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The conduction equation boundary condition for an adiabatic surface with direction \(n\) being normal to the surface is (a) \(T=0\) (b) \(d T / d n=0\) (c) \(d^{2} T / d n^{2}=0\) (d) \(d^{3} T / d n^{3}=0\) (e) \(-k d T / d n=1\)

Short Answer

Expert verified
Answer: The correct boundary condition for an adiabatic surface is \(d T / d n=0\).

Step by step solution

01

Definition of an adiabatic surface

An adiabatic surface is a surface where there is no heat transfer across it. This means that the rate of heat transfer through the surface is zero.
02

Conduction Equation

The rate of heat transfer by conduction is given by Fourier's law, which states that: \[q = -k \frac{dT}{dn}\] where \(q\) is the rate of heat transfer per unit area, \(k\) is the thermal conductivity of the material, and \(\frac{dT}{dn}\) is the temperature gradient in the normal direction to the surface.
03

Adiabatic Boundary Condition

The boundary condition for an adiabatic surface is that the rate of heat transfer (\(q\)) through the surface must be zero. Therefore, from Fourier's law, we get: \[0 = -k \frac{dT}{dn}\]
04

Simplify the Boundary Condition

Since \(k\) is a constant, it can be derived that the temperature gradient in the normal direction to the surface must be zero. Thus, the adiabatic boundary condition for the conduction equation is: \[\frac{dT}{dn} = 0\]
05

Final Answer

The correct boundary condition for an adiabatic surface is option (b): \[d T / d n=0\]

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Most popular questions from this chapter

Consider steady one-dimensional heat conduction through a plane wall, a cylindrical shell, and a spherical shell of uniform thickness with constant thermophysical properties and no thermal energy generation. The geometry in which the variation of temperature in the direction of heat transfer will be linear is (a) plane wall (b) cylindrical shell (c) spherical shell (d) all of them (e) none of them

Consider a third-order linear and homogeneous differential equation. How many arbitrary constants will its general solution involve?

A large plane wall has a thickness \(L=50 \mathrm{~cm}\) and thermal conductivity \(k=25 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). On the left surface \((x=0)\), it is subjected to a uniform heat flux \(\dot{q}_{0}\) while the surface temperature \(T_{0}\) is constant. On the right surface, it experiences convection and radiation heat transfer while the surface temperature is \(T_{L}=225^{\circ} \mathrm{C}\) and the surrounding temperature is \(25^{\circ} \mathrm{C}\). The emissivity and the convection heat transfer coefficient on the right surface are \(0.7\) and $15 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, respectively. (a) Show that the variation of temperature in the wall can be expressed as $T(x)=\left(\dot{q}_{0} / k\right)(L-x)+T_{L},(b)\( calculate the heat flux \)\dot{q}_{0}$ on the left face of the wall, and (c) determine the temperature of the left surface of the wall at \(x=0\).

Is the thermal conductivity of a medium, in general, constant or does it vary with temperature?

The thermal conductivity of a solid depends upon the solid's temperature as \(k=a T+b\) where \(a\) and \(b\) are constants. The temperature in a planar layer of this solid as it conducts heat is given by (a) \(a T+b=x+C_{2}\) (b) \(a T+b=C_{1} x^{2}+C_{2}\) (c) \(a T^{2}+b T=C_{1} x+C_{2}\) (d) \(a T^{2}+b T=C_{1} x^{2}+C_{2}\) (e) None of them

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