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Can we define the convection resistance for a unit surface area as the inverse of the convection heat transfer coefficient?

Short Answer

Expert verified
Answer: Yes, the convection resistance for a unit surface area can be defined as the inverse of the convection heat transfer coefficient. This relationship is mathematically expressed as R_c = 1/h, where R_c represents convection resistance and h represents the convection heat transfer coefficient.

Step by step solution

01

Understand Convection Heat Transfer

Convection heat transfer occurs when a fluid (liquid or gas) moves over a solid surface, carrying heat away or towards the surface. The fluid heats up (or cools down) by direct contact with the surface and transfers the heat to (or from) the surroundings.
02

Define the Convection Heat Transfer Coefficient

The convection heat transfer coefficient (h) is a measure of the effectiveness of heat transfer through convection. It is usually expressed in W/(m^2 K), which represents the heat transfer rate (in watts) for a unit surface area (in square meters) per unit temperature difference between the surface and the fluid (in kelvins). In other words, the higher the value of h, the more effective the convection heat transfer process is.
03

Define Convection Resistance

Convection resistance is a measure of how much resistance there is against heat transfer by convection. It is the thermal resistance due to the presence of a fluid surrounding a solid surface. Just like electrical resistance, thermal resistance can be seen as an opposition to heat flow; when there is more resistance, there will be less heat transfer.
04

Relationship between Convection Heat Transfer Coefficient and Convection Resistance

Convection resistance (R_c) can be defined as the inverse of the product of the convection heat transfer coefficient (h) and the surface area (A). Mathematically, R_c = \dfrac{1}{hA} For a unit surface area, as mentioned in the exercise, the surface area (A) will be equal to 1 m^2. Therefore, the convection resistance for a unit surface area can be written as: R_c = \dfrac{1}{h}
05

Conclusion

Yes, we can define the convection resistance for a unit surface area as the inverse of the convection heat transfer coefficient. This is mathematically demonstrated as R_c = \dfrac{1}{h}, where R_c is the convection resistance and h is the convection heat transfer coefficient.

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Most popular questions from this chapter

Consider a \(1.5-\mathrm{m}\)-high and 2 -m-wide triple pane window. The thickness of each glass layer $(k=0.80 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\( is \)0.5 \mathrm{~cm}$, and the thickness of each airspace \((k=0.025 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is \(1.2 \mathrm{~cm}\). If the inner and outer surface temperatures of the window are $10^{\circ} \mathrm{C}\( and \)0^{\circ} \mathrm{C}$, respectively, the rate of heat loss through the window is (a) \(3.4 \mathrm{~W}\) (b) \(10.2 \mathrm{~W}\) (c) \(30.7 \mathrm{~W}\) (d) \(61.7 \mathrm{~W}\) (e) \(86.8 \mathrm{~W}\)

A cylindrical pin fin of diameter \(0.6 \mathrm{~cm}\) and length of $3 \mathrm{~cm}$ with negligible heat loss from the tip has an efficiency of 0.7. The effectiveness of this fin is (a) \(0.3\) (b) \(0.7\) (c) 2 (d) 8 (e) 14

The heat transfer surface area of a fin is equal to the sum of all surfaces of the fin exposed to the surrounding medium, including the surface area of the fin tip. Under what conditions can we neglect heat transfer from the fin tip?

A 2.2-mm-diameter and 14-m-long electric wire is tightly wrapped with a \(1-\mathrm{mm}\)-thick plastic cover whose thermal conductivity is $k=0.15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. Electrical measurements indicate that a current of \(13 \mathrm{~A}\) passes through the wire, and there is a voltage drop of \(8 \mathrm{~V}\) along the wire. If the insulated wire is exposed to a medium at \(T_{\infty}=30^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(h=24 \mathrm{~W} / \mathrm{m}^{2}\), \(\mathrm{K}\), determine the temperature at the interface of the wire and the plastic cover in steady operation. Also determine if doubling the thickness of the plastic cover will increase or decrease this interface temperature.

An 8-m-internal-diameter spherical tank made of \(1.5\)-cm-thick stainless steel \((k=15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is used to store iced water at \(0^{\circ} \mathrm{C}\). The tank is located in a room whose temperature is \(25^{\circ} \mathrm{C}\). The walls of the room are also at $25^{\circ} \mathrm{C}$. The outer surface of the tank is black (emissivity \(\varepsilon=1\) ), and heat transfer between the outer surface of the tank and the surroundings is by natural convection and radiation. The convection heat transfer coefficients at the inner and the outer surfaces of the tank are $80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\( and \)10 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(, respectively. Determine \)(a)$ the rate of heat transfer to the iced water in the tank and \((b)\) the amount of ice at \(0^{\circ} \mathrm{C}\) that melts during a 24 -h period. The heat of fusion of water at atmospheric pressure is \(h_{i f}=333.7 \mathrm{~kJ} / \mathrm{kg}\).

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