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A plane wall with surface temperature of \(350^{\circ} \mathrm{C}\) is attached with straight rectangular fins $(k=235 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\(. The fins are exposed to an ambient air condition of \)25^{\circ} \mathrm{C}\(, and the convection heat transfer coefficient is \)154 \mathrm{~W} / \mathrm{m}^{2}, \mathrm{~K}\(. Each fin has a length of \)50 \mathrm{~mm}$, a base \(5 \mathrm{~mm}\) thick, and a width of \(100 \mathrm{~mm}\). For a single fin, using a uniform nodal spacing of \(10 \mathrm{~mm}\), determine \((a)\) the finite difference equations, (b) the nodal temperatures by solving the finite difference equations, and \((c)\) the heat transfer rate and compare the result with the analytical solution.

Short Answer

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Question: Determine the heat transfer rate for a given plane wall with attached rectangular fins using the finite difference method and compare the result with the analytical solution. Solution: Step 1: Representation of the fin using finite difference method - Divide the fin length (50mm) in equal spacing of 10mm, creating a total of 6 nodes (including the fin base). Assign the surface temperature of the plane wall at the first node. Step 2: Setting up the finite difference equations - For each interior node, use the finite difference equation based on the heat conduction equation. For exterior node (fin tip) condition and the first node (attached to the wall), use the respective equations with boundary conditions. Step 3: Solve the system of equations for nodal temperatures - Substitute the given values and boundary conditions into the finite difference equations and solve for nodal temperatures using matrix inversion or other numerical methods. Step 4: Calculate the heat transfer rate and compare with analytical solution - Calculate the heat transfer rate for each fin from the nodal temperatures and add them up to analyze the total heat transfer rate for the fin numerically. Compare this with the analytical solution by using the equation for straight rectangular fins.

Step by step solution

01

Representation of the fin using finite difference method

Divide the fin length (50mm) in equal spacing of 10mm, creating a total of 6 nodes (including the fin base). Assign the surface temperature of the plane wall at the first node.
02

Setting up the finite difference equations

For each interior node, we will use the following finite difference equation based on the heat conduction equation: \[ \frac{k \cdot A(T_{i+1} - 2T_i + T_{i-1})}{\Delta x^2} - hP(T_i - T_{\infty}) = 0 \] For exterior node (fin tip) condition, the following equation will be used: \[ \frac{k \cdot A(T_{i-1} - T_i)}{\Delta x} - hP(T_i - T_{\infty}) = 0 \] For the first node (attached to the wall), use the surface temperature as the boundary condition.
03

Solve the system of equations for nodal temperatures

We will now substitute the given values and boundary conditions into the finite difference equations and solve for nodal temperatures. We will have a set of 5 equations for 5 nodes (excluding node 1, which has a surface temperature). The equations can be solved using matrix inversion or other numerical methods.
04

Calculate the heat transfer rate and compare with analytical solution

Calculate the heat transfer rate for each fin from the nodal temperatures using the equations derived in step 2. Add up the heat transfer rate for each node from the node 1 to node 5 and analyze the total heat transfer rate for the fin numerically. Compare this with the analytical solution by using the following equation for straight rectangular fins: \[ q = \sqrt{hP \cdot kA} \cdot \frac{\sinh(mL)}{\cosh(mL)} \cdot (T_s - T_{\infty}) \] where \(m = \sqrt{(hP)/(kA)}\) and \(L\) is the fin length. By comparing the numerical solution and analytical solution for the heat transfer rate, we can validate the accuracy of the finite difference method used in this problem.

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Most popular questions from this chapter

Consider a long solid bar \((k=28 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and \(\alpha=12 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) ) of square cross section that is initially at a uniform temperature of \(32^{\circ} \mathrm{C}\). The cross section of the bar is \(20 \mathrm{~cm} \times 20 \mathrm{~cm}\) in size, and heat is generated in it uniformly at a rate of $\dot{e}=8 \times 10^{5} \mathrm{~W} / \mathrm{m}^{3}$. All four sides of the bar are subjected to convection to the ambient air at \(T_{\infty}=30^{\circ} \mathrm{C}\) with a heat transfer coefficient of $h=45 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. Using the explicit finite difference method with a mesh size of \(\Delta x=\Delta y=10 \mathrm{~cm}\), determine the centerline temperature of the bar \((a)\) after \(20 \mathrm{~min}\) and \((b)\) after steady conditions are established.

What is a practical way of checking if the discretization error has been significant in calculations?

Starting with an energy balance on a volume element, obtain the two- dimensional transient implicit finite difference equation for a general interior node in rectangular coordinates for \(T(x, y, t)\) for the case of constant thermal conductivity and no heat generation.

Design a defrosting plate to speed up defrosting of flat food items such as frozen steaks and packaged vegetables, and evaluate its performance using the finite difference method. Compare your design to the defrosting plates currently available on the market. The plate must perform well, and it must be suitable for purchase and use as a household utensil, durable, easy to clean, easy to manufacture, and affordable. The frozen food is expected to be at an initial temperature of \(-18^{\circ} \mathrm{C}\) at the beginning of the thawing process and \(0^{\circ} \mathrm{C}\) at the end with all the ice melted. Specify the material, shape, size, and thickness of the proposed plate. Justify your recommendations by calculations. Take the ambient and surrounding surface temperatures to be \(20^{\circ} \mathrm{C}\) and the convection heat transfer coefficient to be \(15 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) in your analysis. For a typical case, determine the defrosting time with and without the plate.

A stainless steel plate is connected to an insulation plate by square ASTM A479 904L stainless steel bars. Each square bar has a thickness of $1 \mathrm{~cm}\( and a length of \)5 \mathrm{~cm}$. The bars are exposed to convection heat transfer with a hot gas. The temperature of the hot gas is \(300^{\circ} \mathrm{C}\) with a convection heat transfer coefficient of $25 \mathrm{~W} / \mathrm{m}^{2}$. . The thermal conductivity for ASTM A479 904L stainless steel is known to be \(12 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The stainless steel plate maintains a uniform temperature of $100^{\circ} \mathrm{C}$. According to the ASME Code for Process Piping (ASME B31.3-2014, Table A-1M), the maximum use temperature for ASTM A479 904L stainless steel bar is \(260^{\circ} \mathrm{C}\). Using the finite difference method with a uniform nodal spacing of \(\Delta x=5 \mathrm{~mm}\) along the bar, determine the temperature at each node. Compare the numerical results with the analytical solution. Plot the temperature distribution along the bar. Would any part of the ASTM A479 904L bars be above the maximum use temperature of \(260^{\circ} \mathrm{C}\) ?

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