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At a given temperature and pressure, do you think the mass diffusivity of air in water vapor will be equal to the mass diffusivity of water vapor in air? Explain.

Short Answer

Expert verified
Answer: No, the mass diffusivity of air in water vapor is not expected to be equal to the mass diffusivity of water vapor in air, even when both systems are under the same temperature and pressure. This is because the overall properties and molecular interactions in the two systems differ due to the different ratios of the components.

Step by step solution

01

Understand Mass Diffusivity

Mass diffusivity, also known as diffusion coefficient, is a measure of how easily one substance mixes with another due to the random motion of its particles. It is often represented by the letter D, and its units are m²/s. Factors affecting mass diffusivity include temperature, pressure, and the properties of the gases involved.
02

Analyze the given system

In this case, we are comparing the mass diffusivity of two different gas systems: air in water vapor (System A) and water vapor in air (System B). Both systems are maintained at the same temperature and pressure.
03

Understand the factors involved in diffusivity

The diffusivity of a gas system is generally a function of the physical properties of the gas molecules, such as molecular size, shape, and weight, as well as the interaction between the gas molecules. Other factors, such as temperature and pressure, also influence diffusivity.
04

Compare the systems in question

In both System A and System B, the gases involved are the same - air and water vapor. However, the ratio of air to water vapor differs between the two systems. In System A, the majority of the gas present is water vapor, so the diffusivity of air in water vapor will be mostly influenced by the properties of water vapor. In System B, the majority of the gas is air, so the diffusivity of water vapor in air will be mostly influenced by the properties of air.
05

Conclude whether mass diffusivity is equal in both systems

Because the ratios of air and water vapor are different in the two systems, the overall properties of the systems are not identical, even though both have the same temperature and pressure. The effects of molecular size, shape, and weight, as well as the interaction between molecules, will not be identical in the two systems. As a result, it's unlikely that the mass diffusivities of the two systems will be equal. In conclusion, the mass diffusivity of air in water vapor is not expected to be equal to the mass diffusivity of water vapor in air, even when both systems are under the same temperature and pressure. This is because the overall properties and molecular interactions in the two systems differ due to the different ratios of the components.

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Most popular questions from this chapter

Show that for an ideal gas mixture maintained at a constant temperature and pressure, the molar concentration \(C\) of the mixture remains constant, but this is not necessarily the case for the density \(\rho\) of the mixture.

A sphere of ice, \(5 \mathrm{~cm}\) in diameter, is exposed to $65 \mathrm{~km} / \mathrm{h}$ wind with 15 percent relative humidity. Both the ice sphere and air are at \(-1^{\circ} \mathrm{C}\) and \(90 \mathrm{kPa}\). Predict the rate of evaporation of the ice in \(\mathrm{g} / \mathrm{h}\) by use of the following correlation for single spheres: $\mathrm{Sh}=\left[4.0+1.21(\mathrm{ReSc})^{2 / 3}\right]^{0.5}\(. Data at \)-1^{\circ} \mathrm{C}\( and \)90 \mathrm{kPa}: D_{\text {ais } \mathrm{H}, \mathrm{O}}=2.5 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}^{3}\(, kinematic viscosity (air) \)=1.32 \times 10^{-7} \mathrm{~m}^{2} / \mathrm{s}\(, vapor pressure \)\left(\mathrm{H}_{2} \mathrm{O}\right)=0.56 \mathrm{kPa}\( and density (ice) \)=915 \mathrm{~kg} / \mathrm{m}^{3}$.

Consider a shallow body of water. Is it possible for this water to freeze during a cold and dry night even when the ambient air and surrounding surface temperatures never drop to \(0^{\circ} \mathrm{C}\) ? Explain.

What is diffusion velocity? How does it affect the mass-average velocity? Can the velocity of a species in a moving medium relative to a fixed reference point be zero in a moving medium? Explain.

A recent attempt to circumnavigate the world in a balloon used a helium-filled balloon whose volume was \(7240 \mathrm{~m}^{3}\) and surface area was $1800 \mathrm{~m}^{2}\(. The skin of this balloon is \)2 \mathrm{~mm}$ thick and is made of a material whose helium diffusion coefficient is $1 \times 10^{-9} \mathrm{~m}^{2} / \mathrm{s}$. The molar concentration of the helium at the inner surface of the balloon skin is \(0.2 \mathrm{kmol} / \mathrm{m}^{3}\) and the molar concentration at the outer surface is extremely small. The rate at which helium is lost from this balloon is (a) \(0.26 \mathrm{~kg} / \mathrm{h}\) (b) \(1.5 \mathrm{~kg} / \mathrm{h}\) (c) \(2.6 \mathrm{~kg} / \mathrm{h}\) (d) \(3.8 \mathrm{~kg} / \mathrm{h}\) (e) \(5.2 \mathrm{~kg} / \mathrm{h}\)

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