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What is the geometrical interpretation of a derivative? What is the difference between partial derivatives and ordinary derivatives?

Short Answer

Expert verified
Answer: The main difference between partial derivatives and ordinary derivatives is that partial derivatives are used for multivariable functions, examining the rate of change with respect to one variable while holding all others constant, while ordinary derivatives are used for single-variable functions, examining the rate of change with respect to the only variable in the function.

Step by step solution

01

Geometrical Interpretation of a Derivative

A derivative of a function is a measure of how much the function's output (or dependent variable) changes in response to a small change in its input (or independent variable). Geometrically, the derivative of a function at a given point corresponds to the slope of the tangent line to the function's graph at that point. In simpler terms, the derivative represents the rate of change (or the slope) of the function at a specific point.
02

Partial Derivatives

Partial derivatives are used when dealing with multivariable functions (functions with more than one independent variable). A partial derivative is the rate of change of the function with respect to one of its variables while keeping the other variables constant. It is denoted by the symbol ∂, for example, ∂f/∂x, which represents the partial derivative of the function f(x, y) with respect to x, keeping y constant.
03

Ordinary Derivatives

Ordinary derivatives, on the other hand, are used when dealing with single-variable functions (functions with only one independent variable). An ordinary derivative represents the rate of change of the function with respect to its only variable and is denoted by d, for example, df/dx, which represents the derivative of the function f(x) with respect to x.
04

Difference between Partial Derivatives and Ordinary Derivatives

The primary difference between partial derivatives and ordinary derivatives lies in the context in which they are used. Partial derivatives apply to multivariable functions and examine the rate of change with respect to one variable while holding all others constant. Ordinary derivatives apply to single-variable functions and examine the rate of change with respect to the only variable in the function. Though the concept and interpretation of both types of derivatives are similar, they are used in different contexts and their notation is different, as well.

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Most popular questions from this chapter

In a food processing facility, a spherical container of inner radius $r_{1}=40 \mathrm{~cm}\(, outer radius \)r_{2}=41 \mathrm{~cm}$, and thermal conductivity \(k=1.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) is used to store hot water and to keep it at \(100^{\circ} \mathrm{C}\) at all times. To accomplish this, the outer surface of the container is wrapped with a \(500-\mathrm{W}\) electric strip heater and then insulated. The temperature of the inner surface of the container is observed to be nearly \(100^{\circ} \mathrm{C}\) at all times. Assuming 10 percent of the heat generated in the heater is lost through the insulation, \((a)\) express the differential equation and the boundary conditions for steady one-dimensional heat conduction through the container, \((b)\) obtain a relation for the variation of temperature in the container material by solving the differential equation, and (c) evaluate the outer surface temperature of the container. Also determine how much water at \(100^{\circ} \mathrm{C}\) this tank can supply steadily if the cold water enters at \(20^{\circ} \mathrm{C}\).

A pipe is used for transporting boiling water in which the inner surface is at \(100^{\circ} \mathrm{C}\). The pipe is situated where the ambient temperature is \(20^{\circ} \mathrm{C}\) and the convection heat transfer coefficient is $50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. The pipe has a wall thickness of \(3 \mathrm{~mm}\) and an inner diameter of \(25 \mathrm{~mm}\), and it has a variable thermal conductivity given as \(k(T)=k_{0}(1+\beta T)\), where $k_{0}=1.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \beta=0.003 \mathrm{~K}^{-1}\(, and \)T\( is in \)\mathrm{K}$. Determine the outer surface temperature of the pipe.

Is the thermal conductivity of a medium, in general, constant or does it vary with temperature?

What is the difference between an algebraic equation and a differential equation?

A long electrical resistance wire of radius \(r_{1}=0.25 \mathrm{~cm}\) has a thermal conductivity $k_{\text {wirc }}=15 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. Heat is generated uniformly in the wire as a result of resistance heating at a constant rate of \(0.5 \mathrm{~W} / \mathrm{cm}^{3}\). The wire is covered with polyethylene insulation with a thickness of \(0.25 \mathrm{~cm}\) and thermal conductivity of $k_{\text {ins }}=0.4 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. The outer surface of the insulation is subjected to free convection in air at \(20^{\circ} \mathrm{C}\) and a convection heat transfer coefficient of \(2 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Formulate the temperature profiles for the wire and the polyethylene insulation. Use the temperature profiles to determine the temperature at the interface of the wire and the insulation and the temperature at the center of the wire. The ASTM D1351 standard specifies that thermoplastic polyethylene insulation is suitable for use on electrical wire that operates at temperatures up to \(75^{\circ} \mathrm{C}\). Under these conditions, does the polyethylene insulation for the wire meet the ASTM D1351 standard?

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