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Plasma spraying is a process used for coating a material surface with a protective layer to prevent the material from degradation. In a plasma spraying process, the protective layer in powder form is injected into a plasma jet. The powder is then heated to molten droplets and propelled onto the material surface. Once deposited on the material surface, the molten droplets solidify and form a layer of protective coating. Consider a plasma spraying process using alumina $(k=30 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\(, \)\rho=3970 \mathrm{~kg} / \mathrm{m}^{3}\(, and \)\left.c_{p}=800 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)$ powder that is injected into a plasma jet at \(T_{\infty}=15,000^{\circ} \mathrm{C}\) and $h=10,000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. The alumina powder is made of spherical particles with an average diameter of \(60 \mu \mathrm{m}\) and a melting point at \(2300^{\circ} \mathrm{C}\). Determine the amount of time it would take for the particles, with an initial temperature of $20^{\circ} \mathrm{C}$, to reach their melting point from the moment they are injected into the plasma jet.

Short Answer

Expert verified
Answer: It takes approximately 275 microseconds for the alumina particles to reach their melting point when injected into a plasma jet.

Step by step solution

01

Calculate the temperature difference

First, let's find the temperature difference between the initial temperature of the particle \(T_i\) and the melting point of the alumina \(T_m\): \(\Delta T = T_m - T_i\) Where, \(T_i = 20^{\circ}\mathrm{C}\) (initial temperature) \(T_m = 2300^{\circ}\mathrm{C}\) (melting point) \(\Delta T = 2300 - 20 = 2280\mathrm{~K}\)
02

Calculate the Biot number (Bi)

Biot number (Bi) is a dimensionless value that represents the ratio of internal thermal resistance to the convective heat transfer coefficient. Calculate Bi using the following formula: \(\text{Bi} = \frac{h L_c}{k}\) Where, \(h = 10,000 \mathrm{~W/m^2\cdot K}\) (convective heat transfer coefficient) \(L_c = \frac{d_p}{6}\) (characteristic length, d_p is the diameter of the particle) \(d_p = 60 \times 10^{-6} \mathrm{~m}\) (particle diameter) \(k = 30 \mathrm{~W/m\cdot K}\) (thermal conductivity of alumina) \(L_c = \frac{60 \times 10^{-6}}{6} = 10 \times 10^{-6}\mathrm{~m}\) \(\text{Bi} = \frac{10,000 \times 10 \times 10^{-6}}{30} = 0.003333\)
03

Calculate the Fourier number (Fo)

The Fourier number (Fo) is a dimensionless value that represents the ratio of the rate of heat conduction to the rate of heat energy storage. Calculate Fo using the following formula: \(\text{Fo} = \frac{\alpha t}{L_c^2}\) Where, \(\alpha = \frac{k}{\rho c_p}\) (thermal diffusivity) \(\rho = 3970 \mathrm{~kg/m^3}\) (density of alumina) \(c_p = 800 \mathrm{~J/kg\cdot K}\) (specific heat capacity of alumina) \(t\) is the time we want to find. \(\alpha = \frac{30}{3970 \times 800} = 9.424 \times 10^{-6} \mathrm{~m^2/s}\) Rewrite the equation for time: \(t = \frac{\text{Fo} L_c^2}{\alpha} \)
04

Determine the Fourier number (Fo) using the dominant thermal energy storage process assumption

Let's assume the convective heat transfer is dominant and the process can be analyzed in the regime of \(0.1 \leq \text{Bi} \leq 100\). It has been shown that \(\text{Bi} \leq 0.1\) corresponds to the situation when the temperature varies significantly along the way from the center to the surface of the sphere. In this case, the average temperature of the sphere can be evaluated as follows: \(\frac{T - T_i}{T_{\infty} - T_i} = 1 - e^{-3\text{Fo}}\) Plug in the values: \(\frac{2280}{14,980} = 1 - e^{-3\text{Fo}}\) Solve for Fo: \(\text{Fo} = -\frac{1}{3} \ln (1 - \frac{2280}{14,980}) = 0.245\)
05

Calculate time required for the particles to reach their melting point

Now, use the Fo value found in step 4 and substitute it into the equation found in step 3 to find the time it takes for the particles to reach their melting point: \(t = \frac{0.245 \times (10 \times 10^{-6})^2}{9.424 \times 10^{-6}}\) \(t = 0.000275\mathrm{~s}\) So, it would take approximately \(0.000275\mathrm{~s}\) or about \(275\mathrm{~\mu s}\) for the alumina particles to reach their melting point from the moment they are injected into the plasma jet.

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Most popular questions from this chapter

What is an infinitely long cylinder? When is it proper to treat an actual cylinder as being infinitely long, and when is it not? For example, is it proper to use this model when finding the temperatures near the bottom or top surfaces of a cylinder? Explain.

How does refrigeration prevent or delay the spoilage of foods? Why does freezing extend the storage life of foods for months?

In a production facility, 3-cm-thick large brass plates $\left(k=110 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=8530 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=380 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right.$, and \(\alpha=33.9 \times\) \(10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) ) that are initially at a uniform temperature of \(25^{\circ} \mathrm{C}\) are heated by passing them through an oven maintained at \(700^{\circ} \mathrm{C}\). The plates remain in the oven for a period of \(10 \mathrm{~min}\). Taking the convection heat transfer coefficient to be $h=80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, determine the surface temperature of the plates when they come out of the oven. Solve this problem using the analytical one-term approximation method. Can this problem be solved using lumped system analysis? Justify your answer.

A semi-infinite aluminum cylinder $(k=237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\(, \)\alpha=9.71 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}$ ) of diameter \(D=15 \mathrm{~cm}\) is initially at a uniform temperature of \(T_{i}=115^{\circ} \mathrm{C}\). The cylinder is now placed in water at \(10^{\circ} \mathrm{C}\), where heat transfer takes place by convection with a heat transfer coefficient of $h=140 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. Determine the temperature at the center of the cylinder \)5 \mathrm{~cm}$ from the end surface 8 min after the start of cooling. Solve this problem using the analytical one-term approximation method.

A \(10-\mathrm{cm}\)-thick aluminum plate $\left(\alpha=97.1 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right)$ is being heated in liquid with temperature of \(500^{\circ} \mathrm{C}\). The aluminum plate has a uniform initial temperature of \(25^{\circ} \mathrm{C}\). If the surface temperature of the aluminum plate is approximately the liquid temperature, determine the temperature at the center plane of the aluminum plate after 15 s of heating. Solve this problem using the analytical one-term approximation method.

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