Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What is the basis of the energy balance method? How does it differ from the formal finite difference method? For a specified nodal network, will these two methods result in the same or a different set of equations?

Short Answer

Expert verified
Answer: The key differences between the energy balance method and the finite difference method lie in their mathematical approaches and the types of problems they are best suited for. The energy balance method is based on the conservation of energy principle and typically leads to simpler and more intuitive equations, while the finite difference method focuses on approximating partial derivatives using discrete values and is better suited for complex geometries and boundary conditions. Despite their differences, both methods can be used to solve the same types of problems and can yield similar results when applied correctly and accurately to the same nodal network.

Step by step solution

01

Energy Balance Method

The energy balance method is based on the conservation of energy principle. It states that the amount of energy that enters a system should be equal to the energy that leaves the system plus the change in its internal energy. In order to apply the energy balance method, we can commonly represent energy processes in terms of energy equations, which are typically formed by applying the first law of thermodynamics to a control volume. This can be achieved by dividing the domain into discrete elements and assuming that the energy exchange between the elements is only through conduction.
02

Finite Difference Method

The finite difference method is a numerical technique used to approximate the solution of partial differential equations by discretizing the derivatives present in the equation. It involves dividing the domain into an evenly spaced grid and replacing the continuous derivatives with their proper discrete approximations. The results of these approximations are used to form a system of linear algebraic equations that can be easily solved.
03

Comparison of Both Methods

Both energy balance and finite difference methods involve the discretization of the domain, but the key difference lies in their mathematical basis. The energy balance method is based on the conservation of energy principle, while the finite difference method focuses on approximating partial derivatives using discrete values. Moreover, the energy balance method typically leads to simpler and more intuitive equations, whereas the finite difference method better handles complex geometries and boundary conditions.
04

Equations Resulted from Both Methods

For a specified nodal network, these two methods could potentially lead to different sets of equations. The energy balance method would rely on the first law of thermodynamics to derive the set of equations, while the finite difference method would derive its set of equations from the discretized partial differential equation. However, despite their differences, both methods are often able to solve the same types of problems and can yield similar results when both are applied correctly and accurately to the same nodal network.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider an aluminum alloy fin $(k=180 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\( of triangular cross section whose length is \)L=5 \mathrm{~cm}$, base thickness is \(b=1 \mathrm{~cm}\), and width \(w\) in the direction normal to the plane of paper is very large. The base of the fin is maintained at a temperature of \(T_{0}=180^{\circ} \mathrm{C}\). The fin is losing heat by convection to the ambient air at \(T_{\infty}=25^{\circ} \mathrm{C}\) with a heat transfer coefficient of $h=25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$ and by radiation to the surrounding surfaces at an average temperature of \(T_{\text {sarr }}=290 \mathrm{~K}\). Using the finite difference method with six equally spaced nodes along the fin in the \(x\)-direction, determine \((a)\) the temperatures at the nodes and (b) the rate of heat transfer from the fin for \(w=1 \mathrm{~m}\). Take the emissivity of the fin surface to be \(0.9\) and assume steady onedimensional heat transfer in the fin. Answers: (a) \(177.0^{\circ} \mathrm{C}\), $174.1^{\circ} \mathrm{C}, 171.2^{\circ} \mathrm{C}, 168.4^{\circ} \mathrm{C}, 165.5^{\circ} \mathrm{C} ;\( (b) \)537 \mathrm{~W}$

How can a node on an insulated boundary be treated as an interior node in the finite difference formulation of a plane wall? Explain.

A hot brass plate is having its upper surface cooled by an impinging jet of air at a temperature of \(15^{\circ} \mathrm{C}\) and convection heat transfer coefficient of \(220 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The 10 -cm-thick brass plate $\left(\rho=8530 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=380 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, k=110 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\right.\(, and \)\alpha=33.9 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}$ ) had a uniform initial temperature of \(650^{\circ} \mathrm{C}\), and the lower surface of the plate is insulated. Using a uniform nodal spacing of \(\Delta x=2.5 \mathrm{~cm}\), determine \((a)\) the explicit finite difference equations, \((b)\) the maximum allowable value of the time step, and \((c)\) the temperature at the center plane of the brass plate after 1 min of cooling, and (d) compare the result in (c) with the approximate analytical solution from Chap. \(4 .\)

Consider steady two-dimensional heat transfer in a long solid bar of square cross section in which heat is generated uniformly at a rate of $\dot{e}=0.19 \times 10^{5} \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{3}$. The cross section of the bar is \(0.5 \mathrm{ft} \times 0.5 \mathrm{ft}\) in size, and its thermal conductivity is $k=16 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft} \cdot{ }^{\circ} \mathrm{F}$. All four sides of the bar are subjected to convection with the ambient air at \(T_{\infty}=70^{\circ} \mathrm{F}\) with a heat transfer coefficient of $h=7.9 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{2} \cdot{ }^{\circ} \mathrm{F}$. Using the finite difference method with a mesh size of \(\Delta x=\Delta y=0.25 \mathrm{ft}\), determine \((a)\) the temperatures at the nine nodes and \((b)\) the rate of heat loss from the bar through a 1-ft-long section.

What are the two basic methods of solution of transient problems based on finite differencing? How do heat transfer terms in the energy balance formulation differ in the two methods?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free