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In the heat transfer relation \(\dot{Q}=U A_{s} F \Delta T_{\mathrm{lm}}\) for a heat exchanger, what is the quantity \(F\) called? What does it represent? Can \(F\) be greater than 1?

Short Answer

Expert verified
Answer: In the heat exchanger relation, the correction factor (F) accounts for deviations from the ideal counter-current flow and adjusts the heat transfer equation accordingly. Its value is always between 0 and 1 (0<F≤1), meaning it can never be greater than 1.

Step by step solution

01

Identify the heat transfer relation

The given relation for heat transfer in a heat exchanger is \(\dot{Q}=U A_{s} F \Delta T_{\mathrm{lm}}\). In this relation, various symbols represent: - \(\dot{Q}\): rate of heat transfer - \(U\): overall heat transfer coefficient - \(A_s\): surface area for heat transfer - \(F\): correction factor - \(\Delta T_{\mathrm{lm}}\): logarithmic mean temperature difference
02

Understand the purpose of the Correction Factor (F)

The correction factor, \(F\), is used to account for any deviation from the ideal counter-current flow in a heat exchanger. In ideal conditions, the heat exchanger has pure counter-current flow, which means the hot fluid flows in the opposite direction of the cold fluid. However, in real-world heat exchangers, the flow is not always purely counter-current, which reduces the efficiency of the heat transfer process. Therefore, the correction factor is introduced to adjust the heat transfer equation for these deviations from the ideal counter-current flow.
03

Determine if F can be greater than 1

As mentioned earlier, the correction factor \(F\) accounts for deviations from the ideal counter-current flow. Since an ideal counter-current flow has the maximum possible efficiency, any deviation from it would reduce the efficiency of the heat exchanger. Therefore, the correction factor \(F\) is introduced to decrease the heat transfer rate in such cases. Hence, the value of \(F\) is always between 0 and 1, i.e., \(0<F\leq 1\). This means that the correction factor can never be greater than 1.

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Most popular questions from this chapter

Consider a crossflow engine oil heater that uses ethylene glycol flowing at a temperature of \(110^{\circ} \mathrm{C}\) to heat the oil initially at \(10^{\circ} \mathrm{C}\). The ethylene glycol enters a tube bank consisting of copper tubes \((k=250 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) with staggered arrangement in a \(0.5-\mathrm{m} \times 0.5-\mathrm{m}\) plenum. The outside diameter of the \(0.5\)-m-long copper tubes is \(25 \mathrm{~mm}\), and the wall thickness is \(2 \mathrm{~mm}\). The longitudinal and transverse pitch of the rod bundles is \(0.035 \mathrm{~m}\) each. The engine oil to be heated flows inside the tubes with a mass flow rate of $4.05 \mathrm{~kg} / \mathrm{s}\(. Take the heat transfer coefficient of the oil to be \)2500 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. If the minimum desired exit temperature of oil is \(70^{\circ} \mathrm{C}\) and the measured exit temperature of ethylene glycol is \(90^{\circ} \mathrm{C}\), determine (a) the mass flow rate of ethylene glycol and \((b)\) the number of tube rows. In your calculation, use the following properties for the ethylene glycol.

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Can the temperature of the cold fluid rise above the inlet temperature of the hot fluid at any location in a heat exchanger? Explain.

A double-pipe counterflow heat exchanger is used to cool a hot fluid before it flows into a pipe system. The pipe system is mainly constructed with ASTM F2389 polypropylene pipes. According to the ASME Code for Process Piping, the recommended maximum temperature for polypropylene pipes is $99^{\circ} \mathrm{C}$ (ASME B31.3-2014, Table B-1). The heat exchanger's inner tube has negligible wall thickness. The convection heat transfer coefficients inside and outside of the heat exchanger inner tube are $1500 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\( and 1000 \)\mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{K}$, respectively. The fouling factor estimated for the heat exchanger is \(0.0001 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\). The hot fluid \(\left(c_{p}=3800\right.\) \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{K})\) enters the heat exchanger at \(150^{\circ} \mathrm{C}\) with a flow rate of $0.5 \mathrm{~kg} / \mathrm{s}\(. In the cold side, cooling fluid \)\left(c_{p}=4200 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)$ enters the heat exchanger at \(10^{\circ} \mathrm{C}\) with a mass flow rate of $0.75 \mathrm{~kg} / \mathrm{s}$. Determine the heat transfer surface area that the heat exchanger needs to cool the hot fluid to \(99^{\circ} \mathrm{C}\) at the outlet so that it flows into the pipe system at a temperature not exceeding the recommended maximum temperature for polypropylene pipes.

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