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A man is found dead in a room at \(12^{\circ} \mathrm{C}\). The surface temperature on his waist is measured to be \(23^{\circ} \mathrm{C}\), and the heat transfer coefficient is estimated to be $9 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. Modeling the body as a \)28-\mathrm{cm}$ diameter, \(1.80\)-m-long cylinder, estimate how long it has been since he died. Take the properties of the body to be $k=0.62 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\( and \)\alpha=0.15 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}$, and assume the initial temperature of the body to be \(36^{\circ} \mathrm{C}\). Solve this problem using the analytical one-term approximation method.

Short Answer

Expert verified
Answer: It has been approximately 6.45 hours since the man's death.

Step by step solution

01

Calculate the Biot number (Bi)

The Biot number (Bi) is a dimensionless number that represents the ratio of heat transfer resistance within the body to the heat transfer resistance between the body's surface and surrounding environment. Formula for Biot number (Bi): \(Bi = hL_c/k\) Where: \(h = 9 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (Heat transfer coefficient) \(L_c = (V/A_s) = (28\,\mathrm{cm})/2 = 14\,\mathrm{cm} = 0.14\) m (Characteristic length - the ratio of volume to surface area) \(k = 0.62 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) (Thermal conductivity of the body) Computing the Biot number: \(Bi = \frac{9 \times 0.14}{0.62} = 2.03\)
02

Calculate the time constant (τ)

Time constant (τ) is a parameter that characterizes the time response of a system to various stimuli. For this problem, it is given by: Formula for time constant (τ): \(τ = L_c^2/α\) Where: \(L_c = 0.14\) m (Characteristic length) \(α = 0.15 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) (Thermal diffusivity of the body) Computing the time constant: \(τ = \frac{(0.14)^2}{0.15 \times 10^{-6}} = 130933.33\, \mathrm{s}\)
03

Calculate the Fourier number (Fo)

Use the temperature formula for a cylinder to calculate the Fourier number (Fo). Formula for Fourier number (Fo): \(Fo = τ/Bi\) Where: \(τ = 130933.33\, \mathrm{s}\) (Time constant) \(Bi = 2.03\) (Biot number) Computing the Fourier number: \(Fo = \frac{130933.33}{2.03} = 64468.47\)
04

Calculate the dimensionless temperature (Θ)

We'll use the dimensionless temperature formula for a cylinder in conjunction with the one-term approximation method to determine the time it has been since the man's death. Formula for dimensionless temperature (Θ): \(Θ = \frac{T - T_\infty}{T_i - T_\infty}\) Where: \(T = 23^{\circ} \mathrm{C}\) (Surface temperature on his waist) \(T_\infty = 12^{\circ} \mathrm{C}\) (Room temperature) \(T_i = 36^{\circ} \mathrm{C}\) (Initial temperature of the body) Computing dimensionless temperature: \(Θ = \frac{23 - 12}{36 - 12} = \frac{11}{24} = 0.4583\)
05

Estimate the time (t) using one-term approximation

Using the one-term approximation method, we can write the following equation: \(Θ = e^{-Bi \cdot t/Fo}\) Substituting the values we obtained for Θ, Bi, and Fo: \(0.4583 = e^{-2.03 \cdot t/64468.47}\) Now, solve for t: \(t = \frac{-\ln(0.4583) \times 64468.47}{2.03} = 23207.62\, \mathrm{s}\) Now, convert the time to hours: \(t = \frac{23207.62}{3600} = 6.446\, \mathrm{hours}\) The estimated time since the man's death is approximately 6.45 hours.

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Most popular questions from this chapter

How does \((a)\) the air motion and \((b)\) the relative humidity of the environment affect the growth of microorganisms in foods?

Carbon steel balls $\left(\rho=7833 \mathrm{~kg} / \mathrm{m}^{3}, k=54 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\right.\(, \)c_{p}=0.465 \mathrm{~kJ} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}\(, and \)\left.\alpha=1.474 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right) 8 \mathrm{~mm}$ in diameter are annealed by heating them first to \(900^{\circ} \mathrm{C}\) in a furnace and then allowing them to cool slowly to \(100^{\circ} \mathrm{C}\) in ambient air at \(35^{\circ} \mathrm{C}\). If the average heat transfer coefficient is $75 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, determine how long the annealing process will take. If 2500 balls are to be annealed per hour, determine the total rate of heat transfer from the balls to the ambient air.

The walls of a furnace are made of \(1.5\)-ft-thick concrete $\left(k=0.64 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft} \cdot{ }^{\circ} \mathrm{F}\right.\( and \)\left.\alpha=0.023 \mathrm{ft}^{2} / \mathrm{h}\right)$. Initially, the furnace and the surrounding air are in thermal equilibrium at \(70^{\circ} \mathrm{F}\). The furnace is then fired, and the inner surfaces of the furnace are subjected to hot gases at $1800^{\circ} \mathrm{F}$ with a very large heat transfer coefficient. Determine how long it will take for the temperature of the outer surface of the furnace walls to rise to \(70.1^{\circ} \mathrm{F}\). Answer: \(3.0 \mathrm{~h}\)

In areas where the air temperature remains below \(0^{\circ} \mathrm{C}\) for prolonged periods of time, the freezing of water in underground pipes is a major concern. Fortunately, the soil remains relatively warm during those periods, and it takes weeks for the subfreezing temperatures to reach the water mains in the ground. Thus, the soil effectively serves as an insulation to protect the water from the freezing atmospheric temperatures in winter. The ground at a particular location is covered with snowpack at $-8^{\circ} \mathrm{C}$ for a continuous period of 60 days, and the average soil properties at that location are $k=0.35 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\( and \)\alpha=0.15 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}$. Assuming an initial uniform temperature of \(8^{\circ} \mathrm{C}\) for the ground, determine the minimum burial depth to prevent the water pipes from freezing.

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