(k=237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})$ with a center-to-center distance of \(0.6 \mathrm{~cm}\). The temperature of the surrounding medium is \(30^{\circ} \mathrm{C}\), and the combined heat transfer coefficient on the surfaces is \(35 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Assuming steady one-dimensional heat transfer along the fin and taking the nodal spacing to be \(0.5 \mathrm{~cm}\), determine \((a)\) the finite difference formulation of this problem, \((b)\) the nodal temperatures along the fin by solving these equations, \((c)\) the rate of heat transfer from a single fin, and \((d)\) the rate of heat transfer from a \(1-\mathrm{m} \times 1-\mathrm{m}\) section of the plate.

Using appropriate software, solve these systems of algebraic equations. (a) \(\quad 3 x_{1}-x_{2}+3 x_{3}=0\) $$ \begin{array}{r} -x_{1}+2 x_{2}+x_{3}=3 \\ 2 x_{1}-x_{2}-x_{3}=2 \end{array} $$ (b) $$ \begin{aligned} 4 x_{1}-2 x_{2}^{2}+0.5 x_{3} &=-2 \\ x_{1}^{3}-x_{2}+x_{3} &=11.964 \\ x_{1}+x_{2}+x_{3} &=3 \end{aligned} $$ Answers: \((a) x_{1}=2, x_{2}=3, x_{3}=-1,(b) x_{1}=2.33, x_{2}=2.29\), \(x_{3}=-1.62\)

In the energy balance formulation of the finite difference method, it is recommended that all heat transfer at the boundaries of the volume element be assumed to be into the volume element even for steady heat conduction. Is this a valid recommendation even though it seems to violate the conservation of energy principle?

A composite wall is made of stainless steel $\left(k_{1}=13 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \quad 30 \mathrm{~mm}\right.$ thick), concrete $\left(k_{2}=1.1 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, 30 \mathrm{~mm}\right.\( thick \))\(, and nonmetal \)\left(k_{3}=0.1 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\right.\(, \)15 \mathrm{~mm}$ thick) plates. The concrete plate is sandwiched between the stainless steel plate at the bottom and the nonmetal plate at the top. A series of ASTM B21 naval brass bolts are bolted to the nonmetal plate, and the upper surface of the plate is exposed to convection heat transfer with air at \(20^{\circ} \mathrm{C}\) and $h=20 \mathrm{~W} / \mathrm{m}^{2}$.K. At the bottom surface, the stainless steel plate is subjected to a uniform heat flux of $2000 \mathrm{~W} / \mathrm{m}^{2}$. The ASME Code for Process Piping (ASME B31.3-2014, Table A-2M) limits the maximum use temperature for the ASTM B21 bolts to \(149^{\circ} \mathrm{C}\). Using the finite difference method with a uniform nodal spacing of \(\Delta x_{1}=10 \mathrm{~mm}\) for the stainless steel and concrete plates, and \(\Delta x_{2}=5 \mathrm{~mm}\) for the nonmetal plate, determine the temperature at each node. Plot the temperature distribution as a function of \(x\) along the plate thicknesses. Would the ASTM B21 bolts in the nonmetal plate comply with the ASME code?

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