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Chapter 13: Problem 126

An average ( \(1.82 \mathrm{~kg}\) or \(4.0 \mathrm{lbm}\) ) chicken has a basal metabolic rate of \(5.47 \mathrm{~W}\) and an average metabolic rate of $10.2 \mathrm{~W}\( (3.78 W sensible and \)6.42 \mathrm{~W}$ latent) during normal activity. If there are 100 chickens in a breeding room, determine the rate of total heat generation and the rate of moisture production in the room. Take the heat of vaporization of water to be \(2430 \mathrm{~kJ} / \mathrm{kg}\).

Short Answer

Expert verified
Answer: The rate of total heat generation is 1567 W, and the rate of moisture production is 0.000264 kg/s.

Step by step solution

01

Find the total metabolic rate per chicken

To find the total metabolic rate per chicken, we will add the basal metabolic rate and the average metabolic rate during normal activity. Total metabolic rate per chicken = Basal metabolic rate + Average metabolic rate = 5.47 W + 10.2 W = 15.67 W.
02

Find the rate of total heat generation in the room

To find the rate of total heat generation in the room, multiply the total metabolic rate per chicken by the number of chickens in the room. Total heat generation = Total metabolic rate per chicken × Number of chickens = 15.67 W/chicken × 100 chickens = 1567 W.
03

Find the sensible and latent heat generation rates

We know the sensible and latent heat generation rates per chicken are 3.78 W and 6.42 W, respectively. To find the total sensible and latent heat generation rates in the room, multiply them by the number of chickens present. Total sensible heat generation rate = Sensible heat generation rate per chicken × Number of chickens = 3.78 W/chicken × 100 chickens = 378 W. Total latent heat generation rate = Latent heat generation rate per chicken × Number of chickens = 6.42 W/chicken × 100 chickens = 642 W.
04

Calculate the rate of moisture production

To calculate the rate of moisture production, we will use the latent heat generation rate and the heat of vaporization of water. Rate of moisture production = Total latent heat generation rate / Heat of vaporization = (642 W) / (2430 kJ/kg * 1000 W/kJ) = 0.000264 kg/s. Now, we have both the rate of total heat generation and the rate of moisture production in the room: Rate of total heat generation = 1567 W. Rate of moisture production = 0.000264 kg/s.

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