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Consider a medium in which the heat conduction equation is given in its simplest forms as $$ \frac{1}{r^{2}} \frac{\partial}{\partial r}\left(r^{2} \frac{\partial T}{\partial r}\right)=\frac{1}{\alpha} \frac{\partial T}{\partial t} $$ (a) Is heat transfer steady or transient? (b) Is heat transfer one-, two-, or three-dimensional? (c) Is there heat generation in the medium? (d) Is the thermal conductivity of the medium constant or variable? (e) Is the medium a plane wall, a cylinder, or a sphere? (f) Is this differential equation for heat conduction linear or nonlinear?

Short Answer

Expert verified
To summarize, the given heat conduction equation has the following properties: a) Transient heat transfer b) One-dimensional heat transfer c) No heat generation in the medium d) Constant thermal conductivity of the medium e) Cylindrical or spherical shape of the medium (cannot definitively identify) f) Linearity of the differential equation

Step by step solution

01

(a) Steady or Transient Heat Transfer

The given heat conduction equation involves a time derivative term, which is: $$ \frac{\partial T}{\partial t} $$ Since the time derivative term exists in the equation, it means the heat transfer is transient, not steady.
02

(b) Dimensionality of the Heat Transfer

The equation involves only the spatial variable, r: $$ \frac{\partial}{\partial r}\left(r^{2} \frac{\partial T}{\partial r}\right) $$ As it is the only spatial variable included in the equation, this indicates that the heat transfer is one-dimensional.
03

(c) Heat Generation in the Medium

The equation does not include any additional terms representing heat generation. Therefore, there is no heat generation in the medium.
04

(d) Thermal Conductivity of the Medium

The thermal conductivity of the medium is not explicitly given in the equation, but the constant α is used. Since the equation does not involve any function of thermal conductivity as a variable, we can assume that the thermal conductivity is constant.
05

(e) Shape of the Medium

The equation is given in terms of the radial coordinate, r: $$ \frac{1}{r^{2}} \frac{\partial}{\partial r}\left(r^{2} \frac{\partial T}{\partial r}\right) $$ This suggests that the medium is either cylindrical or spherical in shape. However, without additional information, we can not definitively identify the shape.
06

(f) Linearity of the Differential Equation

The given differential equation is linear. This can be seen by the absence of any nonlinear interactions with temperature T or its derivatives, such as multiplication of different order derivatives or raising them to a power. The equation only includes the derivatives of the temperature term T and their linear combinations.

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Most popular questions from this chapter

Consider a solid cylindrical rod whose ends are maintained at constant but different temperatures while the side surface is perfectly insulated. There is no heat generation. It is claimed that the temperature along the axis of the rod varies linearly during steady heat conduction. Do you agree with this claim? Why?

A large plane wall has a thickness \(L=50 \mathrm{~cm}\) and thermal conductivity \(k=25 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). On the left surface \((x=0)\), it is subjected to a uniform heat flux \(\dot{q}_{0}\) while the surface temperature \(T_{0}\) is constant. On the right surface, it experiences convection and radiation heat transfer while the surface temperature is \(T_{L}=225^{\circ} \mathrm{C}\) and the surrounding temperature is \(25^{\circ} \mathrm{C}\). The emissivity and the convection heat transfer coefficient on the right surface are \(0.7\) and $15 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, respectively. (a) Show that the variation of temperature in the wall can be expressed as $T(x)=\left(\dot{q}_{0} / k\right)(L-x)+T_{L},(b)\( calculate the heat flux \)\dot{q}_{0}$ on the left face of the wall, and (c) determine the temperature of the left surface of the wall at \(x=0\).

A plane wall of thickness \(L\) is subjected to convection at both surfaces with ambient temperature \(T_{\infty \text { el }}\) and heat transfer coefficient \(h_{1}\) at the inner surface and corresponding \(T_{\infty 2}\) and \(h_{2}\) values at the outer surface. Taking the positive direction of \(x\) to be from the inner surface to the outer surface, the correct expression for the convection boundary condition is (a) \(k \frac{d T(0)}{d x}=h_{1}\left[T(0)-T_{\infty 1}\right]\) (b) $k \frac{d T(L)}{d x}=h_{2}\left[T(L)-T_{\infty 22}\right]$ (c) $-k \frac{d T(0)}{d x}=h_{1}\left(T_{\infty 1}-T_{\infty 22}\right)(d)-k \frac{d T(L)}{d x}=h_{2}\left(T_{\infty \infty 1}-T_{\infty 22}\right)$ (e) None of them

Consider steady one-dimensional heat conduction in a plane wall in which the thermal conductivity varies linearly. The error involved in heat transfer calculations by assuming constant thermal conductivity at the average temperature is \((a)\) none, \((b)\) small, or \((c)\) significant.

A spherical communication satellite with a diameter of \(2.5 \mathrm{~m}\) is orbiting the earth. The outer surface of the satellite in space has an emissivity of \(0.75\) and a solar absorptivity of \(0.10\), while solar radiation is incident on the spacecraft at a rate of $1000 \mathrm{~W} / \mathrm{m}^{2}$. If the satellite is made of material with an average thermal conductivity of \(5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and the midpoint temperature is \(0^{\circ} \mathrm{C}\), determine the heat generation rate and the surface temperature of the satellite.

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