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The molar analysis of a gas mixture at \(290 \mathrm{~K}\) and $250 \mathrm{kPa}\( is 65 percent \)\mathrm{N}_{2}, 20\( percent \)\mathrm{O}_{2}$, and 15 percent \(\mathrm{CO}_{2}\). Determine the mass fraction and partial pressure of each gas.

Short Answer

Expert verified
Answer: The mass fractions and partial pressures of each gas are: - N2: mass fraction ≈ 0.593, partial pressure ≈ 162.5 kPa - O2: mass fraction ≈ 0.270, partial pressure ≈ 50 kPa - CO2: mass fraction ≈ 0.137, partial pressure ≈ 37.5 kPa

Step by step solution

01

Calculate the molar mass of each gas

To find the mass fractions, we need the molar mass of each gas. For N2, O2, and CO2, we can use the periodic table to determine their molar masses: - N2 has a molar mass of 28 g/mol - O2 has a molar mass of 32 g/mol - CO2 has a molar mass of 44 g/mol
02

Calculate the mass fraction of each gas

Mass fraction is the mass of each component divided by the total mass of the mixture. When given the molar analysis, we can calculate the mass fraction of each gas as follows: - N2 mass fraction = 0.65 x 28 / (0.65 x 28 + 0.20 x 32 + 0.15 x 44) - O2 mass fraction = 0.20 x 32 / (0.65 x 28 + 0.20 x 32 + 0.15 x 44) - CO2 mass fraction = 0.15 x 44 / (0.65 x 28 + 0.20 x 32 + 0.15 x 44) Calculate the mass fractions: - N2 mass fraction ≈ 0.593 - O2 mass fraction ≈ 0.270 - CO2 mass fraction ≈ 0.137
03

Calculate the partial pressure of each gas

The partial pressure of each gas can be found using Dalton's Law, which states that the partial pressure of a gas in a mixture is equal to the mole fraction of that gas times the total pressure. For N2, O2, and CO2, use their mole fractions (given as percentages) and the total pressure of 250 kPa: - N2 partial pressure = 0.65 x 250 kPa - O2 partial pressure = 0.20 x 250 kPa - CO2 partial pressure = 0.15 x 250 kPa Calculate the partial pressures: - N2 partial pressure ≈ 162.5 kPa - O2 partial pressure ≈ 50 kPa - CO2 partial pressure ≈ 37.5 kPa So, the mass fractions and partial pressures of each gas are: - N2: mass fraction ≈ 0.593, partial pressure ≈ 162.5 kPa - O2: mass fraction ≈ 0.270, partial pressure ≈ 50 kPa - CO2: mass fraction ≈ 0.137, partial pressure ≈ 37.5 kPa

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Most popular questions from this chapter

You probably have noticed that balloons inflated with helium gas rise in the air the first day during a party but they fall down the next day and act like ordinary balloons filled with air. This is because the helium in the balloon slowly leaks out through the wall while air leaks in by diffusion. Consider a balloon that is made of \(0.2\)-mm-thick soft rubber and has a diameter of \(15 \mathrm{~cm}\) when inflated. The pressure and temperature inside the balloon are initially \(120 \mathrm{kPa}\) and $25^{\circ} \mathrm{C}$. The permeability of rubber to helium, oxygen, and nitrogen at \(25^{\circ} \mathrm{C}\) are \(9.4 \times 10^{-13}, 7.05 \times 10^{-13}\), and $2.6 \times 10^{-13} \mathrm{kmol} / \mathrm{m} \cdot \mathrm{s} \cdot \mathrm{bar}$, respectively. Determine the initial rates of diffusion of helium, oxygen, and nitrogen through the balloon wall and the mass fraction of helium that escapes the balloon during the first 5 \(\mathrm{h}\), assuming the helium pressure inside the balloon remains nearly constant. Assume air to be 21 percent oxygen and 79 percent nitrogen by mole numbers, and take the room conditions to be \(100 \mathrm{kPa}\) and \(25^{\circ} \mathrm{C}\).

Explain how vapor pressure of the ambient air is determined when the temperature, total pressure, and relative humidity of the air are given.

How does the condensation or freezing of water vapor in the wall affect the effectiveness of the insulation in the wall? How does the moisture content affect the effective thermal conductivity of soil?

Reconsider Prob. 14-82. In order to reduce the migration of water vapor through the wall, it is proposed to use a \(0.051-\mathrm{mm}\)-thick polyethylene film with a permeance of $9.1 \times 10^{-12} \mathrm{~kg} / \mathrm{s}^{2} \mathrm{~m}^{2}$.Pa. Determine the amount of water vapor that will diffuse through the wall in this case during a \(24-\mathrm{h}\) period. Answer: \(26.4 \mathrm{~g}\)

Pure \(\mathrm{N}_{2}\) gas at \(1 \mathrm{~atm}\) and \(25^{\circ} \mathrm{C}\) is flowing through a 10 -m-long, 3-cm-inner diameter pipe made of 2 -mm-thick rubber. Determine the rate at which \(\mathrm{N}_{2}\) leaks out of the pipe if the medium surrounding the pipe is \((a)\) a vacuum and \((b)\) atmospheric air at \(1 \mathrm{~atm}\) and \(25^{\circ} \mathrm{C}\) with 21 percent \(\mathrm{O}_{2}\) and 79 percent \(\mathrm{N}_{2}\). Answers: (ca) $2.28 \times 10^{-10} \mathrm{kmol} / \mathrm{s}\(, (b) \)4.78 \times\( \)10^{-11} \mathrm{kmol} / \mathrm{s}$

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