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Chapter 13: Problem 131

An average person produces \(0.50 \mathrm{lbm}\) of moisture while taking a shower and \(0.12 \mathrm{lbm}\) while bathing in a tub. Consider a family of four who shower once a day in a bathroom that is not ventilated. Taking the heat of vaporization of water to be \(1050 \mathrm{Btu} / \mathrm{lbm}\), determine the contribution of showers to the latent heat load of the air conditioner in summer per day.

Short Answer

Expert verified
Answer: The contribution of showers to the latent heat load of the air conditioner in summer per day for a family of four is 2100 Btu.

Step by step solution

01

1. Determine the total moisture produced by the family members taking showers

To determine the total moisture produced by the family members, we will multiply the given average moisture produced per shower with the number of family members. Total moisture produced = (Average moisture produced per shower) x (Number of family members) Total moisture produced = (0.50 lbm) x (4)
02

2. Calculate the total moisture produced

Now, let's calculate the total moisture produced by the family members. Total moisture produced = (0.50 lbm) x (4) = 2 lbm
03

3. Determine the contribution to the latent heat load from showers

To find the heat load from showers, we will multiply the total moisture produced by the heat of vaporization of water. Latent heat load from showers = (Total moisture produced) x (Heat of vaporization of water) Latent heat load from showers = (2 lbm) x (1050 Btu/lbm)
04

4. Calculate the latent heat load from showers

Finally, let's calculate the latent heat load from showers. Latent heat load from showers = (2 lbm) x (1050 Btu/lbm) = 2100 Btu Therefore, the contribution of showers to the latent heat load of the air conditioner in summer per day is 2100 Btu.

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What is sensible heat? How is the sensible heat loss from a human body affected by \((a)\) skin temperature, \((b)\) environment temperature, and \((c)\) air motion?

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