Chapter 5: Problem 14
What are the basic steps involved in solving a system of equations with the Gauss-Seidel method?
Chapter 5: Problem 14
What are the basic steps involved in solving a system of equations with the Gauss-Seidel method?
All the tools & learning materials you need for study success - in one app.
Get started for freeA nonmetal plate is connected to a stainless steel plate by long ASTM A437 B4B stainless steel bolts \(9.5 \mathrm{~mm}\) in diameter. The portion of the bolts exposed to convection heat transfer with a cryogenic fluid is \(5 \mathrm{~cm}\) long. The fluid temperature for convection is at \(-50^{\circ} \mathrm{C}\) with a convection heat transfer coefficient of $100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. The thermal conductivity of the bolts is known to be \)23.9 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. Both the nonmetal and stainless steel plates maintain a uniform temperature of \(0^{\circ} \mathrm{C}\). According to the ASME Code for Process Piping (ASME B31.3-2014, Table A-2M), the minimum temperature suitable for ASTM A437 B4B stainless steel bolts is \(-30^{\circ} \mathrm{C}\). Using the finite difference method with a uniform nodal spacing of \(\Delta x=5 \mathrm{~mm}\) along the bolt, determine the temperature at each node. Compare the numerical results with the analytical solution. Plot the temperature distribution along the bolt. Would any part of the ASTM A437 B4B bolts be lower than the minimum suitable temperature of \(-30^{\circ} \mathrm{C}\) ?
Solar radiation incident on a large body of clean water $\left(k=0.61 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\right.\( and \)\left.\alpha=0.15 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right)$ such as a lake, a river, or a pond is mostly absorbed by water, and the amount of absorption varies with depth. For solar radiation incident at a \(45^{\circ}\) angle on a \(1-\mathrm{m}\)-deep large pond whose bottom surface is black (zero reflectivity), for example, \(2.8\) percent of the solar energy is reflected back to the atmosphere, \(37.9\) percent is absorbed by the bottom surface, and the remaining \(59.3\) percent is absorbed by the water body. If the pond is considered to be four layers of equal thickness \((0.25 \mathrm{~m}\) in this case), it can be shown that \(47.3\) percent of the incident solar energy is absorbed by the top layer, \(6.1\) percent by the upper mid layer, \(3.6\) percent by the lower mid layer, and 2.4 percent by the bottom layer [for more information, see Cengel and Ozi?ik, Solar Energy, 33, no. 6 (1984), pp. 581-591]. The radiation absorbed by the water can be treated conveniently as heat generation in the heat transfer analysis of the pond. Consider a large \(1-\mathrm{m}\)-deep pond that is initially at a uniform temperature of \(15^{\circ} \mathrm{C}\) throughout. Solar energy is incident on the pond surface at \(45^{\circ}\) at an average rate of $500 \mathrm{~W} / \mathrm{m}^{2}$ for a period of 4 h. Assuming no convection currents in the water and using the explicit finite difference method with a mesh size of \(\Delta x=0.25 \mathrm{~m}\) and a time step of \(\Delta t=15 \mathrm{~min}\), determine the temperature distribution in the pond under the most favorable conditions (i.e., no heat losses from the top or bottom surfaces of the pond). The solar energy absorbed by the bottom surface of the pond can be treated as a heat flux to the water at that surface in this case.
Consider a large plane wall of thickness \(L=0.4 \mathrm{~m}\), thermal conductivity \(k=2.3 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and surface area \(A=20 \mathrm{~m}^{2}\). The left side of the wall is maintained at a constant temperature of \(95^{\circ} \mathrm{C}\), while the right side loses heat by convection to the surrounding air at $T_{\infty}=15^{\circ} \mathrm{C}\( with a heat transfer coefficient of \)h=18 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. Assuming steady one-dimensional heat transfer and taking the nodal spacing to be \(10 \mathrm{~cm}\), (a) obtain the finite difference formulation for all nodes, (b) determine the nodal temperatures by solving those equations, and (c) evaluate the rate of heat transfer through the wall.
A stainless steel plate is connected to a copper plate by long ASTM B98 copper-silicon bolts \(9.5 \mathrm{~mm}\) in diameter. The portion of the bolts exposed to convection heat transfer with hot gas is \(5 \mathrm{~cm}\) long. The gas temperature for convection is at \(500^{\circ} \mathrm{C}\) with a convection heat transfer coefficient of $50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. The thermal conductivity of the bolt is known to be \)36 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. The stainless steel plate has a uniform temperature of \(100^{\circ} \mathrm{C}\), and the copper plate has a uniform temperature of \(80^{\circ} \mathrm{C}\). According to the ASME Code for Process Piping (ASME B31.3-2014, Table A-2M), the maximum use temperature for an ASTM B98 copper-silicon bolt is \(149^{\circ} \mathrm{C}\). Using the finite difference method with a uniform nodal spacing of \(\Delta x=5 \mathrm{~mm}\) along the bolt, determine the temperature at each node. Plot the temperature distribution along the bolt. Compare the numerical results with the analytical solution. Would any part of the ASTM B 98 bolts be above the maximum use temperature of \(149^{\circ} \mathrm{C}\) ?
Consider a large uranium plate of thickness \(L=9 \mathrm{~cm}\), thermal conductivity \(k=28 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and thermal diffusivity \(\alpha=12.5 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) that is initially at a uniform temperature of \(100^{\circ} \mathrm{C}\). Heat is generated uniformly in the plate at a constant rate of $\dot{e}=10^{6} \mathrm{~W} / \mathrm{m}^{3}\(. At time \)t=0$, the left side of the plate is insulated while the other side is subjected to convection with an environment at \(T_{\infty}=20^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(h=35 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Using the explicit finite difference approach with a uniform nodal spacing of $\Delta x=1.5 \mathrm{~cm}\(, determine \)(a)$ the temperature distribution in the plate after \(5 \mathrm{~min}\) and \((b)\) how long it will take for steady conditions to be reached in the plate.
What do you think about this solution?
We value your feedback to improve our textbook solutions.