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How does refrigeration prevent or delay the spoilage of foods? Why does freezing extend the storage life of foods for months?

Short Answer

Expert verified
Answer: Refrigeration and freezing help preserve food by slowing down or stopping the growth of microorganisms, enzyme activity, and chemical reactions that cause spoilage. Refrigeration reduces temperature and slows microbial growth and biochemical activities, while freezing stops most microbial growth by turning water into ice, depriving microorganisms of the water they need for growth. Freezing is more efficient for long-term storage, while refrigeration is suitable for short-term storage or for preserving delicate foods.

Step by step solution

01

Understand the factors contributing to food spoilage

Food spoilage mainly occurs due to the growth of microorganisms like bacteria, yeast, and molds. These microorganisms use food as their nutrient source, breaking down proteins, carbohydrates, and fats in the process. This not only makes the food unfit for consumption but may also result in the production of harmful substances like toxins. Moreover, certain chemical reactions and enzymatic activities within the food also contribute to spoilage.
02

Describe the role of refrigeration in preventing food spoilage

Refrigeration slows down the spoilage process by reducing the temperature at which the food is stored. Lowering temperature decreases the rate of growth, reproduction, and biochemical activities of microorganisms, thereby slowing down the food degradation process. Furthermore, at lower temperatures, the key enzymes responsible for various food spoilage reactions are less active, reducing the rate of chemical and enzymatic reactions in the food.
03

Explain how freezing extends storage life of foods

Freezing is a more effective method of preserving food because it halts the growth and multiplication of most microorganisms. It does so by turning the water inside the food into ice, which deprives microorganisms of the water they need for growth and metabolic activities. Moreover, freezing slows down enzyme activity and chemical reactions within the food, helping to maintain its freshness, taste, and nutritional content for longer periods.
04

Compare refrigeration and freezing in terms of food preservation

While both refrigeration and freezing help prevent food spoilage, freezing is a more efficient method for long-term storage. Refrigeration only slows down microbial growth, enzyme activity, and chemical reactions, whereas freezing stops or severely reduces these processes, thus significantly extending shelf life. However, some food items may lose their texture and quality due to ice crystal formation during freezing, so refrigeration may be more appropriate for short-term storage or preservation of delicate foods.

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Most popular questions from this chapter

A 40 -cm-thick brick wall \((k=0.72 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and \(\alpha=1.6 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) ) is heated to an average temperature of \(18^{\circ} \mathrm{C}\) by the heating system and the solar radiation incident on it during the day. During the night, the outer surface of the wall is exposed to cold air at \(-3^{\circ} \mathrm{C}\) with an average heat transfer coefficient of $20 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. Determine the wall temperatures at distances 15,30 , and \)40 \mathrm{~cm}\( from the outer surface for a period of \)2 \mathrm{~h}$.

Chickens with an average mass of \(2.2 \mathrm{~kg}\) and average specific heat of \(3.54 \mathrm{~kJ} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}\) are to be cooled by chilled water that enters a continuous-flow-type immersion chiller at \(0.5^{\circ} \mathrm{C}\). Chickens are dropped into the chiller at a uniform temperature of \(15^{\circ} \mathrm{C}\) at a rate of 500 chickens per hour and are cooled to an average temperature of \(3^{\circ} \mathrm{C}\) before they are taken out. The chiller gains heat from the surroundings at a rate of \(210 \mathrm{~kJ} / \mathrm{min}\). Determine \((a)\) the rate of heat removal from the chicken, in \(\mathrm{kW}\), and ( \(b\) ) the mass flow rate of water, in \(\mathrm{kg} / \mathrm{s}\), if the temperature rise of water is not to exceed \(2^{\circ} \mathrm{C}\).

Citrus trees are very susceptible to cold weather, and extended exposure to subfreezing temperatures can destroy the crop. In order to protect the trees from occasional cold fronts with subfreezing temperatures, tree growers in Florida usually install water sprinklers on the trees. When the temperature drops below a certain level, the sprinklers spray water on the trees and their fruits to protect them against the damage the subfreezing temperatures can cause. Explain the basic mechanism behind this protection measure, and write an essay on how the system works in practice.

In an experiment, the temperature of a hot gas stream is to be measured by a thermocouple with a spherical junction. Due to the nature of this experiment, the response time of the thermocouple to register 99 percent of the initial temperature difference must be within \(5 \mathrm{~s}\). The properties of the thermocouple junction are $k=35 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=8500 \mathrm{~kg} / \mathrm{m}^{3}\(, and \)c_{p}=320 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}$. If the heat transfer coefficient between the thermocouple junction and the gas is $250 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, determine the diameter of the junction.

Consider a 7.6-cm-diameter cylindrical lamb meat chunk $\left(\rho=1030 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=3.49 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}, k=0.456 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\right.$, \(\alpha=1.3 \times 10^{-7} \mathrm{~m}^{2} / \mathrm{s}\) ). Such a meat chunk intially at \(2^{\circ} \mathrm{C}\) is dropped into boiling water at \(95^{\circ} \mathrm{C}\) with a heat transfer coefficient of $1200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. The time it takes for the center temperature of the meat chunk to rise to \(75^{\circ} \mathrm{C}\) is (a) \(136 \mathrm{~min}\) (b) \(21.2 \mathrm{~min}\) (c) \(13.6 \mathrm{~min}\) (d) \(11.0 \mathrm{~min}\) (e) \(8.5 \mathrm{~min}\)

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