Chapter 14: Problem 12
At a given temperature and pressure, do you think the mass diffusivity of copper in aluminum will be equal to the mass diffusivity of aluminum in copper? Explain.
Chapter 14: Problem 12
At a given temperature and pressure, do you think the mass diffusivity of copper in aluminum will be equal to the mass diffusivity of aluminum in copper? Explain.
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Get started for freeA gas mixture in a tank at \(550 \mathrm{R}\) and 25 psia consists of $1 \mathrm{lbm}\( of \)\mathrm{CO}_{2}\( and \)3 \mathrm{lbm}\( of \)\mathrm{CH}_{4}$. Determine the volume of the tank and the partial pressure of each gas.
What is Stefan flow? Write the expression for Stefan's law and indicate what each variable represents.
Consider a rubber membrane separating carbon dioxide gas that is maintained on one side at \(2 \mathrm{~atm}\) and on the opposite at \(1 \mathrm{~atm}\). If the temperature is constant at \(25^{\circ} \mathrm{C}\), determine (a) the molar densities of carbon dioxide in the rubber membrane on both sides and \((b)\) the molar densities of carbon dioxide outside the rubber membrane on both sides.
Consider a 30 -cm-diameter pan filled with water at \(15^{\circ} \mathrm{C}\) in a room at \(20^{\circ} \mathrm{C}, 1 \mathrm{~atm}\), and 30 percent relative humidity. Determine \((a)\) the rate of heat transfer by convection, (b) the rate of evaporation of water, and \((c)\) the rate of heat transfer to the water needed to maintain its temperature at \(15^{\circ} \mathrm{C}\). Disregard any radiation effects.
Air flows in a 4-cm-diameter wet pipe at \(20^{\circ} \mathrm{C}\) and $1 \mathrm{~atm}\( with an average velocity of \)4 \mathrm{~m} / \mathrm{s}$ in order to dry the surface. The Nusselt number in this case can be determined from \(\mathrm{Nu}=0.023 \operatorname{Re}^{0.8} \mathrm{Pr}^{0.4}\) where \(\operatorname{Re}=10,550\) and \(\mathrm{Pr}=\) \(0.731\). Also, the diffusion coefficient of water vapor in air is $2.42 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}$. Using the analogy between heat and mass transfer, the mass transfer coefficient inside the pipe for fully developed flow becomes (a) \(0.0918 \mathrm{~m} / \mathrm{s}\) (b) \(0.0408 \mathrm{~m} / \mathrm{s}\) (c) \(0.0366 \mathrm{~m} / \mathrm{s}\) (d) \(0.0203 \mathrm{~m} / \mathrm{s}\) (e) \(0.0022 \mathrm{~m} / \mathrm{s}\)
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