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Consider a third-order linear and homogeneous differential equation. How many arbitrary constants will its general solution involve?

Short Answer

Expert verified
Answer: The general solution of a third-order linear and homogeneous differential equation involves 3 arbitrary constants.

Step by step solution

01

Understand the given differential equation

A third-order linear and homogeneous differential equation can be represented as: \(a_3y'''(x) + a_2y''(x) + a_1y'(x) + a_0y(x) = 0\) where \(a_0, a_1, a_2,\) and \(a_3\) are constants, \(y(x)\) is the dependent variable, and the primes denote the order of the derivative.
02

Determine the number of independent solutions

For a linear homogeneous differential equation of order \(n\), there will be \(n\) linearly independent solutions. In this case, the order is 3, so there are 3 independent solutions.
03

Write the general solution

The general solution of a linear homogeneous differential equation is the linear combination of its \(n\) linearly independent solutions. For a third-order equation with 3 independent solutions \(y_1(x), y_2(x),\) and \(y_3(x)\), the general solution can be written as: \(y(x) = C_1y_1(x) + C_2y_2(x) + C_3y_3(x)\)
04

Determine the number of arbitrary constants

The general solution involves 3 arbitrary constants, \(C_1, C_2,\) and \(C_3\), which correspond to the 3 coefficients of the linear combination of independent solutions. These constants can take any value and are determined by the initial conditions or boundary conditions of the specific problem. Therefore, the general solution of a third-order linear and homogeneous differential equation will involve 3 arbitrary constants.

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Most popular questions from this chapter

How do you distinguish a linear differential equation from a nonlinear one?

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