Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Consider a long pipe of inner radius \(r_{1}\), outer radius \(r_{2}\), and thermal conductivity \(k\). The outer surface of the pipe is subjected to convection to a medium at \(T_{\infty}\) with a heat transfer coefficient of \(h\), but the direction of heat transfer is not known. Express the convection boundary condition on the outer surface of the pipe.

Short Answer

Expert verified
Answer: The convection boundary condition on the outer surface of the pipe can be expressed as: \(-k \frac{d T}{d r}\Big|_{r=r_2} = h (T_s - T_{\infty})\).

Step by step solution

01

Understand the conduction and convection processes

In this scenario, heat is transferred from the pipe to the surroundings in two ways: 1. Conduction: This is the process by which heat is transferred within the pipe through its walls. It depends on the temperature gradient and the pipe's thermal conductivity. 2. Convection: This is the process by which heat is transferred from the pipe's outer surface to the surrounding medium. It depends on the heat transfer coefficient and the temperature difference between the outer surface and the surrounding medium.
02

Write the heat transfer equation for conduction

Using Fourier's Law of conduction, the heat transfer rate due to conduction (\(q_c\)) can be given as: $$q_c = -k \frac{d T}{d r}$$ Where \(k\) is the thermal conductivity of the pipe and \(\frac{d T}{d r}\) is the temperature gradient across the pipe wall.
03

Write the heat transfer equation for convection

Using Newton's Law of cooling, the heat transfer rate due to convection (\(q_h\)) can be given as: $$q_h = h (T_s - T_{\infty})$$ Where \(h\) is the heat transfer coefficient, \(T_s\) is the temperature at the outer surface of the pipe, and \(T_{\infty}\) is the temperature of the surrounding medium.
04

Express the convection boundary condition on the outer surface of the pipe

At the outer surface (i.e., \(r=r_2\)), the heat transfer rate due to conduction should be equal to the heat transfer rate due to convection. Thus, the convection boundary condition can be given as: $$-k \frac{d T}{d r}\Big|_{r=r_2} = h (T_s - T_{\infty})$$ This equation represents the convection boundary condition on the outer surface of the pipe.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A series of ASME SA-193 carbon steel bolts are bolted onto the upper surface of a metal plate. The metal plate has a thickness of \(3 \mathrm{~cm}\), and its thermal conductivity is \(15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The bottom surface of the plate is subjected to a uniform heat flux of $5 \mathrm{~kW} / \mathrm{m}^{2}$. The upper surface of the plate is exposed to ambient air with a temperature of \(30^{\circ} \mathrm{C}\) and a convection heat transfer coefficient of \(10 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The ASME Boiler and Pressure Vessel Code (ASME BPVC.IV-2015, HF-300) limits the maximum allowable use temperature to \(260^{\circ} \mathrm{C}\) for the SA-193 bolts. Formulate the variation of temperature in the metal plate, and determine the temperatures at \(x=0,1.5\), and \(3.0 \mathrm{~cm}\). Would the SA-193 bolts comply with the ASME code?

Liquid water flows in a tube with the inner surface lined with polytetrafluoroethylene (PTFE). The inner diameter of the tube is $24 \mathrm{~mm}\(, and its wall thickness is \)5 \mathrm{~mm}$. The thermal conductivity of the tube wall is $15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\(. The water flowing in the tube has a temperature of \)50^{\circ} \mathrm{C}$, and the convection heat transfer coefficient with the inner tube surface is \(50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The outer surface of the tube is exposed to convection with superheated steam at \(600^{\circ} \mathrm{C}\) with a convection heat transfer coefficient of $50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. According to the ASME Code for Process Piping (ASME B31.3-2014, A323), the recommended maximum temperature for PTFE lining is \(260^{\circ} \mathrm{C}\). Formulate the temperature profile in the tube wall. Use the temperature profile to determine if the tube inner surface is in compliance with the ASME Code for Process Piping.

A long electrical resistance wire of radius \(r_{1}=0.25 \mathrm{~cm}\) has a thermal conductivity $k_{\text {wirc }}=15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. Heat is generated uniformly in the wire as a result of resistance heating at a constant rate of \(0.5 \mathrm{~W} / \mathrm{cm}^{3}\). The wire is covered with polyethylene insulation with a thickness of \(0.25 \mathrm{~cm}\) and thermal conductivity of $k_{\text {ins }}=0.4 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. The outer surface of the insulation is subjected to free convection in air at \(20^{\circ} \mathrm{C}\) and a convection heat transfer coefficient of \(2 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Formulate the temperature profiles for the wire and the polyethylene insulation. Use the temperature profiles to determine the temperature at the interface of the wire and the insulation and the temperature at the center of the wire. The ASTM D1351 standard specifies that thermoplastic polyethylene insulation is suitable for use on electrical wire that operates at temperatures up to \(75^{\circ} \mathrm{C}\). Under these conditions, does the polyethylene insulation for the wire meet the ASTM D1351 standard?

Hot water flows through a PVC $(k=0.092 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\( pipe whose inner diameter is \)2 \mathrm{~cm}$ and whose outer diameter is \(2.5 \mathrm{~cm}\). The temperature of the interior surface of this pipe is \(35^{\circ} \mathrm{C}\), and the temperature of the exterior surface is \(20^{\circ} \mathrm{C}\). The rate of heat transfer per unit of pipe length is (a) \(22.8 \mathrm{~W} / \mathrm{m}\) (b) \(38.9 \mathrm{~W} / \mathrm{m}\) (c) \(48.7 \mathrm{~W} / \mathrm{m}\) (d) \(63.6 \mathrm{~W} / \mathrm{m}\) (e) \(72.6 \mathrm{~W} / \mathrm{m}\)

A spherical communication satellite with a diameter of \(2.5 \mathrm{~m}\) is orbiting the earth. The outer surface of the satellite in space has an emissivity of \(0.75\) and a solar absorptivity of \(0.10\), while solar radiation is incident on the spacecraft at a rate of $1000 \mathrm{~W} / \mathrm{m}^{2}$. If the satellite is made of material with an average thermal conductivity of \(5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and the midpoint temperature is \(0^{\circ} \mathrm{C}\), determine the heat generation rate and the surface temperature of the satellite.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free