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What does the thermal resistance of a medium represent?

Short Answer

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Answer: Thermal resistance is a property of a material that quantifies its resistance to the flow of heat through it, specifically by thermal conduction. It is essential in understanding thermal conduction because it helps engineers and designers make informed decisions about materials usage for efficient thermal management systems, such as insulation materials, building design, and electronic devices.

Step by step solution

01

Concept of Thermal Resistance

Thermal resistance is a property of a material that quantifies its resistance to the flow of heat. Heat is transferred through a medium via conduction, convection, or radiation. In the context of a medium, thermal resistance represents how effectively the medium resists the transfer of heat through it by thermal conduction.
02

Importance of Thermal Resistance

The importance of understanding thermal resistance lies in its applications, such as in insulation materials, building design, and electronic devices. By knowing a medium's thermal resistance, engineers and designers can make informed decisions about materials to use for designing efficient thermal management systems. High thermal resistance materials are favored for insulation, while low thermal resistance materials are favored for applications where it's essential to dissipate heat efficiently.
03

Calculation of Thermal Resistance

Thermal resistance (\(R_{th}\)) can be calculated using the formula: \[R_{th} = \frac{L}{kA}\] where \(L\) represents the thickness of the medium, \(k\) is the thermal conductivity of the material, and \(A\) is the cross-sectional area through which the heat is flowing. A higher value of thermal resistance indicates a more significant resistance to heat transfer, while a lower value indicates a more efficient heat transfer.

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Most popular questions from this chapter

In the United States, building insulation is specified by the \(R\)-value (thermal resistance in $\mathrm{h} \cdot \mathrm{ft}^{2}+{ }^{\circ} \mathrm{F} /$ Btu units). A homeowner decides to save on the cost of heating the home by adding additional insulation in the attic. If the total \(R\)-value is increased from 15 to 25 , the homeowner can expect the heat loss through the ceiling to be reduced by (a) \(25 \%\) (b) \(40 \%\) (c) \(50 \%\) (d) \(60 \%\) (e) \(75 \%\)

Consider a tube for transporting steam that is not centered properly in a cylindrical insulation material \((k=0.73\) $\mathrm{W} / \mathrm{m} \cdot \mathrm{K})\(. The tube diameter is \)D_{1}=20 \mathrm{~cm}$ and the insulation diameter is \(D_{2}=40 \mathrm{~cm}\). The distance between the center of the tube and the center of the insulation is \(z=5 \mathrm{~mm}\). If the surface of the tube maintains a temperature of \(100^{\circ} \mathrm{C}\) and the outer surface temperature of the insulation is constant at \(30^{\circ} \mathrm{C}\),

Consider a pipe at a constant temperature whose radius is greater than the critical radius of insulation. Someone claims that the rate of heat loss from the pipe has increased when some insulation is added to the pipe. Is this claim valid?

A hot surface at \(100^{\circ} \mathrm{C}\) is to be cooled by attaching 3 -cm- long, \(0.25\)-cm-diameter aluminum pin fins \((k=237\) $\mathrm{W} / \mathrm{m} \cdot \mathrm{K})\( to it, with a center-to-center distance of \)0.6 \mathrm{~cm}\(. The temperature of the surrounding medium is \)30^{\circ} \mathrm{C}\(, and the heat transfer coefficient on the surfaces is \)35 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. Determine the rate of heat transfer from the surface for a \(1-\mathrm{m} \times 1-\mathrm{m}\) section of the plate. Also determine the overall effectiveness of the fins.

A plane brick wall \((k=0.7 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is $10 \mathrm{~cm}$ thick. The thermal resistance of this wall per unit of wall area is (a) \(0.143 \mathrm{~m}^{2}, \mathrm{~K} / \mathrm{W}\) (b) \(0.250 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\) (c) \(0.327 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\) (d) \(0.448 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\) (e) \(0.524 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\)

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