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Consider transient heat conduction in a plane wall with variable heat generation and constant thermal conductivity. The nodal network of the medium consists of nodes 0 , \(1,2,3\), and 4 with a uniform nodal spacing of $\Delta x$. The wall is initially at a specified temperature. The temperature at the right boundary (node 4) is specified. Using the energy balance approach, obtain the explicit finite difference formulation of the boundary node 0 for the case of combined convection, radiation, and heat flux at the left boundary with an emissivity of \(\varepsilon\), convection coefficient of \(h\), ambient temperature of \(T_{\infty}\), surrounding temperature of \(T_{\text {surr }}\), and uniform heat flux of \(\dot{q}_{0}\) toward the wall. Also, obtain the finite difference formulation for the total amount of heat transfer at the right boundary for the first 20 time steps.

Short Answer

Expert verified
2. What are the boundary conditions for node 0 (left boundary) and node 4 (right boundary)? 3. What is the explicit finite difference formulation for calculating temperatures at node 0? 4. How can the finite difference formulation for the total amount of heat transfer at the right boundary for the first 20 time steps be determined?

Step by step solution

01

Governing equation for transient heat conduction

The governing equation for transient heat conduction with variable heat generation and constant thermal conductivity can be represented as: $$\frac{\partial T}{\partial t} = \alpha \frac{\partial^2 T}{\partial x^2} + q(x, t)$$ where \(T\) is the temperature, \(\alpha\) is the thermal diffusivity, and \(q(x, t)\) represents the heat generation rate per unit volume in the medium.
02

Define boundary conditions

The boundary conditions for our problem are as follows: At the left boundary (node 0): 1. Convection heat transfer: \(h(T_0 - T_{\infty})\) 2. Radiation heat transfer: \(\varepsilon\sigma(T_0^4 - T_\text{surr}^4)\) 3. Heat flux toward the wall: \(\dot{q}_{0}\) At the right boundary (node 4): Temperature is specified.
03

Develop explicit finite difference formulation for node 0

Developing an explicit finite difference formulation for node 0 using the forward difference for time and central difference for the spatial derivative, we get: $$\frac{T_0^{n+1} - T_0^n}{\Delta t} = \alpha \frac{T_1^n - 2T_0^n + T_{-1}^n}{\Delta x^2} + q(x_0, t_n)$$ Now, we can substitute the convection, radiation, and heat flux boundary conditions for node 0 in the above equation: $$\frac{T_0^{n+1} - T_0^n}{\Delta t} = \alpha \frac{T_1^n - 2T_0^n + (T_0^n - \frac{\Delta x}{k}(h(T_0^n - T_{\infty}) + \varepsilon\sigma(T_0^n)^4 - \varepsilon\sigma T_\text{surr}^4 + \dot{q}_{0}))}{\Delta x^2} + q(x_0, t_n)$$ This explicit finite difference formulation can be used to calculate temperatures at node 0.
04

Determine the finite difference formulation for the total amount of heat transfer at the right boundary for the first 20 time steps

For the first 20 time steps, the total amount of heat transfer at node 4 can be calculated as follows: 1. Write down the explicit finite difference equation for node 4, similar to the one in step 3. 2. Calculate the temperature at each time step using this equation. 3. Calculate the heat transfer at the right boundary by taking the difference between node 4 and node 3. The result will give us the finite difference formulation for the total amount of heat transfer at the right boundary for the first 20 time steps.

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Most popular questions from this chapter

Consider transient heat conduction in a plane wall whose left surface (node 0 ) is maintained at \(80^{\circ} \mathrm{C}\) while the right surface (node 6) is subjected to a solar heat flux of \(600 \mathrm{~W} / \mathrm{m}^{2}\). The wall is initially at a uniform temperature of \(50^{\circ} \mathrm{C}\). Express the explicit finite difference formulation of the boundary nodes 0 and 6 for the case of no heat generation. Also, obtain the finite difference formulation for the total amount of heat transfer at the left boundary during the first three time steps.

Consider a uranium nuclear fuel element $(k=35 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\(, \)\rho=19,070 \mathrm{~kg} / \mathrm{m}^{3}\(, and \)\left.c_{p}=116 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\( of radius \)10 \mathrm{~cm}$ that experiences a volumetric heat generation at a rate of $4 \times 10^{5} \mathrm{~W} / \mathrm{m}^{3}$ because of the nuclear fission reaction. The nuclear fuel element initially at a temperature of \(500^{\circ} \mathrm{C}\) is enclosed inside a cladding made of stainless steel material $\left(k=15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=8055 \mathrm{~kg} / \mathrm{m}^{3}\right.\(, and \)\left.c_{p}=480 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\( of thickness \)4 \mathrm{~cm}$. The fuel element is cooled by passing pressurized heavy water over the cladding surface. The pressurized water has a bulk temperature of \(50^{\circ} \mathrm{C}\), and the convective heat transfer coefficient is $1000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. Assuming one-dimensional transient heat conduction in Cartesian coordinates, determine the temperature in the fuel rod and in the cladding after 10,20 , and \(30 \mathrm{~min}\). Use the implicit finite difference formulation with a uniform mesh size of \(2 \mathrm{~cm}\) and a time step of $1 \mathrm{~min}$.

A nonmetal plate is connected to a stainless steel plate by long ASTM A437 B4B stainless steel bolts \(9.5 \mathrm{~mm}\) in diameter. The portion of the bolts exposed to convection heat transfer with a cryogenic fluid is \(5 \mathrm{~cm}\) long. The fluid temperature for convection is at \(-50^{\circ} \mathrm{C}\) with a convection heat transfer coefficient of $100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. The thermal conductivity of the bolts is known to be \)23.9 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. Both the nonmetal and stainless steel plates maintain a uniform temperature of \(0^{\circ} \mathrm{C}\). According to the ASME Code for Process Piping (ASME B31.3-2014, Table A-2M), the minimum temperature suitable for ASTM A437 B4B stainless steel bolts is \(-30^{\circ} \mathrm{C}\). Using the finite difference method with a uniform nodal spacing of \(\Delta x=5 \mathrm{~mm}\) along the bolt, determine the temperature at each node. Compare the numerical results with the analytical solution. Plot the temperature distribution along the bolt. Would any part of the ASTM A437 B4B bolts be lower than the minimum suitable temperature of \(-30^{\circ} \mathrm{C}\) ?

A hot surface at \(120^{\circ} \mathrm{C}\) is to be cooled by attaching 8-cm- long, \(0.8-\mathrm{cm}\) - diameter aluminum pin fins ( $k=237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\( and \)\left.\alpha=97.1 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right)$ to it with a center-to-center distance of \(1.6 \mathrm{~cm}\). The temperature of the surrounding medium is $15^{\circ} \mathrm{C}\(, and the heat transfer coefficient on the surfaces is \)35 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. Initially, the fins are at a uniform temperature of \(30^{\circ} \mathrm{C}\), and at time \(t=0\), the temperature of the hot surface is raised to \(120^{\circ} \mathrm{C}\). Assuming one-dimensional heat conduction along the fin and taking the nodal spacing to be \(\Delta x=2 \mathrm{~cm}\) and a time step to be \(\Delta t=0.5 \mathrm{~s}\), determine the nodal temperatures after \(10 \mathrm{~min}\) by using the explicit finite difference method. Also, determine how long it will take for steady conditions to be reached.

What happens to the discretization and the roundoff errors as the step size is decreased?

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