Question

How can you determine the view factor \(F_{12}\) when the view factor \(F_{21}\) and the surface areas are available?

Short answer

Answer: By substituting the given values into the equation, we can determine \(F_{12}\) as follows: $$F_{12} = \frac{F_{21} A_2}{A_1} = \frac{0.6 * 6 m^2}{4 m^2} = \frac{3.6 m^2}{4 m^2} = 0.9$$ Hence, the view factor from surface 1 to surface 2, \(F_{12}\), is 0.9.

Step-by-step solution

Apply the Reciprocity Theorem

According to the reciprocity theorem, we have: $$F_{12} A_1 = F_{21} A_2$$

Rearrange the equation to find \(F_{12}\)

We are supposed to find the view factor \(F_{12}\). So, we can rearrange the equation as follows: $$F_{12} = \frac{F_{21} A_2}{A_1}$$

Substitute the given values of \(F_{21}\), \(A_1\), and \(A_2\)

Now, we can substitute the available values of \(F_{21}\), \(A_1\), and \(A_2\) into the equation to find the value of \(F_{12}\). Note: Ensure the values of \(F_{21}\), \(A_1\), and \(A_2\) given in the problem statement are substituted in the equation.