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What is a conduction shape factor? How is it related to the thermal resistance?

Short Answer

Expert verified
Answer: The conduction shape factor (S) is a dimensionless quantity used in heat conduction problems to characterize the geometry of a system and compare its efficiency of heat conduction to a simple, reference geometry. It is related to thermal resistance (R) through the equation R = 1/(kS), where k is the thermal conductivity of the material. The lower the thermal resistance, the more quickly heat flows through the material.

Step by step solution

01

Definition of Conduction Shape Factor

The conduction shape factor, commonly denoted as S, is a dimensionless quantity used in heat conduction problems, specifically in systems where a three-dimensional heat transfer is reduced to a one-dimensional problem. It's a way to compare the actual complex geometry of a system to a simple, reference geometry and gives an indication of the efficiency of heat conduction for a given system.
02

Relation to Thermal Resistance

The thermal resistance (R) for conductive heat transfer in a system is the inverse of the conduction shape factor multiplied by the conductivity (k) of the material. Mathematically, this is represented as: R = \frac{1}{kS} Where: - R is the thermal resistance (K/W or °C/W) - k is the thermal conductivity of the material (W/mK) - S is the conduction shape factor The lower the thermal resistance, the more quickly heat flows through the material, which is generally desired to improve heat transfer efficiency.
03

Example Calculation

Let's consider a simple example to understand these concepts better. Suppose we have a wall made of brick with uniform thickness, and we want to compute its conduction shape factor and thermal resistance. Given: - Brick Thermal Conductivity k = 0.72 W/mK - Dimensions of the wall: 10 m x 10 m (height x width) - Thickness of the wall: 0.2 m Step 1: Compute the area (A) of the wall: A = height x width = 10 m x 10 m = 100 m^2 Step 2: Compute the conduction shape factor (S): For a simple plane wall of uniform thickness, the conduction shape factor is calculated using the equation: S = \frac{A}{L} Where L is the thickness of the wall. S = \frac{100 m^2}{0.2 m} = 500 Step 3: Compute the thermal resistance (R): Now, using the previously mentioned formula (R = \frac{1}{kS}), we calculate the thermal resistance: R = \frac{1}{(0.72 W/mK)(500)} = \frac{1}{360} K/W ≈ 0.00278 K/W Therefore, the conduction shape factor for the brick wall is 500 and the thermal resistance is approximately 0.00278 K/W. This information can be used to analyze the heat transfer properties of the wall and to design energy-efficient building systems.

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Most popular questions from this chapter

Steam at \(280^{\circ} \mathrm{C}\) flows in a stainless steel pipe $(k=15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})$ whose inner and outer diameters are \(5 \mathrm{~cm}\) and \(5.5 \mathrm{~cm}\), respectively. The pipe is covered with \(3-\mathrm{cm}\)-thick glass wool insulation $(k=0.038 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\(. Heat is lost to the surroundings at \)5^{\circ} \mathrm{C}$ by natural convection and radiation, with a combined natural convection and radiation heat transfer coefficient of $22 \mathrm{~W} / \mathrm{m}^{2}$. . Taking the heat transfer coefficient inside the pipe to be \(80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), determine the rate of heat loss from the steam per unit length of the pipe. Also determine the temperature drops across the pipe shell and the insulation.

A plane brick wall \((k=0.7 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is $10 \mathrm{~cm}$ thick. The thermal resistance of this wall per unit of wall area is (a) \(0.143 \mathrm{~m}^{2}, \mathrm{~K} / \mathrm{W}\) (b) \(0.250 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\) (c) \(0.327 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\) (d) \(0.448 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\) (e) \(0.524 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\)

Consider a very long rectangular fin attached to a flat surface such that the temperature at the end of the fin is essentially that of the surrounding air, i.e., \(20^{\circ} \mathrm{C}\). Its width is \(5.0 \mathrm{~cm}\); thickness is \(1.0 \mathrm{~mm}\); thermal conductivity is $200 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\(; and base temperature is \)40^{\circ} \mathrm{C}$. The heat transfer coefficient is \(20 \mathrm{~W} / \mathrm{m}^{2}\). . Estimate the fin temperature at a distance of \(5.0 \mathrm{~cm}\) from the base and the rate of heat loss from the entire fin.

A spherical vessel, \(3.0 \mathrm{~m}\) in diameter (and negligible wall thickness), is used for storing a fluid at a temperature of $0^{\circ} \mathrm{C}\(. The vessel is covered with a \)5.0$-cm-thick layer of an insulation \((k=0.20 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\). The surrounding air is at \(22^{\circ} \mathrm{C}\). The inside and outside heat transfer coefficients are 40 and 10 $\mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{K}\(, respectively. Calculate \)(a)$ all thermal resistances, in \(\mathrm{K} / \mathrm{W},(b)\) the steady rate of heat transfer, and \((c)\) the temperature difference across the insulation layer.

Hot water flows in a 1-m-long section of a pipe that is made of acrylonitrile butadiene styrene (ABS) thermoplastic. The \(\mathrm{ABS}\) pipe section has an inner diameter of \(D_{1}=22 \mathrm{~mm}\) and an outer diameter of $D_{2}=27 \mathrm{~mm}\(. The thermal conductivity of the ABS pipe wall is \)0.1 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. The outer pipe surface is exposed to convection heat transfer with air at \(20^{\circ} \mathrm{C}\) and $h=10 \mathrm{~W} / \mathrm{m}^{2} . \mathrm{K}$. The water flowing inside the pipe has a convection heat transfer coefficient of $50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. According to the ASME Code for Process Piping (ASME B31.3-2014, Table B-1), the maximum recommended temperature for \(\mathrm{ABS}\) pipe is \(80^{\circ} \mathrm{C}\). Determine the maximum temperature of the water flowing in the pipe, such that the ABS pipe is operating at the recommended temperature or lower. What is the temperature at the outer pipe surface when the water is at maximum temperature?

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