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How is the combined heat transfer coefficient defined? What convenience does it offer in heat transfer calculations?

Short Answer

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Answer: The combined heat transfer coefficient, denoted as $$h_c$$, is the overall or effective heat transfer coefficient that accounts for conduction, convection, and radiation in heat transfer through multiple layers or media. It simplifies calculations involving multiple modes of heat transfer and different layers of materials, making it easier to solve problems, compare materials, and apply solutions in various heat transfer situations.

Step by step solution

01

Definition of Combined Heat Transfer Coefficient

The combined heat transfer coefficient, denoted as $$h_c$$, is defined as the overall or effective heat transfer coefficient that accounts for conduction, convection, and radiation. It is used when dealing with heat transfer through multiple layers or media, and allows for a simplified analysis of the heat transfer process. It is typically expressed in units of W/m^2K.
02

Calculating the Combined Heat Transfer Coefficient

To calculate the combined heat transfer coefficient, you first need to consider the individual heat transfer coefficients for each mode of heat transfer (conduction, convection, and radiation) and the different layers involved. Mathematically, the combined heat transfer coefficient ($$h_c$$) can be found using the following formula: $$\frac{1}{h_c} = \frac{1}{h_1} + \frac{\Delta x}{k_1} + \frac{1}{h_2} + \frac{\Delta x}{k_2} + \dots $$ Here, $$h_1$$ and $$h_2$$ are the convective heat transfer coefficients, $$\Delta x$$ is the thickness of each layer of the material, and $$k_1$$ and $$k_2$$ are the thermal conductivities of the materials in the different layers.
03

Convenience of Combined Heat Transfer Coefficient

The combined heat transfer coefficient offers several conveniences in heat transfer calculations, including: 1. Simplification: By using a single, combined coefficient, the complexity of calculations involving multiple layers or modes of heat transfer can be reduced. 2. Applicability: The combined heat transfer coefficient can be used in various heat transfer problems, such as flat plates, cylinders, and spheres, making it a versatile tool in solving various engineering problems. 3. Comparison: Having an overall heat transfer coefficient allows for straightforward comparisons of various insulation materials or techniques in terms of their effectiveness. In summary, the combined heat transfer coefficient is an essential concept in heat transfer that simplifies calculations involving multiple modes of heat transfer and different layers of materials. It provides conveniences in solving problems, comparing materials, and applying the solutions to a range of heat transfer situations.

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Most popular questions from this chapter

A row of 10 parallel pipes that are \(5 \mathrm{~m}\) long and have an outer diameter of \(6 \mathrm{~cm}\) are used to transport steam at $145^{\circ} \mathrm{C}\( through the concrete floor \)(k=0.75 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\( of a \)10-\mathrm{m} \times 5-\mathrm{m}$ room that is maintained at \(24^{\circ} \mathrm{C}\). The combined convection and radiation heat transfer coefficient at the floor is $12 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. If the surface temperature of the concrete floor is not to exceed \(38^{\circ} \mathrm{C}\), determine how deep the steam pipes should be buried below the surface of the concrete floor.

Someone comments that a microwave oven can be viewed as a conventional oven with zero convection resistance at the surface of the food. Is this an accurate statement?

A 12 -m-long and 8-cm-diameter hot-water pipe of a district heating system is buried in the soil \(80 \mathrm{~cm}\) below the ground surface. The outer surface temperature of the pipe is \(60^{\circ} \mathrm{C}\). Taking the surface temperature of the earth to be \(2^{\circ} \mathrm{C}\) and the thermal conductivity of the soil at that location to be $0.9 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$, determine the rate of heat loss from the pipe.

Using a timer (or watch) and a thermometer, conduct this experiment to determine the rate of heat gain of your refrigerator. First, make sure that the door of the refrigerator is not opened for at least a few hours to make sure that steady operating conditions are established. Start the timer when the refrigerator stops running, and measure the time \(\Delta t_{1}\) it stays off before it kicks in. Then measure the time \(\Delta t_{2}\) it stays on. Noting that the heat removed during \(\Delta t_{2}\) is equal to the heat gain of the refrigerator during \(\Delta t_{1}+\Delta t_{2}\) and using the power consumed by the refrigerator when it is running, determine the average rate of heat gain for your refrigerator, in watts. Take the COP (coefficient of performance) of your refrigerator to be \(1.3\) if it is not available. Now, clean the condenser coils of the refrigerator and remove any obstacles in the way of airflow through the coils. Then determine the improvement in the COP of the refrigerator.

A pipe is insulated such that the outer radius of the insulation is less than the critical radius. Now the insulation is taken off. Will the rate of heat transfer from the pipe increase or decrease for the same pipe surface temperature?

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