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Can the thermal resistance concept be used for a solid cylinder or sphere in steady operation? Explain.

Short Answer

Expert verified
Answer: Yes, the concept of thermal resistance can be utilized for solid cylinders and spheres in steady operation. The governing equations for both geometries can be expressed in terms of thermal resistance, which is useful for analyzing heat transfer in such systems.

Step by step solution

01

Understand the concept of thermal resistance

Thermal resistance is a parameter that describes the resistance to heat flow across a material or between two surfaces in contact. It is the reciprocal of thermal conductivity, which is a property of a substance that indicates its ability to transfer heat. Mathematically, thermal resistance (R) can be expressed as: R = \frac{L}{kA} Where L is the thickness of the material, k is the thermal conductivity, and A is the surface area for heat transfer.
02

Consider steady-state conditions

Steady-state conditions refer to situations where the temperature distribution within a system does not change with time. For a solid cylinder or sphere, thermal energy flows radially (outwards or inwards) under steady-state conditions, and the temperature distribution remains constant over time.
03

Apply thermal resistance concept to solid cylinders

For a solid cylinder, the radial heat flow can be described using the thermal resistance concept. The governing equation for cylindrical coordinates is: q = \frac{2 \pi kL (\Delta T)}{ln(r2/r1)} Where q represents the heat flow (in watts), ∆T is the temperature difference between the inner and outer surfaces, r2 > r1, and L is the length of the cylinder. The thermal resistance (R_cylinder) can be written as: R_cylinder = \frac{ln(r2/r1)}{2 \pi kL} Thus, the thermal resistance concept can be utilized for a solid cylinder in steady operation since the governing equation can be expressed in terms of the resistance.
04

Apply the thermal resistance concept to solid spheres

Similarly, the radial heat flow in a solid sphere can be described using the thermal resistance concept. The governing equation for spherical coordinates is: q = \frac{4 \pi kR (\Delta T)}{(r2^3-r1^3)/(r2-r1)} Where R is the average sphere radius, r2 > r1, ∆T is the temperature difference between the inner and outer surfaces, and q represents the heat flow (in watts). The thermal resistance (R_sphere) can be written as: R_sphere = \frac{(r2^3-r1^3)/(r2-r1)}{4 \pi kR} This equation shows that the concept of thermal resistance can also be applied to spheres in steady-state operation.
05

Conclusion

In conclusion, the thermal resistance concept is applicable to solid cylinders and spheres in steady-state operation. The governing equations for both geometries can be expressed in terms of thermal resistance, signifying that this approach is useful for analyzing heat transfer in such systems.

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Most popular questions from this chapter

A total of 10 rectangular aluminum fins $(k=203 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})$ are placed on the outside flat surface of an electronic device. Each fin is \(100 \mathrm{~mm}\) wide, \(20 \mathrm{~mm}\) high, and $4 \mathrm{~mm}$ thick. The fins are located parallel to each other at a center- to-center distance of \(8 \mathrm{~mm}\). The temperature at the outside surface of the electronic device is \(72^{\circ} \mathrm{C}\). The air is at $20^{\circ} \mathrm{C}\(, and the heat transfer coefficient is \)80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. Determine \)(a)$ the rate of heat loss from the electronic device to the surrounding air and \((b)\) the fin effectiveness.

Hot water at an average temperature of \(90^{\circ} \mathrm{C}\) passes through a row of eight parallel pipes that are \(4 \mathrm{~m}\) long and have an outer diameter of \(3 \mathrm{~cm}\), located vertically in the middle of a concrete wall \((k=0.75 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) that is $4 \mathrm{~m}\( high, \)8 \mathrm{~m}\( long, and \)15 \mathrm{~cm}$ thick. If the surfaces of the concrete walls are exposed to a medium at $32^{\circ} \mathrm{C}\(, with a heat transfer coefficient of \)12 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, determine the rate of heat loss from the hot water and the surface temperature of the wall.

Circular cooling fins of diameter \(D=1 \mathrm{~mm}\) and length $L=30 \mathrm{~mm}\(, made of copper \)(k=380 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})$, are used to enhance heat transfer from a surface that is maintained at temperature \(T_{s 1}=132^{\circ} \mathrm{C}\). Each rod has one end attached to this surface \((x=0)\), while the opposite end \((x=L)\) is joined to a second surface, which is maintained at \(T_{s 2}=0^{\circ} \mathrm{C}\). The air flowing between the surfaces and the rods is also at \(T_{\infty}=0^{\circ} \mathrm{C}\). and the convection coefficient is $h=100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. (a) Express the function \(\theta(x)=T(x)-T_{\infty}\) along a fin, and calculate the temperature at \(x=L / 2\). (b) Determine the rate of heat transferred from the hot surface through each fin and the fin effectiveness. Is the use of fins justified? Why? (c) What is the total rate of heat transfer from a \(10-\mathrm{cm}\) by \(10-\mathrm{cm}\) section of the wall, which has 625 uniformly distributed fins? Assume the same convection coefficient for the fin and for the unfinned wall surface.

Circular fins of uniform cross section, with diameter of \(10 \mathrm{~mm}\) and length of \(50 \mathrm{~mm}\), are attached to a wall with surface temperature of \(350^{\circ} \mathrm{C}\). The fins are made of material with thermal conductivity of \(240 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), they are exposed to an ambient air condition of \(25^{\circ} \mathrm{C}\), and the convection heat transfer coefficient is $250 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. Determine the heat transfer rate and plot the temperature variation of a single fin for the following boundary conditions: (a) Infinitely long fin (b) Adiabatic fin tip (c) Fin with tip temperature of \(250^{\circ} \mathrm{C}\) (d) Convection from the fin tip

A row of 10 parallel pipes that are \(5 \mathrm{~m}\) long and have an outer diameter of \(6 \mathrm{~cm}\) are used to transport steam at $145^{\circ} \mathrm{C}\( through the concrete floor \)(k=0.75 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\( of a \)10-\mathrm{m} \times 5-\mathrm{m}$ room that is maintained at \(24^{\circ} \mathrm{C}\). The combined convection and radiation heat transfer coefficient at the floor is $12 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. If the surface temperature of the concrete floor is not to exceed \(38^{\circ} \mathrm{C}\), determine how deep the steam pipes should be buried below the surface of the concrete floor.

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