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Explain how the fins enhance heat transfer from a surface. Also, explain how the addition of fins may actually decrease heat transfer from a surface.

Short Answer

Expert verified
Answer: The key factors to consider when adding fins are adequate spacing, appropriate fin design and size, regular cleaning to prevent dirt and dust accumulation, and avoiding overcrowding by adding too many fins. These factors ensure efficient conduction and convection processes and prevent resistance to air circulation or impaired heat transfer.

Step by step solution

01

Understanding Fins

Fins are protrusions made from high thermal conductivity materials that are attached to surfaces to enhance heat transfer. Fins increase the overall heat transferring surface area, leading to a more efficient cooling or heating system.
02

How Fins Enhance Heat Transfer

Fins enhance heat transfer through two main mechanisms: conduction and convection. 1. Conduction: Fins are made from high thermal conductivity materials, which allow faster heat transfer from the base surface to the fin tips. 2. Convection: The increased surface area due to the presence of fins promotes better contact between the solid surface and the fluid, allowing greater heat transfer through the process of convection. As a result, fins help to efficiently move heat away from the base surface, keeping it cool and maintaining the desired temperature.
03

Circumstances Where Fins May Decrease Heat Transfer

There are a few factors that can negatively impact the efficiency of fins and may lead to a decrease in heat transfer. 1. Inadequate Spacing: Fins that are placed too closely might lead to impaired air circulation, resulting in a reduced heat transfer rate. In this case, the benefits of the increased surface area are nullified due to poor convective heat transfer. 2. Poor Fin Design: If fins have an inappropriate geometry or are not adequately sized, they may experience low efficiency, leading to reduced heat transfer from the surface. 3. Dirty Fins: Dirt and dust accumulating on the fin surface can act as an insulating layer and reduce heat transfer between the fins and the surrounding fluid. Regular cleaning is necessary to maintain fin efficiency. 4. Overcrowding: Including too many fins can sometimes result in diminishing returns. Beyond a certain limit, adding more fins may increase the resistance to air circulation, hindering heat transfer. In conclusion, fins can significantly enhance the heat transfer from a surface by increasing the surface area and facilitating conduction and convection processes. However, the addition of fins requires careful consideration of factors like spacing, design, cleanliness, and number of fins to ensure their efficiency and not lead to a decrease in heat transfer.

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Most popular questions from this chapter

Hot water at an average temperature of \(80^{\circ} \mathrm{C}\) and an average velocity of \(1.5 \mathrm{~m} / \mathrm{s}\) is flowing through a \(25-\mathrm{m}\) section of a pipe that has an outer diameter of $5 \mathrm{~cm}\(. The pipe extends \)2 \mathrm{~m}$ in the ambient air above the ground, dips into the ground $(k=1.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\( ) vertically for \)3 \mathrm{~m}$, and continues horizontally at this depth for \(20 \mathrm{~m}\) more before it enters the next building.

Hot air is to be cooled as it is forced to flow through the tubes exposed to atmospheric air. Fins are to be added in order to enhance heat transfer. Would you recommend attaching the fins inside or outside the tubes? Why? When would you recommend attaching fins both inside and outside the tubes?

A spherical vessel, \(3.0 \mathrm{~m}\) in diameter (and negligible wall thickness), is used for storing a fluid at a temperature of $0^{\circ} \mathrm{C}\(. The vessel is covered with a \)5.0$-cm-thick layer of an insulation \((k=0.20 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\). The surrounding air is at \(22^{\circ} \mathrm{C}\). The inside and outside heat transfer coefficients are 40 and 10 $\mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{K}\(, respectively. Calculate \)(a)$ all thermal resistances, in \(\mathrm{K} / \mathrm{W},(b)\) the steady rate of heat transfer, and \((c)\) the temperature difference across the insulation layer.

A \(3-\mathrm{cm}\)-long, \(2-\mathrm{mm} \times 2-\mathrm{mm}\) rectangular cross-section aluminum fin \((k=237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is attached to a surface. If the fin efficiency is 65 percent, the effectiveness of this single fin is (a) 39 (b) 30 (c) 24 (d) 18 (e) 7

Heat is lost at a rate of \(275 \mathrm{~W}\) per \(\mathrm{m}^{2}\) area of a 15 -cm-thick wall with a thermal conductivity of $k=1.1 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. The temperature drop across the wall is (a) \(37.5^{\circ} \mathrm{C}\) (b) \(27.5^{\circ} \mathrm{C}\) (c) \(16.0^{\circ} \mathrm{C}\) (d) \(8.0^{\circ} \mathrm{C}\) (e) \(4.0^{\circ} \mathrm{C}\)

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