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Consider a cold canned drink left on a dinner table. Would you model the heat transfer to the drink as one-, two-, or three-dimensional? Would the heat transfer be steady or transient? Also, which coordinate system would you use to analyze this heat transfer problem, and where would you place the origin? Explain.

Short Answer

Expert verified
Answer: For the cold canned drink problem, the heat transfer process is one-dimensional and transient. A cylindrical coordinate system should be used for analysis, with the origin placed at the center of the can's bottom surface.

Step by step solution

01

Determine if the heat transfer is one-, two-, or three-dimensional

First, let's examine the geometry of the canned drink and how heat transfers. Heat transfers from the surrounding air to the canned drink in all directions. However, the can is cylindrical and its height or length is much greater than its radius or diameter. Due to the predominant heat transfer occurring across the height of the can, we can assume that the heat transfer process is one-dimensional along its height or length.
02

Determine if the heat transfer is steady or transient

The temperature of the canned drink will change over time as it gains heat from the surrounding air, and that change will eventually slow down when it reaches the equilibrium with the surrounding temperature. Since the temperature of the drink changes over time, the heat transfer process is transient.
03

Choose the appropriate coordinate system

Since we have established that the heat transfer is one-dimensional along the height of the can, it is best to use a cylindrical coordinate system. In this coordinate system, we have three variables: radial distance (r), azimuthal angle (θ), and axial distance (z). Since the heat transfer is mainly along the height of the can (one-dimensional), we will focus on the z-coordinate.
04

Placement of the origin

To analyze the heat transfer problem, we can place the origin at the center of the can's bottom surface. In the cylindrical coordinate system, the origin placement would be (r, θ, z) = (0, 0, 0). This position helps to simplify the mathematical analysis and allows us to focus on the axial distance (z) for understanding the heat transfer along the height of the can. In conclusion, we have established the following for this heat transfer problem: The heat transfer to the cold canned drink is one-dimensional and transient. A cylindrical coordinate system is suitable for analyzing this problem, with the origin placed at the center of the can's bottom surface.

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Most popular questions from this chapter

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