Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Express the general stability criterion for the explicit method of solution of transient heat conduction problems.

Short Answer

Expert verified
Answer: The general stability criterion for the explicit method of solution for transient heat conduction problems is 0 < F ≤ 1/2, where F = (αδt)/(Δx)². F is the control variable, α is the thermal diffusivity of the material, δt is the time step, and Δx is the spatial step. The criterion determines the appropriate time and spatial steps for ensuring a stable and accurate solution.

Step by step solution

01

Understanding the Explicit Method for Transient Heat Conduction Problems

The explicit method calculates the solution for each time step based on the previous time step values. The general equation for the transient heat conduction in one dimension is given by the Fourier's heat equation: \[ \frac{\partial T(x,t)}{\partial t} = \alpha\frac{\partial^2 T(x,t)}{\partial x^2} \] Here, \(T(x,t)\) is the temperature at spatial position x and time t, and \(\alpha\) is the thermal diffusivity of the material. To solve this equation using the explicit method, a discretization scheme is adopted in both space and time. Let the spatial grid points be represented by \(x_i\) and the time grid points be represented by \(t_j\). Hence, the temperature at grid point i and time step j, \(T^{j}_i\), can be written as: \[T^{j+1}_{i} = T^j_i + \delta t\frac{\alpha(\Delta x)^2}{\delta x^2}(T^j_{i+1} - 2T^j_i + T^j_{i-1}) \]
02

Deriving the Stability Criterion

Stability criteria are used to determine if the explicit method will produce a stable and accurate solution for the transient heat conduction problem. The most commonly used stability criterion is the Von Neumann stability analysis. The Von Neumann stability analysis states that, if the amplification factor of the numerical method is less than or equal to 1, the method is stable: \[\left|\frac{T^{j+1}_i}{T^j_i}\right| \leq 1 \] Substitute the explicit method equation into the amplification factor expression: \[\left|\frac{T^j_i+\delta t\frac{\alpha(\Delta x)^2}{\delta x^2}(T^j_{i+1}-2T^j_i+T^j_{i-1})}{T^j_i}\right| \leq 1 \] Define the control variable \(F\) as: \[ F = \frac{\alpha\delta t}{(\Delta x)^2} \] Re-write the previous equation using the control variable F: \[\left|1 + F(T^j_{i+1}-2T^j_i+T^j_{i-1})\right| \leq 1 \]
03

Express the General Stability Criterion

For the explicit method of solution for transient heat conduction problems, its stability criterion will depend on the value of the control variable F. The general stability criterion can be expressed as: \[ 0 < F \leq \frac{1}{2} \] This means that for the explicit method to be stable and accurate, the value of F must be between 0 and 1/2. Otherwise, the method might result in inaccurate or unstable results. Remember that F is defined as: \[ F = \frac{\alpha\delta t}{(\Delta x)^2} \] The stability criterion is crucial in determining the appropriate time step, \(\delta t\), and spatial step, \(\Delta x\), for solving transient heat conduction problems using the explicit method.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What are the basic steps involved in solving a system of equations with the Gauss-Seidel method?

Starting with an energy balance on the volume element, obtain the two- dimensional transient explicit finite difference equation for a general interior node in rectangular coordinates for \(T(x, y, t)\) for the case of constant thermal conductivity and uniform heat generation.

How is the finite difference formulation for the first derivative related to the Taylor series expansion of the solution function?

A hot surface at \(100^{\circ} \mathrm{C}\) is to be cooled by attaching \(3-\mathrm{cm}-\) long, \(0.25-\mathrm{cm}\)-diameter aluminum pin fins $(k=237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})$ with a center-to-center distance of \(0.6 \mathrm{~cm}\). The temperature of the surrounding medium is \(30^{\circ} \mathrm{C}\), and the combined heat transfer coefficient on the surfaces is \(35 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Assuming steady one-dimensional heat transfer along the fin and taking the nodal spacing to be \(0.5 \mathrm{~cm}\), determine \((a)\) the finite difference formulation of this problem, \((b)\) the nodal temperatures along the fin by solving these equations, \((c)\) the rate of heat transfer from a single fin, and \((d)\) the rate of heat transfer from a \(1-\mathrm{m} \times 1-\mathrm{m}\) section of the plate.

Consider steady two-dimensional heat transfer in a long solid bar of square cross section in which heat is generated uniformly at a rate of $\dot{e}=0.19 \times 10^{5} \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{3}$. The cross section of the bar is \(0.5 \mathrm{ft} \times 0.5 \mathrm{ft}\) in size, and its thermal conductivity is $k=16 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft} \cdot{ }^{\circ} \mathrm{F}$. All four sides of the bar are subjected to convection with the ambient air at \(T_{\infty}=70^{\circ} \mathrm{F}\) with a heat transfer coefficient of $h=7.9 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{2}{ }^{\circ} \mathrm{F}$. Using the finite difference method with a mesh size of \(\Delta x=\Delta y=0.25 \mathrm{ft}\), determine \((a)\) the temperatures at the nine nodes and \((b)\) the rate of heat loss from the bar through a 1-ft-long section.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free